Question

Copper tuming when heated with conc. \(\mathrm{H}_{2} \mathrm{SO}_{4}\) gives (a) \(\mathrm{O}_{3}\) (b) \(\mathrm{SO}_{2}\) (c) \(\mathrm{SO}_{3}\) (d) \(\bar{H}_{2} \mathrm{~S}\)

Short answer

(b) \(\mathrm{SO}_{2}\) is formed when copper reacts with conc. \(\mathrm{H}_{2} \mathrm{SO}_{4}\).

Step-by-step solution

Understand the Reactants

The problem involves copper turnings reacting with concentrated sulfuric acid, (H_2SO_4). We need to know the products of this reaction.

Apply Reaction Knowledge

When copper (Cu) reacts with concentrated sulfuric acid, a redox reaction occurs. Copper acts as a reducing agent and sulfuric acid as an oxidizing agent. The sulfur from the sulfuric acid is reduced.

Determine the Products

During the reaction, sulfuric acid (H_2SO_4) is reduced to form sulfur dioxide (SO_2), while copper is oxidized to copper sulfate (CuSO_4).The overall reaction is: \[Cu + 2H_2SO_4 ightarrow CuSO_4 + 2H_2O + SO_2\]

Verify the Correct Option

Based on the chemical reaction, the main gaseous product formed is sulfur dioxide (SO_2). Thus, option (b) (SO_2) is the correct answer.

Key concepts

Redox Reaction

When discussing the reaction between copper and concentrated sulfuric acid, it's essential to understand the concept of redox reactions. A redox reaction is a chemical process where there is a transfer of electrons between two substances. One substance is oxidized, meaning it loses electrons.
Conversely, the other is reduced, which means it gains those electrons. In our specific reaction, copper (Cu) is oxidized. It loses electrons and turns into copper ions, creating copper sulfate in the process.
Concurrently, sulfuric acid acts as the oxidizing agent. It accepts electrons, resulting in the reduction of sulfur within the acid. This dynamic between copper and sulfuric acid highlights the fundamental principles of redox reactions, where oxidation and reduction occur simultaneously.

Sulfur Dioxide Production

An interesting aspect of the copper and sulfuric acid reaction is the production of sulfur dioxide (SO_2). When sulfur within sulfuric acid (H_2SO_4) is reduced during the redox reaction, it leads to the release of sulfur dioxide gas as a product.
This step in the reaction is critical because the transformation of sulfuric acid into sulfur dioxide involves a reduction process, marking it as the major gaseous product formed.
The overall reaction can be summarized with the chemical equation:

• Copper,
• Sulfuric Acid,
• Copper Sulfate,
• Sulfur Dioxide, and
• Water.

Releasing sulfur dioxide is a clear indicator of sulfur being reduced from its higher oxidation state within sulfuric acid to a lower oxidation state as SO_2.

Copper Sulfate Formation

The formation of copper sulfate (CuSO_4) in the reaction between copper turnings and concentrated sulfuric acid is another pivotal aspect. Copper sulfate is generated when copper metal oxidizes; losing electrons this converts metallic copper into copper ions.
As sulfuric acid acts as the oxidizer, it supports the process of sulfate ion attachment to the copper ions, forming copper sulfate. This blue crystalline compound is noteworthy not only for its color but also for its role in various practical applications, such as in agriculture and industry.
The attachment of sulfate ions to the oxidized copper results in the formation of

• Copper Sulfate,
• Water,
• And sulfur dioxide as part of the entire reaction scheme,

showcasing the significance of this copper and sulfuric acid interaction.