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(a) Calculate the kinetic energy in joules of a \(45-\mathrm{g}\) golf ball moving at \(61 \mathrm{~m} / \mathrm{s}\). (b) Convert this energy to calories. (c) What happens to this energy when the ball lands in a sand trap?

Short Answer

Expert verified
The kinetic energy of a \(45g\) golf ball moving at \(61 m/s\) is \(83.8 J\). When converted to calories, this is \(20 cal\). When the golf ball lands in a sand trap, its kinetic energy is transformed into other forms of energy, such as heat and potential energy, as it displaces the sand and comes to rest.

Step by step solution

01

Calculate the kinetic energy in joules

To calculate the kinetic energy, we can use the following formula: \[K.E. = \frac{1}{2}mv^2\] where \(K.E.\) is the kinetic energy, \(m\) is the mass of the golf ball, and \(v\) is its velocity. Given that the mass of the golf ball is \(45 g\) and its velocity is \(61 m/s\), we need to convert the mass unit from grams to kilograms: \[45 g = 0.045 kg\] Now, plug the mass and velocity into the formula: \[K.E. = \frac{1}{2}(0.045 kg)(61 m/s)^2\]
02

Calculate the kinetic energy

Calculate the kinetic energy using the values given: \[K.E. = \frac{1}{2}(0.045 kg)(61 m/s)^2 = 83.8 J\] So, the kinetic energy of the golf ball is \(83.8 J\).
03

Convert the kinetic energy to calories

To convert the kinetic energy from joules to calories, we can use the following conversion factor: \[1 cal = 4.184 J\] Therefore, the energy in calories is: \[\frac{83.8 J}{4.184 J/cal} = 20 cal\] So, the kinetic energy of the golf ball is \(20 cal\).
04

Explain what happens to the energy when the ball lands in a sand trap

When the golf ball lands in a sand trap, the kinetic energy is transformed into other forms of energy. Some of the energy will be used to displace the sand as the ball impacts and sinks into it. The energy is converted to heat due to friction between the golf ball and the sand particles, as well as potential energy as the sand particles move and rearrange themselves. Ultimately, the energy is dissipated, and the ball comes to rest in the sand trap.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Conversion
Unit conversion is an essential tool in solving physics problems, especially when calculating kinetic energy. In the given exercise, the mass of the golf ball is given in grams, but the kinetic energy formula requires us to use kilograms. To convert grams to kilograms, the conversion factor is:
  • 1 kilogram = 1000 grams
Thus, to convert 45 grams to kilograms, you divide by 1000:
45 g = 45 / 1000 = 0.045 kg
This conversion ensures the correct units are used in the kinetic energy calculation. Unit conversions allow for consistency in calculations and help avoid errors when using formulas that assume specific units.
Energy Transformation
Energy transformation occurs when energy changes from one form to another. In the context of the golf ball, when it lands in a sand trap, its kinetic energy is not lost but transformed. Initially, the ball's kinetic energy is due to its motion.
Upon impact with the sand, this energy is primarily converted into:
  • Heat: Generated through friction between the ball and sand particles.
  • Sound: Produced from the impact noise.
  • Potential energy: As sand particles are displaced and rearranged.
This transformation illustrates the principle of conservation of energy, where energy is neither created nor destroyed, but it changes forms when an object interacts with its environment.
Physics Concepts
Several core physics concepts are at play in the kinetic energy calculation exercise. Understanding these can aid in comprehending the problem's mechanics:
  • Conservation of Energy: Energy remains constant in an isolated system, merely transforming between types.
  • Mass and Velocity: Both are crucial in calculating kinetic energy, emphasizing their roles in an object's motion.
  • Friction: This force opposes motion, converting kinetic energy into heat during the collision in the sand trap.
These concepts highlight the interconnectedness of various physical phenomena and reinforce basic principles studied in physics.
Kinetic Energy Formula
The kinetic energy ( K.E.) of an object can be determined using the formula:
\[K.E. = \frac{1}{2}mv^2\]Here, \(m\) represents mass, and \(v\) stands for velocity. The formula illustrates that kinetic energy is directly proportional to both mass and the square of velocity. This means:
  • Doubling the mass will double the kinetic energy.
  • Doubling the velocity quadruples the kinetic energy.
When calculating kinetic energy, it's vital to ensure correct unit usage, keeping mass in kilograms and velocity in meters per second to produce energy in joules. This formula is a cornerstone of basic physics, articulating the energy associated with motion.

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Most popular questions from this chapter

(a) Why are fats well suited for energy storage in the human body? (b) A particular chip snack food is composed of \(12 \%\) protein, \(14 \%\) fat, and the rest carbohydrate. What percentage of the calorie content of this food is fat? (c) How many grams of protein provide the same fuel value as \(25 \mathrm{~g}\) of fat?

Gasoline is composed primarily of hydrocarbons, including many with eight carbon atoms, called octanes. One of the cleanest-burning octanes is a compound called \(2,3,4\) -trimethylpentane, which has the following structural formula: The complete combustion of one mole of this compound to \(\mathrm{CO}_{2}(g)\) and \(\mathrm{H}_{2} \mathrm{O}(g)\) leads to \(\Delta H^{\circ}=-5064.9 \mathrm{~kJ} / \mathrm{mol}\). (a) Write a balanced equation for the combustion of 1 mol of \(\mathrm{C}_{8} \mathrm{H}_{18}(l) .(\mathrm{b})\) Write a balanced equation for the formation of \(\mathrm{C}_{8} \mathrm{H}_{18}(l)\) from its elements. (c) By using the information in this problem and data in Table \(5.3\), calculate \(\Delta H_{f}^{\circ}\) for \(2,3,4\) -trimethylpentane.

Consider the following hypothetical reactions: $$ \begin{array}{ll} \mathrm{A} \rightarrow \mathrm{B} & \Delta H=+30 \mathrm{~kJ} \\ \mathrm{~B} \longrightarrow \mathrm{C} & \Delta H=+60 \mathrm{~kJ} \end{array} $$ (a) Use Hess's law to calculate the enthalpy change for the reaction A - - - - C. (b) Construct an enthalpy diagram for substances \(\mathrm{A}, \mathrm{B}\), and \(\mathrm{C}\), and show how Hess's law applies.

For each of the following compounds, write a balanced thermochemical equation depicting the formation of one mole of the compound from its elements in their standard states and use Appendix \(C\) to obtain the value of \(\Delta H_{f}^{\circ}:\) (a) \(\mathrm{NH}_{3}(g)\), (b) \(\mathrm{SO}_{2}(g)\) (c) \(\mathrm{RbClO}_{3}(s)\) (d) \(\mathrm{NH}_{4} \mathrm{NO}_{3}(s)\).

(a) Write an equation that expresses the first law of thermodynamics in terms of heat and work. (b) Under what conditions will the quantities \(q\) and \(w\) be negative numbers?

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