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For each of these Lewis symbols, indicate the group in the periodic table in which the element \(X\) belongs: (a) \(\cdot \dot{\mathrm{X}} \cdot(\mathrm{b}) \cdot \mathrm{X} \cdot(\mathrm{c}): \dot{\mathrm{X}}\)

Short Answer

Expert verified
In the given Lewis symbols, the element X belongs to the following groups in the periodic table: (a) Group 13 with 3 valence electrons, (b) Group 2 with 2 valence electrons, and (c) Group 1 with 1 valence electron.

Step by step solution

01

Identify the number of valence electrons for each Lewis symbol

Determine the number of valence electrons by counting the dots around element X in each scenario: (a) \(\cdot \dot{\mathrm{X}} \cdot\) : 3 valence electrons (b) \(\cdot \mathrm{X} \cdot\) : 2 valence electrons (c) \(\dot{\mathrm{X}}\) : 1 valence electron
02

Match each scenario to the correct group in the periodic table

Determine the group in the periodic table in which element X belongs for each scenario: (a) 3 valence electrons: Element X belongs to Group 13. (b) 2 valence electrons: Element X belongs to Group 2. (c) 1 valence electron: Element X belongs to Group 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Valence Electrons
Valence electrons are the outermost electrons of an atom. These electrons play a pivotal role in chemical bonding and reactions. When we refer to valence electrons, we are specifically talking about how these electrons participate in forming chemical bonds. Typically, the number of valence electrons is equal to an element's main group number in the periodic table, which makes understanding their behavior easier.
In Lewis symbols, valence electrons are represented as dots around an element’s symbol. By counting these dots, you can easily determine how many valence electrons are present. For instance:
  • A Lewis symbol with three dots means three valence electrons.

  • One with two dots indicates two valence electrons.

  • If there's a single dot, this represents one valence electron.
Understanding valence electrons is crucial as they dictate how an element will interact with others. They determine the element’s chemical properties and its placement in the periodic table.
Periodic Table Groups
The periodic table is organized into groups, which are the columns of the table. Elements in the same group have similar properties and valence electron configurations. This simplifies predicting an element’s chemical behavior.
The Lewis symbols with different valence electrons help identify to which group on the periodic table an element belongs:
  • If an element has 1 valence electron, like \,dot{X} \,\, \(\dot{X}\), it belongs to Group 1, the alkali metals.

  • Two valence electrons, such as in \,\, \, \cdot{X}\cdot \,\, \(\cdot \mathrm{X} \cdot\), correspond to Group 2, the alkaline earth metals.

  • Elements with three valence electrons, like \,\, \,\cdot{\dot{X}}\cdot \,\, \(\cdot \dot\mathrm{X} \cdot\), fall into Group 13, also known as the boron group.
Using periodic table groups helps in understanding how elements will bond and their general reactivity, making chemistry much simpler and systematic.
Element Classification
Element classification refers to how we organize elements based on their properties and behaviors. In chemistry, elements are grouped into metals, nonmetals, and metalloids. Additionally, we look at categories like transition metals and inner transition metals.
Knowing the number of valence electrons of an element allows us to classify them accurately. Metals generally have fewer valence electrons, often making them good conductors and very reactive, like the alkali metals in Group 1.
Nonmetals tend to have more valence electrons, causing them to react differently, often by gaining or sharing electrons. For example, the three dots in a Lewis symbol indicating three valence electrons would be characteristic of metalloids, like those in Group 13. Metalloids exhibit properties of both metals and nonmetals, making them unique and versatile.
  • Elements with fewer valence electrons often donate or lose electrons easily.

  • Those with more tend to gain or share electrons to reach a stable electron configuration.
By understanding element classification and how valence electrons contribute to this, students can predict how elements will behave in chemical reactions, aiding in both academic and practical applications of chemistry.

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Most popular questions from this chapter

(a) Write the electron configuration for the element titanium, Ti. How many valence electrons does this atom possess? (b) Hafnium, Hf, is also found in group \(4 \mathrm{~B}\). Write the electron configuration for Hf. (c) Both \(\mathrm{Ti}\) and Hf behave as though they possess the same number of valence electrons. Which of the subshells in the electron configuration of Hf behave as valence orbitals? Which behave as core orbitals?

Which of the following bonds are polar: (a) \(\mathrm{B}-\mathrm{F}\), (b) \(\mathrm{Cl}-\mathrm{Cl}\), (c) \(\mathrm{Se}-\mathrm{O}\), (d) \(\mathrm{H}-\mathrm{I}\) ? Which is the more electronegative atom in each polar bond?

Energy is required to remove two electrons from Ca to form \(\mathrm{Ca}^{2+}\) and is required to add two electrons to \(\mathrm{O}\) to form \(\mathrm{O}^{2-}\). Why, then, is \(\mathrm{CaO}\) stable relative to the free elements?

One scale for electronegativity is based on the concept that the electronegativity of any atom is proportional to the ionization energy of the atom minus its electron affinity: electronegativity \(=k(\mathrm{IE}-\mathrm{EA})\), where \(k\) is a proportionality constant. (a) How does this definition explain why the electronegativity of \(\mathrm{F}\) is greater than that of \(C l\) even though \(C l\) has the greater electron affinity? (b) Why are both ionization energy and electron affinity relevant to the notion of electronegativity? (c) By using data in Chapter 7 , determine the value of \(k\) that would lead to an electronegativity of \(4.0\) for \(\mathrm{F}\) under this definition. (d) Use your result from part (c) to determine the electronegativities of \(\mathrm{Cl}\) and \(\mathrm{O}\) using this scale. Do these values follow the trend shown in Figure \(8.6\) ?

(a) Explain the following trend in lattice energy: \(\mathrm{BeH}_{2}\), \(3205 \mathrm{~kJ} / \mathrm{mol} ; \mathrm{MgH}_{2}, 2791 \mathrm{~kJ} / \mathrm{mol} ; \mathrm{CaH}_{2}, 2410 \mathrm{~kJ} / \mathrm{mol}\) \(\mathrm{Sr} \mathrm{H}_{2}, 2250 \mathrm{~kJ} / \mathrm{mol} ; \mathrm{BaH}_{2}, 2121 \mathrm{~kJ} / \mathrm{mol}\). (b) The lattice energy of \(\mathrm{ZnH}_{2}\) is \(2870 \mathrm{~kJ} / \mathrm{mol}\). Based on the data given in part (a), the radius of the \(\mathrm{Zn}^{2+}\) ion is expected to be closest to that of which group \(2 \mathrm{~A}\) element?

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