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(a) How does a polar molecule differ from a nonpolar one? (b) Atoms X and Y have different electronegativities. Will the diatomic molecule \(X-Y\) necessarily be polar? Explain. (c) What factors affect the size of the dipole moment of a diatomic molecule?

Short Answer

Expert verified
A polar molecule has a net dipole moment due to the presence of polar bonds with a difference in electronegativity, while a nonpolar molecule does not have a net dipole moment. The diatomic molecule \(X-Y\) with different electronegativities will necessarily be polar, as it will have an uneven electron distribution and a net dipole moment. Factors affecting the dipole moment of a diatomic molecule include the charge difference (electronegativity) and bond length; dipole moment can be calculated using the formula: \[\text{Dipole moment} = (\text{Charge difference}) \times (\text{Bond length})\]

Step by step solution

01

Definition of Polar and Nonpolar Molecules

A polar molecule is a molecule that has a net dipole moment due to the presence of polar bonds in the molecule. These molecules have a difference in electronegativity between the atoms that results in an uneven distribution of electrons, creating a positive and negative end (or pole) within the molecule. Nonpolar molecules, on the other hand, have an even distribution of electrons within the molecule and do not have a net dipole moment.
02

Determine if the \(X-Y\) Molecule is Polar

If atoms X and Y have different electronegativities, it means that there will be an uneven distribution of electrons between the two atoms in the \(X-Y\) diatomic molecule. This will create a polar bond, and since the molecule is diatomic, there will be a net dipole moment. Therefore, the \(X-Y\) diatomic molecule will necessarily be polar.
03

Factors Affecting the Dipole Moment of a Diatomic Molecule

The dipole moment of a diatomic molecule depends on two factors: the charge difference (or the difference in electronegativity) between the two atoms and the bond length (or distance) between the two atoms. The dipole moment can be calculated using the formula: \[ \text{Dipole moment} = (\text{Charge difference}) \times (\text{Bond length}) \] - A larger difference in electronegativity between the two atoms in a diatomic molecule will result in a larger dipole moment, as the electrons will be more unevenly distributed and create a stronger charge difference. - A larger bond length between the two atoms in a diatomic molecule will also result in a larger dipole moment. If the bond length increases, it means that the charge difference is spread over a larger distance, which increases the dipole moment.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electronegativity Difference
Electronegativity is a measure of how strongly an atom can attract electrons in a chemical bond. When two atoms form a bond, the difference in their electronegativities determines how the electrons are distributed.
  • If the electronegativity difference is large, one atom will attract electrons more strongly, leading to an uneven distribution. This results in a polar bond with distinct positive and negative poles.
  • If the electronegativity difference is small or nonexistent, electrons are shared more equally, resulting in a nonpolar bond.
Understanding electronegativity is crucial when determining whether a molecule is polar or nonpolar. In diatomic molecules like \(X-Y\), differing electronegativities between X and Y will create a polar molecule because of the resulting uneven electron distribution.
Dipole Moment
The dipole moment is a vector quantity that measures the separation of charge within a molecule. It indicates how polar a molecule is. In simple terms, the dipole moment can be thought of as a vector pointing from the positive to the negative charge center. Several factors influence the dipole moment:
  • Electronegativity Difference: As the difference in electronegativity between two bonded atoms increases, so does the dipole moment. This is because the charge separation becomes more pronounced.
  • Bond Length: The greater the distance between two atoms, the larger the dipole moment. Since the charge is spread over a longer distance, the dipole moment increases. The dipole moment can be calculated using the formula: \[ \text{Dipole moment} = (\text{Charge difference}) \times (\text{Bond length}) \]
A molecule with a significant dipole moment is said to be polar, with examples of such molecules including water \((H_2O)\), which has a strong dipole due to its angular shape and electronegativity differences.
Diatomic Molecules
Diatomic molecules consist of two atoms, which may either be the same or different elements. These molecules are a great way to explore fundamental concepts like bond polarity and dipole moments because they are simple and small.
  • Homonuclear Diatomic Molecules: When both atoms are the same (e.g., \(N_2\), \(O_2\)), they share electrons equally, resulting in nonpolar molecules.
  • Heteronuclear Diatomic Molecules: When the atoms are different (e.g., \(HCl\), \(CO\)), their differing electronegativities can result in polar bonds and thus polar molecules with dipole moments.
The simplicity of diatomic molecules makes them ideal for studying the basic principles of molecular polarity, as the absence of complex geometry helps focus solely on electronegativity and its effects on the bond and molecule as a whole.

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Most popular questions from this chapter

One scale for electronegativity is based on the concept that the electronegativity of any atom is proportional to the ionization energy of the atom minus its electron affinity: electronegativity \(=k(\mathrm{IE}-\mathrm{EA})\), where \(k\) is a proportionality constant. (a) How does this definition explain why the electronegativity of \(\mathrm{F}\) is greater than that of \(C l\) even though \(C l\) has the greater electron affinity? (b) Why are both ionization energy and electron affinity relevant to the notion of electronegativity? (c) By using data in Chapter 7 , determine the value of \(k\) that would lead to an electronegativity of \(4.0\) for \(\mathrm{F}\) under this definition. (d) Use your result from part (c) to determine the electronegativities of \(\mathrm{Cl}\) and \(\mathrm{O}\) using this scale. Do these values follow the trend shown in Figure \(8.6\) ?

The dipole moment and bond distance measured for the highly reactive gas phase OH molecule are \(1.78 \mathrm{D}\) and \(0.98 \AA\), respectively. (a) Given these values calculate the effective charges on the \(\mathrm{H}\) and \(\mathrm{O}\) atoms of the OH molecule in units of the electronic charges \(e\). (b) Is this bond more or less polar than the \(\mathrm{H}-\mathrm{Cl}\) bond in an \(\mathrm{HCl}\) molecule? (c) Is that what you would have expected based on electronegativities?

Write the Lewis symbol for atoms of each of the following elements: (a) \(\mathrm{Al}\), (b) \(\mathrm{Br}\), (c) \(\mathrm{Ar}\), (d) \(\mathrm{Sr}\).

In the vapor phase, \(\mathrm{BeCl}_{2}\) exists as a discrete molecule. (a) Draw the Lewis structure of this molecule, using only single bonds. Does this Lewis structure satisfy the octet rule? (b) What other resonance forms are possible that satisfy the octet rule? (c) Using formal charges, select the resonance form from among all the Lewis structures that is most important in describing \(\mathrm{BeCl}_{2}\) :

Under special conditions, sulfur reacts with anhydrous liquid ammonia to form a binary compound of sulfur and nitrogen. The compound is found to consist of \(69.6 \% \mathrm{~S}\) and \(30.4 \%\) N. Measurements of its molecular mass yield a value of \(184.3 \mathrm{~g} \mathrm{~mol}^{-1} .\) The compound occasionally detonates on being struck or when heated rapidly. The sulfur and nitrogen atoms of the molecule are joined in a ring. All the bonds in the ring are of the same length. (a) Calculate the empirical and molecular formulas for the substance. (b) Write Lewis structures for the molecule, based on the information you are given. (Hint: You should find a relatively small number of dominant Lewis structures.) (c) Predict the bond distances between the atoms in the ring. (Note: The \(\mathrm{S}-\mathrm{S}\) distance in the \(S_{8}\) ring is \(2.05 \AA\).) (d) The enthalpy of formation of the compound is estimated to be \(480 \mathrm{~kJ} \mathrm{~mol}^{-1}\). \(\Delta H_{f}^{\circ}\) of \(S(g)\) is \(222.8 \mathrm{~kJ} \mathrm{~mol}^{-1}\). Estimate the average bond enthalpy in the compound.

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