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Write the balanced molecular and net ionic equations for each of the following neutralization reactions: (a) Aqueous acetic acid is neutralized by aqueous potassium hydroxide. (b) Solid chromium(III) hydroxide reacts with nitric acid. (c) Aqueous hypochlorous acid and aqueous calcium hydroxide react.

Short Answer

Expert verified
Reaction (a) - Molecular: \( HC2H3O2(aq) + KOH(aq) \rightarrow H2O(l) + KC2H3O2(aq) \); Net Ionic: \( H^+(aq) + OH^-(aq) \rightarrow H2O(l) \) Reaction (b) - Molecular: \( Cr(OH)3(s) + 3HNO3(aq) \rightarrow 3H2O(l) + Cr(NO3)3(aq) \); Net Ionic: \( Cr(OH)3(s) + 3H^+(aq) \rightarrow 3H2O(l) + Cr^{3+}(aq) \) Reaction (c) - Molecular: \( 2HClO(aq) + Ca(OH)2(aq) \rightarrow 2H2O(l) + Ca(ClO)2(aq) \); Net Ionic: \( 2H^+(aq) + 2OH^-(aq) \rightarrow 2H2O(l) \)

Step by step solution

01

Write the balanced molecular equation

Identify the reactants and products: acetic acid (HC2H3O2) and potassium hydroxide (KOH) are the reactants; water (H2O) and potassium acetate (KC2H3O2) are the products. The balanced molecular equation is: \( HC2H3O2(aq) + KOH(aq) \rightarrow H2O(l) + KC2H3O2(aq) \)
02

Write the total ionic equation

Break the reactants and products into their respective ions: \( H^+(aq) + C2H3O2^-(aq) + K^+(aq) + OH^-(aq) \rightarrow H2O(l) + K^+(aq) + C2H3O2^-(aq) \)
03

Write the net ionic equation

Eliminate the spectator ions (K^+ and C2H3O2^-) to obtain the net ionic equation: \( H^+(aq) + OH^-(aq) \rightarrow H2O(l) \) ##Reaction (b): Solid chromium(III) hydroxide and nitric acid##
04

Write the balanced molecular equation

Identify the reactants and products: chromium(III) hydroxide (Cr(OH)3) and nitric acid (HNO3) are the reactants; water (H2O) and chromium(III) nitrate, Cr(NO3)3, are the products. The balanced molecular equation is: \( Cr(OH)3(s) + 3HNO3(aq) \rightarrow 3H2O(l) + Cr(NO3)3(aq) \)
05

Write the total ionic equation

Break the reactants and products into their respective ions: \( Cr(OH)3(s) + 3H^+(aq) + 3NO3^-(aq) \rightarrow 3H2O(l) + Cr^{3+}(aq) + 3NO3^-(aq) \)
06

Write the net ionic equation

Eliminate the spectator ions (NO3^-) to obtain the net ionic equation: \( Cr(OH)3(s) + 3H^+(aq) \rightarrow 3H2O(l) + Cr^{3+}(aq) \) ##Reaction (c): Aqueous hypochlorous acid and aqueous calcium hydroxide##
07

Write the balanced molecular equation

Identify the reactants and products: hypochlorous acid (HClO) and calcium hydroxide (Ca(OH)2) are the reactants; water (H2O) and calcium hypochlorite (Ca(ClO)2) are the products. The balanced molecular equation is: \( 2HClO(aq) + Ca(OH)2(aq) \rightarrow 2H2O(l) + Ca(ClO)2(aq) \)
08

Write the total ionic equation

Break the reactants and products into their respective ions: \( 2H^+(aq) + 2ClO^-(aq) + Ca^{2+}(aq) + 2OH^-(aq) \rightarrow 2H2O(l) + Ca^{2+}(aq) + 2ClO^-(aq) \)
09

Write the net ionic equation

Eliminate the spectator ions (Ca^2+ and ClO^-) to obtain the net ionic equation: \( 2H^+(aq) + 2OH^-(aq) \rightarrow 2H2O(l) \)

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Most popular questions from this chapter

(a) By titration, \(15.0 \mathrm{~mL}\) of \(0.1008 \mathrm{M}\) sodium hydroxide is needed to neutralize a 0.2053-g sample of an organic acid. What is the molar mass of the acid if it is monoprotic? (b) An elemental analysis of the acid indicates that it is composed of \(5.89 \% \mathrm{H}, 70.6 \% \mathrm{C}\), and \(23.5 \% \mathrm{O}\) by mass. What is its molecular formula?

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(a) Starting with solid sucrose, \(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\), describe how you would prepare \(250 \mathrm{~mL}\) of a \(0.250 \mathrm{M}\) sucrose solution. (b) Describe how you would prepare \(350.0 \mathrm{~mL}\) of \(0.100 \mathrm{M} \mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\) starting with \(3.00 \mathrm{~L}\) of \(1.50 \mathrm{M}\) \(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\)

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