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Identify the group of elements that corresponds to each of the following generalized electron configurations: (a) [noble gas] \(n s^{2} n p^{5}\) (b) [noble gas] \(n s^{2}(n-1) d^{2}\) (c) [noble gas] \(n s^{2}(n-1) d^{10} n p^{1}\) (d) [noble gas] \(n s^{2}(n-2) f^{6}\)

Short Answer

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(a) Group 17: Halogens (b) Group 4: Transition metals (c) Group 13 (d) Lanthanides and Actinides: Inner transition metals (f-block)

Step by step solution

01

(a) Identify the group for [noble gas] \(ns^2np^5\)

The elements with this electron configuration have two electrons in an s-orbital and five electrons in a p-orbital. The total number of valence electrons is 7. When we locate an element with 7 valence electrons in the periodic table, we find that they belong to Group 17, known as the halogens.
02

(b) Identify the group for [noble gas] \(ns^2(n-1)d^2\)

The elements with this electron configuration have two electrons in an s-orbital and two electrons in a d-orbital, which is one shell lower than their current outermost shell. The total number of valence electrons is 4. When we look for elements with 4 valence electrons in the periodic table, we find that they belong to Group 4 (transition metals).
03

(c) Identify the group for [noble gas] \(ns^2(n-1)d^{10}np^1\)

The elements with this electron configuration have two electrons in an s-orbital, a full d-orbital at the previous energy level, and one electron in a p-orbital. The total number of valence electrons is 3. When we search for elements with 3 valence electrons in the periodic table, we find that they belong to Group 13.
04

(d) Identify the group for [noble gas] \(ns^2(n-2)f^6\)

The elements with this electron configuration have two electrons in an s-orbital and six electrons in an f-orbital, which is two shells lower than their current outermost shell. These elements are part of the f-block, also known as the inner transition metals. Specifically, they belong to the lanthanides and actinides, which do not have a designated group number in the periodic table.

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Most popular questions from this chapter

Under appropriate conditions, molybdenum emits Xrays that have a characteristic wavelength of \(0.711 \AA .\) These X-rays are used in diffraction experiments to determine the structures of molecules. (a) Why are X-rays, and not visible light, suitable for the determination of structure at the atomic level? (b) How fast would an electron have to be moving to have the same wavelength as these X-rays?

List the following types of electromagnetic radiation in order of increasing wavelength: (a) the gamma rays produced by a radioactive nuclide used in medical imaging; (b) radiation from an FM radio station at \(93.1 \mathrm{MHz}\) on the dial; (c) a radio signal from an AM radio station at \(680 \mathrm{kHz}\) on the dial; \((\mathrm{d})\) the yellow light from sodium vapor streetlights; (e) the red light of a light-emitting diode, such as in a calculator display.

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Molybdenum metal must absorb radiation with a minimum frequency of \(1.09 \times 10^{15} \mathrm{~s}^{-1}\) before it can eject an electron from its surface via the photoelectric effect. (a) What is the minimum energy needed to eject an electron? (b) What wavelength of radiation will provide a photon of this energy? (c) If molybdenum is irradiated with light of wavelength of \(120 \mathrm{~nm}\), what is the maximum possible kinetic energy of the emitted electrons?

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