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Draw the condensed structural formulas for two different molecules with the formula \(\mathrm{C}_{3} \mathrm{H}_{4} \mathrm{O}\).

Short Answer

Expert verified
The condensed structural formulas for two different molecules with the formula \(\mathrm{C}_{3} \mathrm{H}_{4} \mathrm{O}\) are Acrolein \(\mathrm{CH}_{2} = \mathrm{C}(\mathrm{H}) - \mathrm{CHO}\) and Methyl vinyl ketone \(\mathrm{CH}_{3} - \mathrm{C}(\mathrm{H}) = \mathrm{C} - \mathrm{O}\).

Step by step solution

01

Draw the first molecule - Acrolein

For the first molecule, we will draw Acrolein (aka Propenal). Acrolein is an unsaturated aldehyde with an aldehyde functional group (-CHO) on one end and a carbon-carbon double bond in the middle. The condensed formula will look like this: \[ \mathrm{CH}_{2} = \mathrm{C}(\mathrm{H}) - \mathrm{CHO} \]
02

Draw the second molecule - Methyl vinyl ketone

For the second molecule, we will draw Methyl vinyl ketone (aka Butenone). Methyl vinyl ketone has a ketone functional group (C=O) and a carbon-carbon double bond (C=C). The condensed formula will look like this: \[ \mathrm{CH}_{3} - \mathrm{C}(\mathrm{H}) = \mathrm{C} - \mathrm{O} \] These two molecules, Acrolein and Methyl vinyl ketone, have different structural arrangements and both have the molecular formula \(\mathrm{C}_{3} \mathrm{H}_{4} \mathrm{O}\).

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