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Why are there no \(s p^{4}\) or \(s p^{5}\) hybrid orbitals?

Short Answer

Expert verified
In summary, there are no \(sp^4\) or \(sp^5\) hybrid orbitals because an atom has only one s orbital and three p orbitals (px, py, and pz). For \(sp^4\) and \(sp^5\) hybrid orbitals to exist, there would need to be four and five p orbitals, respectively, which are not available. Instead, other types of hybridizations, such as dsp² and d²sp³, involve the combination of d orbitals with s and p orbitals to form more complex molecular geometries.

Step by step solution

01

Understand the basics of hybridization

The concept of hybridization is used to describe the combining of atomic orbitals to form new hybrid orbitals, which share the same energy and are useful for understanding the bonding of atoms in molecules. The main types of hybrid orbitals are sp, sp², sp³, dsp², and d²sp³, depending on the number of orbitals used in the hybridization process.
02

Learn about the available orbitals and electrons

An atom has different types of atomic orbitals with different energy levels. These include s, p, d, and f orbitals. Each orbital can hold a specific number of electrons: - s orbitals can hold 2 electrons - p orbitals can hold 6 electrons (2 each in px, py, and pz orbitals) - d orbitals can hold 10 electrons (2 each in 5 different d orbitals) - f orbitals can hold 14 electrons (2 each in 7 different f orbitals)
03

Evalute the feasibility of sp^4 and sp^5 hybrid orbitals

For sp^4 hybrid orbitals, one s orbital and four p orbitals would have to be combined. However, there are only three p orbitals in an atom (px, py, and pz). Therefore, sp^4 hybridization is not possible. For sp^5 hybrid orbitals, one s orbital and five p orbitals would have to be combined. Like mentioned before, there are only three p orbitals in an atom. So, sp^5 hybridization is also not possible.
04

Understand exceptions and alternatives

Although sp^4 and sp^5 hybridizations are not possible, there are other types of hybridizations that occur involving more than 3 p orbitals, such as dsp² and d²sp³. These hybridizations involve the combination of d orbitals with s and p orbitals, allowing the formation of more complex molecular geometries.

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Most popular questions from this chapter

The reaction of three molecules of fluorine gas with a Xe atom produces the substance xenon hexafluoride, \(\mathrm{XeF}_{6}\) : $$ \mathrm{Xe}(g)+3 \mathrm{~F}_{2}(g) \longrightarrow \mathrm{XeF}_{6}(s) $$ (a) Draw a Lewis structure for \(\mathrm{XeF}_{6}\). (b) If you try to use the VSEPR model to predict the molecular geometry of \(\mathrm{XeF}_{6 r}\) you run into a problem. What is it? (c) What could you do to resolve the difficulty in part (b)? (d) Suggest a hybridization scheme for the Xe atom in \(\mathrm{XeF}_{6}\). (e) The molecule \(\mathrm{IF}_{7}\) has a pentagonal- bipyramidal structure (five equatorial fluorine atoms at the vertices of a regular pentagon and two axial fluorine atoms). Based on the structure of \(\mathrm{IF}_{7}\), suggest a structure for \(\mathrm{XeF}_{6}\)

(a) Explain why the following ions have different bond angles: \(\mathrm{C} 1 \mathrm{O}_{2}^{-}\) and \(\mathrm{NO}_{2}^{-}\). Predict the bond angle in each case. (b) Explain why the \(\mathrm{XeF}_{2}\) molecule is linear and not bent.

(a) Sketch the molecular orbitals of the \(\mathrm{H}_{2}^{-}\) ion, and draw its energy-level diagram. (b) Write the electron configuration of the ion in terms of its MOs. (c) Calculate the bond order in \(\mathrm{H}_{2}^{-}\) (d) Suppose that the ion is excited by light, so that an electron moves from a lower-energy to a higher-energy molecular orbital. Would you expect the excited-state \(\mathrm{H}_{2}^{-}\) ion to be stable? Explain.

What is the hybridization of the central atom in (a) \(\mathrm{SiCl}_{4}\) (b) \(\mathrm{HCN},(\mathrm{c}) \mathrm{SO}_{3}\), (d) \(\mathrm{ICl}_{2}^{-}\), (e) \(\mathrm{BrF}_{4}\) ?

(a) Draw Lewis structures for ethane \(\left(\mathrm{C}_{2} \mathrm{H}_{6}\right)\), ethylene \(\left(\mathrm{C}_{2} \mathrm{H}_{4}\right)\), and acetylene \(\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)\). (b) What is the hybridization of the carbon atoms in each molecule? (c) Predict which molecules, if any, are planar. (d) How many \(\sigma\) and \(\pi\) bonds are there in each molecule? (e) Suppose that silicon could form molecules that are precisely the analogs of ethane, ethylene, and acetylene. How would you describe the bonding about \(S i\) in terms of hydrid orbitals? Does it make a difference that Si lies in the row below \(\mathrm{C}\) in the periodic table? Explain.

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