Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

(a) Why is calcium generally more reactive than magnesium? (b) Why is calcium generally less reactive than potassium?

Short Answer

Expert verified
a) Calcium is more reactive than magnesium due to its larger atomic radius, making it easier for valence electrons to be removed. b) Calcium is less reactive than potassium because potassium's larger atomic radius makes it easier to remove its valence electron.

Step by step solution

01

Understanding Electronic Configuration

First, look up the atomic numbers of calcium (Ca), magnesium (Mg), and potassium (K) and write down their electronic configurations. Ca (Atomic number 20): \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2\) Mg (Atomic number 12): \(1s^2 2s^2 2p^6 3s^2\) K (Atomic number 19): \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^1\)
02

Comparing Reactivity

Reactivity of elements is related to the ease with which they can lose electrons to form positive ions. For elements in the same group of the periodic table (vertical column), reactivity generally increases as you move down the group. Since Ca and Mg are both in Group 2 (alkaline earth metals) and Ca is below Mg, we can say that calcium is generally more reactive than magnesium. To explain why, let's look into the factors that affect reactivity: effective nuclear charge, electron shielding, and atomic radius.
03

Effective Nuclear Charge

Effective nuclear charge is the net positive charge experienced by the outermost electrons of an atom. It is proportional to the attraction of the nucleus to the valence electrons. As the effective nuclear charge increased, the attraction to the electrons increases and they are more tightly held, making it difficult to lose electrons and decreasing reactivity. For Ca and Mg, the valence electrons are in the same shell (n=4 for Ca, n=3 for Mg), but with more protons in the nucleus in Ca. As a result, the effective nuclear charge experienced by the valence electrons of Ca should be higher than Mg. However, electron shielding must also be taken into account.
04

Electron Shielding

Electron shielding refers to the repulsion between electrons in different energy levels. Electrons in the inner shells shield the valence electrons from the full positive charge of the nucleus, which reduces the effective nuclear charge experienced by the valence electrons. Both Ca and Mg have similar electron configurations, with the same number of electrons in their inner shells. Therefore, electron shielding remains quite similar for both elements.
05

Atomic Radius

Atomic radius is the distance between the nucleus and the outermost shell. As we move down a group in the periodic table, atomic radius generally increases because of the addition of a new energy level to the electron configuration. A larger atomic radius means that valence electrons are farther from the nucleus, making them easier to remove. In this case, the atomic radius of Ca is larger than that of Mg as it is below Mg in the same group. This leads to the valence electrons in Ca being further from the nucleus than those in Mg, making it easier for Ca to lose electrons and be more reactive.
06

Reactivity of Calcium and Potassium

Comparing Ca and K (located in Group 1), K is below Ca in the periodic table and has a larger atomic radius. This means that the valence electron in K is farther from the nucleus and more weakly attracted than the valence electrons in Ca, making K more reactive than Ca. To summarize: a) Calcium is generally more reactive than magnesium due to the larger atomic radius of calcium, which makes it easier for the valence electrons to be removed. b) Calcium is generally less reactive than potassium because potassium's atomic radius is larger than that of calcium, and its valence electron is more weakly attracted to the nucleus, making it easier to be removed.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In the chemical process called electron transfer, an electron is transferred from one atom or molecule to another (We will talk about electron transfer extensively in Chapter 20.) A simple electron transfer reaction is $$ \mathrm{A}(g)+\mathrm{A}(g) \longrightarrow \mathrm{A}^{+}(g)+\mathrm{A}^{-}(g) $$ In terms of the ionization energy and electron affinity of atom A, what is the energy change for this reaction? For a representative nonmetal such as chlorine, is this process exothermic? For a representative metal such as sodium, is this process exothermic? [Sections \(7.4\) and \(7.51\)

Write balanced equations for the following reactions: (a) potassium oxide with water, (b) diphosphorus trioxide with water, (c) chromium(III) oxide with dilute hydrochloric acid, (d) selenium dioxide with aqueous potassium hydroxide.

Consider the gas-phase transfer of an electron from a sodium atom to a chlorine atom: $$ \mathrm{Na}(\mathrm{g})+\mathrm{Cl}(\mathrm{g}) \longrightarrow \mathrm{Na}^{+}(\mathrm{g})+\mathrm{Cl}^{-}(g) $$ (a) Write this reaction as the sum of two reactions, one that relates to an ionization energy and one that relates to an electron affinity. (b) Use the result from part (a), data in this chapter, and Hess's law to calculate the enthalpy of the above reaction. Is the reaction exothermic or endothermic? (c) The reaction between sodium metal and chlorine gas is highly exothermic and produces \(\mathrm{NaCl}(\mathrm{s})\), whose structure was discussed in Section 2.7. Comment on this observation relative to the calculated enthalpy for the aforementioned gas-phase reaction.

What is the relationship between the ionization energy of an anion with a \(1-\) charge such as \(\mathrm{F}\) and the electron affinity of the neutral atom, F?

How do the sizes of atoms change as we move (a) from left to right across a row in the periodic table. (b) from top to bottom in a group in the periodic table? (c) Arrange the following atoms in order of increasing atomic radius \(\mathrm{F}, \mathrm{P}, \mathrm{S}\), As.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free