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Identify the specific element that corresponds to each of the following electron configurations: (a) \(1 s^{2} 2 s^{2}\), (b) \(1 s^{2} 2 s^{2} 2 p^{4}\), (c) \([\mathrm{Ar}] 4 s^{1} 3 d^{5}\), (d) \([\mathrm{Kr}] 5 s^{2} 4 d^{10} 5 p^{4}\), (e) \(1 s\) ?

Short Answer

Expert verified
The elements corresponding to each electron configuration are: (a) Beryllium (Be), (b) Oxygen (O), (c) Chromium (Cr), (d) Tellurium (Te), and (e) Hydrogen (H).

Step by step solution

01

(a) 1s^2 2s^2 Electron Configuration

For this configuration, we have a total of 4 electrons (2 in the 1s subshell and 2 in the 2s subshell). The element with 4 electrons is Beryllium (Be). Its atomic number is 4.
02

(b) 1s^2 2s^2 2p^4 Electron Configuration

For this configuration, we have a total of 8 electrons (2 in the 1s, 2 in the 2s, and 4 in the 2p subshells). The element with 8 electrons is Oxygen (O). Its atomic number is 8.
03

(c) [Ar] 4s^1 3d^5 Electron Configuration

Here, we have a noble gas, Argon (Ar) in the electron configuration. Argon has 18 electrons. Additionally, there is 1 electron in the 4s subshell and 5 electrons in the 3d subshell. Therefore, in total, there are 18 + 1 + 5 = 24 electrons. The element with 24 electrons is Chromium (Cr). Its atomic number is 24.
04

(d) [Kr] 5s^2 4d^10 5p^4 Electron Configuration

Here, we have another noble gas, Krypton (Kr) in the electron configuration. Krypton has 36 electrons. Additionally, there are 2 electrons in the 5s, 10 electrons in the 4d, and 4 electrons in the 5p subshells. Therefore, in total, there are 36 + 2 + 10 + 4 = 52 electrons. The element with 52 electrons is Tellurium (Te). Its atomic number is 52.
05

(e) 1s Electron Configuration

For this configuration, we have only 1 electron in the 1s subshell. The element with 1 electron is Hydrogen (H). Its atomic number is 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Number
The atomic number of an element is fundamental to understanding its place in the periodic table and its chemical behavior. The atomic number represents the number of protons in an atom's nucleus, and by extension, it also equals the number of electrons in a neutral atom. This number is unique to each element and determines the element's identity.
For example, in the exercise given, Beryllium (Be) has an atomic number of 4, meaning it has 4 protons in its nucleus and 4 electrons orbiting the nucleus. By knowing the atomic numbers, students can easily use the electron configurations to identify elements, as seen in the textbook solutions. When an element's electron configuration is written, we begin by counting electrons up to the atomic number, which then helps in determining the type and arrangement of subshells that contain these electrons.
  • The atomic number is crucial for understanding the periodic table.
  • It determines the specific identity of an element.
  • It helps to link the electron configurations to the correct element.
Subshells in Quantum Chemistry
Subshells are divisions within the electron shells of an atom and are denoted by the letters s, p, d, and f. These subshells have different capacities for electrons: 's' can hold 2, 'p' can hold 6, 'd' can hold 10, and 'f' can hold 14 electrons.
In quantum chemistry, the energy levels and the presence of subshells are defined by quantum numbers. These help predict the electron configuration of each element. For instance, the exercise solutions demonstrate how to distribute electrons through the different subshells. In case (a), the electrons are distributed in the 1s and 2s subshells, consistent with Beryllium's configuration.
Understanding subshells is critical because they dictate an atom's shape and how it bonds with other atoms. Here are some key points:
  • Subshells are based on quantum numbers.
  • They determine the distribution of electrons in an atom.
  • They are essential for predicting chemical bonding and properties.
When dealing with subshells, it's important to fill in the lower energy subshells first, following the 'Aufbau Principle', before moving on to higher energy subshells.
Noble Gas Notation
Noble gas notation, also known as electron configuration shorthand, simplifies the representation of an atom's electron structure by using the closest previous noble gas to represent filled subshells. It is a convenient way, especially for elements with a large atomic number, to denote their electron configurations without having to write out all the preceding electron arrangements.
In the given exercise, Chromium's electron configuration starts with \[Ar\], which represents all of the electron subshells filled up to Argon, a noble gas. From this point, only the electrons in excess of Argon's configuration are listed (4s^1 3d^5).
Using noble gas notation helps to display how additional electrons fill the available subshells beyond the noble gas configuration. This method not only makes writing electron configurations faster but also eases the understanding of valence electrons, which are fundamental for forming chemical bonds.
  • Noble gas notation abbreviates electron configuration.
  • It begins with the electron configuration of the nearest noble gas.
  • It highlights the valence subshells which are key in chemical bonding.
Remember that the noble gases are located at the end of each row in the periodic table, and they include Helium (He), Neon (Ne), Argon (Ar), Krypton (Kr), Xenon (Xe), and Radon (Rn). Use the noble gas that comes before your element of interest in the periodic table when applying this notation.

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Most popular questions from this chapter

Bohr's model can be used for hydrogen-like ions-ions that have only one electron, such as \(\mathrm{He}^{+}\) and \(\mathrm{Li}^{2+}\). (a) Why is the Bohr model applicable to \(\mathrm{He}^{+}\) ions but not to neutral He atoms? (b) The ground-state energies of \(\mathrm{H}, \mathrm{He}^{+}\), and \(\mathrm{Li}^{2+}\) are tabulated as follows: By examining these numbers, propose a relationship between the ground-state energy of hydrogen-like systems and the nuclear charge, Z. (c) Use the relationship you derive in part (b) to predict the ground-state energy of the \(\mathrm{C}^{5+}\) ion.

Indicate whether energy is emitted or absorbed when the following electronic transitions occur in hydrogen: (a) from \(n=2\) to \(n=6,(b)\) from an orbit of radius \(4.76 \AA\) to one of radius \(0.529 \AA,(\mathrm{c})\) from the \(n=6\) to the \(n=9\) state.

(a) Using Equation \(6.5\), calculate the energy of an electron in the hydrogen atom when \(n=2\) and when \(n=6\). Calculate the wavelength of the radiation released when an electron moves from \(n=6\) to \(n=2\). Is this line in the visible region of the electromagnetic spectrum? If so, what color is it? (b) Calculate the energies of an electron in the hydrogen atom for \(n=1\) and for \(n=(\infty)\). How much energy does it require to move the electron out of the atom completely (from \(n=1\) to \(n=\infty\) ), according to Bohr? Put your answer in \(\mathrm{kJ} / \mathrm{mol}\). (c) The energy for the process \(\mathrm{H}+\) energy \(\rightarrow \mathrm{H}^{+}+\mathrm{e}^{-}\) is called the ionization energy of hydrogen. The experimentally determined value for the ionization energy of hydrogen is \(1310 \mathrm{~kJ} / \mathrm{mol}\). How does this compare to your calculation?

In the television series Star Trek, the transporter beam is a device used to "beam down" people from the Starship Enterprise to another location, such as the surface of a planet. The writers of the show put a "Heisenberg compensator" into the transporter beam mechanism. Explain why such a compensator would be necessary to get around Heisenberg's uncertainty principle.

The rays of the Sun that cause tanning and burning are in the ultraviolet portion of the electromagnetic spectrum. These rays are categorized by wavelength. Socalled UV-A radiation has wavelengths in the range of $320-380 \mathrm{~nm}\(, whereas UV-B radiation has wavelengths in the range of \)290-320 \mathrm{~nm}$. (a) Calculate the frequency of light that has a wavelength of \(320 \mathrm{~nm}\). (b) Calculate the energy of a mole of 320 -nm photons. (c) Which are more energetic, photons of UV-A radiation or photons of UV-B radiation? (d) The UV-B radiation from the Sun is considered a greater cause of sunburn in humans than is UV-A radiation. Is this observation consistent with your answer to part (c)?

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