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Given the following bond-dissociation energies, calculate the average bond enthalpy for the \(\mathrm{Ti}-\mathrm{Cl}\) bond. $$ \begin{array}{lc} \hline & \Delta H(\mathrm{~kJ} / \mathrm{mol}) \\ \hline \mathrm{TiCl}_{4}(g) \longrightarrow \mathrm{TiCl}_{3}(g)+\mathrm{Cl}(g) & 335 \\ \mathrm{TiCl}_{3}(\mathrm{~g}) \longrightarrow \mathrm{TiCl}_{2}(g)+\mathrm{Cl}(g) & 423 \\ \mathrm{TiCl}_{2}(g) \longrightarrow \mathrm{TiCl}(g)+\mathrm{Cl}(g) & 444 \\ \mathrm{TiCl}(g) \longrightarrow \mathrm{Ti}(g)+\mathrm{Cl}(g) & 519 \\ \hline \end{array} $$

Short Answer

Expert verified
The average bond enthalpy for the \(\mathrm{Ti}-\mathrm{Cl}\) bond is \(430.25 ~\mathrm{kJ/mol}\).

Step by step solution

01

Identify the number of \(\mathrm{Ti}-\mathrm{Cl}\) bonds broken in each reaction

Observe the given reactions. In each reaction, the total number of \(\mathrm{Ti}-\mathrm{Cl}\) bonds broken are: - In reaction 1, \(\mathrm{TiCl}_{4}(g) \to \mathrm{TiCl}_{3}(g) + \mathrm{Cl}(g)\), one \(\mathrm{Ti}-\mathrm{Cl}\) bond is broken. - In reaction 2, \(\mathrm{TiCl}_{3}(g) \to \mathrm{TiCl}_{2}(g) + \mathrm{Cl}(g)\), one \(\mathrm{Ti}-\mathrm{Cl}\) bond is broken. - In reaction 3, \(\mathrm{TiCl}_{2}(g) \to \mathrm{TiCl}(g) + \mathrm{Cl}(g)\), one \(\mathrm{Ti}-\mathrm{Cl}\) bond is broken. - In reaction 4, \(\mathrm{TiCl}(g) \to \mathrm{Ti}(g) + \mathrm{Cl}(g)\), one \(\mathrm{Ti}-\mathrm{Cl}\) bond is broken.
02

Calculate total bond dissociation energy for \(\mathrm{Ti}-\mathrm{Cl}\) bonds

The bond dissociation energy in each reaction represents the energy needed to break the \(\mathrm{Ti}-\mathrm{Cl}\) bond. We need to sum the bond dissociation energy for all the reactions in order to obtain the total bond dissociation energy. Total Bond Dissociation Energy = \(335 + 423 + 444 + 519 = 1721 ~\mathrm{kJ/mol}\)
03

Calculate the average bond enthalpy for the \(\mathrm{Ti}-\mathrm{Cl}\) bond

To find the average bond enthalpy, we divide the total bond dissociation energy by the number of bonds present in the compound. In this case, \(\mathrm{TiCl}_{4}\) has 4 \(\mathrm{Ti}-\mathrm{Cl}\) bonds. Hence, the average bond enthalpy is: Average Bond Enthalpy = \(\frac{1721}{4} = 430.25 ~\mathrm{kJ/mol}\) Thus, the average bond enthalpy for the \(\mathrm{Ti}-\mathrm{Cl}\) bond is \(430.25 ~\mathrm{kJ/mol}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bond Dissociation Energy
Bond dissociation energy is crucial in understanding the energy required to break a specific bond in a molecule. In our example involving the titanium-chlorine (\(\mathrm{Ti}-\mathrm{Cl}\)) bond, we calculate the total energy needed to break all the bonds one by one.
  • It is the energy change required to dissociate one mole of bonds in a gaseous substance into gaseous atoms. In simpler terms, it measures how strong a bond is.
  • The values are generally measured in kilojoules per mole (kJ/mol).
When calculating the bond dissociation energy:
You sum up the energy values for each stage where a bond is broken. In the case of \(\mathrm{Ti}-\mathrm{Cl}\) bonds, we used the given energies: 335, 423, 444, and 519 kJ/mol for each stage. Adding these values gives a total bond dissociation energy of 1721 kJ/mol.
This total value helps in determining the average bond enthalpy, providing insights into the strength and stability of the chemical bonds present in the compound.
Chemical Reactions
Chemical reactions involve the breaking and forming of chemical bonds, which is where the concept of bond dissociation energy plays a vital role. During a chemical reaction:
  • Bonds in the reactants are broken while new bonds are formed in the products.
  • The energy required to break bonds is absorbed, whereas the energy released in forming new bonds comes off as heat.
In the example provided:
We experience the sequence of reactions where a \(\mathrm{Ti}-\mathrm{Cl}\) bond is broken at each step, converting \(\mathrm{TiCl}_4\) into elemental \(\mathrm{Ti}\) and \(\mathrm{Cl}\). These reactions showcase how energy is utilized and released, supporting the interconnectivity between bond dissociation energy and chemical processes.
Understanding these reactions offers insight into how chemical processes can be balanced energetically, allowing predictions related to reaction outcomes and feasibility.
Thermodynamics
Thermodynamics is the study of energy changes, particularly how energy flows in systems, including chemical reactions. Analyzing the bond dissociation energy in a chemical reaction provides valuable insight into its thermodynamic properties.
  • Thermodynamics helps us understand how energy is absorbed or released, determining whether a reaction is endothermic or exothermic.
  • Endothermic reactions absorb heat, as evident when breaking bonds, while exothermic reactions release heat during bond formation.
In the breakdown of \(\mathrm{TiCl}_4\),
Each of the provided reactions requires energy input for bond breaking, making these reactions endothermic. The cumulative bond dissociation energies reflect the overall energy absorption needed.
By understanding these thermodynamic principles, one can predict how temperature changes may influence the reaction's rate or even its possibility, providing a broader understanding of any chemical process in question.

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Most popular questions from this chapter

Which ionic compound is expected to form from combining the following pairs of elements: (a) barium and fluorine, (b) cesium and chlorine, (c) lithium and nitrogen, (d) aluminum and oxygen?

By referring only to the periodic table, select (a) the most electronegative element in group \(6 \mathrm{~A} ;\) (b) the least electronegative element in the group \(\mathrm{Al}, \mathrm{Si}, \mathrm{P} ;(\mathrm{c})\) the most electronegative element in the group \(\mathrm{Ga}, \mathrm{P}, \mathrm{Cl}, \mathrm{Na}\); (d) the element in the group \(\mathrm{K}, \mathrm{C}, \mathrm{Zn}, \mathrm{F}\), that is most likely to form an ionic compound with Ba.

Mothballs are composed of naphthalene, \(\mathrm{C}_{10} \mathrm{H}_{8}\), a molecule of which consists of two six-membered rings of carbon fused along an edge, as shown in this incomplete Lewis structure: (a) Write two complete Lewis structures for naphthalene. (b) The observed \(\mathrm{C}-\mathrm{C}\) bond lengths in the molecule are intermediate between \(\mathrm{C}-\mathrm{C}\) single and \(\mathrm{C}=\mathrm{C}\) double bonds. Explain. (c) Represent the resonance in naphthalene in a way analogous to that used to represent it in benzene.

For the following collection of nonmetallic elements, \(\mathrm{O}\), \(\mathrm{P}, \mathrm{Te}, \mathrm{I}, \mathrm{B},(\mathrm{a})\) which two would form the most polar single bond? (b) Which two would form the longest single bond? (c) Which two would be likely to form a compound of formula \(\mathrm{XY}_{2}\) ? (d) Which combinations of elements would likely yield a compound of empirical formula \(\mathrm{X}_{2} \mathrm{Y}_{3} ?\) In each case explain your answer.

Write the electron configuration for each of the following ions, and determine which ones possess noble-gas configurations: (a) \(\mathrm{Sr}^{2+}\), (b) \(\mathrm{Ti}^{2+}\), (c) \(\mathrm{Se}^{2-}\),(d) \(\mathrm{Ni}^{2+}\),(e) \(\mathrm{Br}^{-}\), (f) \(\mathrm{Mn}^{3+}\).

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