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For each element, count the number of valence electrons, core electrons, and unpaired electrons in the ground state: (a) carbon, (b) phosphorus, (c) neon.

Short Answer

Expert verified
For the given elements in their ground state: (a) Carbon has 4 valence electrons, 2 core electrons, and 2 unpaired electrons; (b) Phosphorus has 5 valence electrons, 10 core electrons, and 3 unpaired electrons; (c) Neon has 8 valence electrons, 2 core electrons, and 0 unpaired electrons.

Step by step solution

01

(a) Carbon

Step 1: Determine the electron configuration Carbon has an atomic number of 6, meaning it has 6 electrons in its neutral state. The electron configuration is given by: 1s² 2s² 2p² Step 2: Identify valence and core electrons Valence electrons are the electrons in the outermost shell of an atom. In this case, carbon has 4 valence electrons (2s² and 2p²). The remaining 2 electrons (1s²) are core electrons. Step 3: Determine unpaired electrons Unpaired electrons are electrons without a full set of paired electrons. Here, carbon has 2 unpaired electrons (2p²). So, for carbon: - Valence electrons: 4 - Core electrons: 2 - Unpaired electrons: 2
02

(b) Phosphorus

Step 1: Determine the electron configuration Phosphorus has an atomic number of 15, meaning it has 15 electrons in its neutral state. The electron configuration is given by: 1s² 2s² 2p⁶ 3s² 3p³ Step 2: Identify valence and core electrons Phosphorus has 5 valence electrons (3s² and 3p³). The remaining 10 electrons (1s², 2s², and 2p⁶) are core electrons. Step 3: Determine unpaired electrons Unpaired electrons are electrons without a full set of paired electrons. Here, phosphorus has 3 unpaired electrons (3p³). So, for phosphorus: - Valence electrons: 5 - Core electrons: 10 - Unpaired electrons: 3
03

(c) Neon

Step 1: Determine the electron configuration Neon has an atomic number of 10, meaning it has 10 electrons in its neutral state. The electron configuration is given by: 1s² 2s² 2p⁶ Step 2: Identify valence and core electrons Neon has 8 valence electrons (2s² and 2p⁶). The 2 remaining electrons (1s²) are core electrons. Step 3: Determine unpaired electrons Since neon has a full set of paired electrons in the 2s and 2p orbitals, it has 0 unpaired electrons. So, for neon: - Valence electrons: 8 - Core electrons: 2 - Unpaired electrons: 0

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Most popular questions from this chapter

(a) What are the similarities and differences between the \(1 s\) and \(2 s\) orbitals of the hydrogen atom? (b) In what sense does a \(2 p\) orbital have directional character? Compare the "directional" characteristics of the \(p_{x}\) and \(d_{x^{2}-y^{2}}\) orbitals (that is, in what direction or region of space is the electron density concentrated?). (c) What can you say about the average distance from the nucleus of an electron in a \(2 s\) orbital as compared with a \(3 s\) orbital? (d) For the hydrogen atom, list the following orbitals in order of increasing energy (that is, most stable ones first): \(4 f, 6 s, 3 d, 1 s, 2 p\).

Identify the specific element that corresponds to each of the following electron configurations: (a) \(1 s^{2} 2 s^{2}\), (b) \(1 s^{2} 2 s^{2} 2 p^{4}\), (c) \([\mathrm{Ar}] 4 s^{1} 3 d^{5}\), (d) \([\mathrm{Kr}] 5 s^{2} 4 d^{10} 5 p^{4}\), (e) \(1 s\) ?

Give the values for \(n, l\), and \(m_{l}\) for \((a)\) each orbital in the \(2 p\) subshell, (b) each orbital in the \(5 d\) subshell.

(a) What is the relationship between the wavelength and the frequency of radiant energy? (b) Ozone in the upper atmosphere absorbs energy in the \(210-230-\mathrm{nm}\) range of the spectrum. In what region of the electromagnetic spectrum does this radiation occur?

Indicate whether energy is emitted or absorbed when the following electronic transitions occur in hydrogen: (a) from \(n=2\) to \(n=6,(b)\) from an orbit of radius \(4.76 \AA\) to one of radius \(0.529 \AA,(\mathrm{c})\) from the \(n=6\) to the \(n=9\) state.

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