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Use orbital diagrams to illustrate what happens when an oxygen atom gains two electrons. Why is it extremely difficult to add a third electron to the atom?

Short Answer

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When an oxygen atom gains two electrons, it transforms into an oxide ion (O^2-). Its orbital diagram changes from \(1s^2 2s^2 2p^4\) to a fully filled 2p orbital. Adding a third electron is extremely difficult due to increased electrostatic repulsion from the already present electrons and the higher energy requirement to move the electron into the 3s orbital.

Step by step solution

01

Drawing the Orbital Diagram for a Neutral Oxygen Atom

A neutral oxygen atom has 8 electrons. The atomic structure consists of orbital levels, which are labeled as 1s, 2s, and 2p. The 1s orbital can hold a maximum of 2 electrons, the 2s orbital can hold a maximum of 2 electrons, and the 2p orbital can hold a maximum of 6 electrons. To draw the orbital diagram, follow these three rules: Aufbau's principle, Hund's rule, and Pauli's exclusion principle. 1. Aufbau Principle: Fill the lower energy levels before filling the higher energy levels. 2. Hund's Rule: When filling degenerate orbitals, place one electron into each orbital before pairing the electrons. 3. Pauli's Exclusion Principle: Each orbital can only hold 2 electrons with opposite spins. Following these rules, we will create an orbital diagram for the oxygen atom: \(1s^2 2s^2 2p^4\) Here is the diagram for the neutral oxygen atom: 1s: ↑↓ 2s: ↑↓ 2p: ↑↑↑↓
02

Illustrating the Gain of Two Electrons by the Oxygen Atom

When an oxygen atom gains two electrons, it transforms into an oxide ion (O^2-). The two additional electrons will fill up the remaining spaces in the 2p orbital. Here is the orbital diagram for the oxide ion (O^2-): 1s: ↑↓ 2s: ↑↓ 2p: ↑↓↑↓↑↓
03

Explaining Why It Is Extremely Difficult to Add a Third Electron

Adding a third electron to the oxygen atom would require placing the electron into the next available orbital, which is the 3s orbital. However, this process encounters a few obstacles: 1. Electrostatic Repulsion: When trying to add a third electron, the negatively charged electron experiences repulsion from the negatively charged electrons that are already present in the 2p orbitals. This repulsion creates a barrier that prevents the third electron from being added easily. 2. Energy Requirement: As the electron moves away from the nucleus and into higher energy orbitals, it requires more energy to overcome the electrostatic repulsion. Adding a third electron would necessitate a significant amount of energy. Due to the increased electrostatic repulsion and higher energy requirement, it becomes extremely difficult to add a third electron to an oxygen atom.

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Most popular questions from this chapter

How are metallic character and first ionization energy related?

One way to measure ionization energies is photoelectron spectroscopy (PES), a technique based on the photoelectric effect. em (Section 6.2) In PES, monochromatic light is directed onto a sample, causing electrons to be emitted. The kinetic energy of the emitted electrons is measured. The difference between the energy of the photons and the kinetic energy of the electrons corresponds to the energy needed to remove the electrons (that is, the ionization energy). Suppose that a PES experiment is performed in which mercury vapor is irradiated with ultraviolet light of wavelength \(58.4 \mathrm{~nm}\). (a) What is the energy of a photon of this light, in \(\mathrm{eV}\) ? (b) Write an equation that shows the process corresponding to the first ionization energy of \(\mathrm{Hg}\). (c) The kinetic energy of the emitted electrons is measured to be \(10.75 \mathrm{eV}\). What is the first ionization energy of \(\mathrm{Hg}\), in \(\mathrm{kJ} / \mathrm{mol} ?\) (d) With reference to Figure \(7.11\), determine which of the halogen elements has a first ionization energy closest to that of mercury.

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