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A four-coordinate complex \(\mathrm{MA}_{2} \mathrm{~B}_{2}\) is prepared and found to have two different isomers. Is it possible to determine from this information whether the complex is square planar or tetrahedral? If so, which is it?

Short Answer

Expert verified
Based on the given information that the complex MA₂B₂ has two different isomers, we can determine that the complex is square planar. This is because square planar complexes can have two geometrical isomers (cis and trans), while tetrahedral complexes with the same ligands (A and B) do not have any isomers.

Step by step solution

01

Understanding the terms and basic concepts

A coordination complex is a molecule with a central metal atom bonded to a number of surrounding ligands (atoms, ions or molecules). In a four-coordinate complex, there are four ligands bonded to the central metal atom. In this exercise, the four-coordinate complex has the formula MA₂B₂, where M represents the central metal atom, A and B are two different types of ligands, and there are two of each type of ligand (A and B). There are two common geometries for a four-coordinate complex: square planar and tetrahedral. In a square planar complex, the four ligands are positioned at the corners of a square in the same plane, surrounding the central metal atom. In a tetrahedral complex, the four ligands are positioned at the vertices of a tetrahedron, surrounding the central metal atom.
02

Comparing isomers in square planar and tetrahedral complexes

An isomer is a molecule with the same chemical formula but different arrangement of atoms. In coordination complexes, there are two main types of isomers: geometrical isomers and optical isomers. A) Square planar complexes: In a square planar complex MA₂B₂, there are two possible geometrical isomers. One isomer has both A ligands adjacent to each other (cis), while the other isomer has the A ligands opposite each other (trans). B) Tetrahedral complexes: In a tetrahedral complex MA₂B₂, there are no geometrical isomers as all positions are equivalent. However, there may be optical isomers if all four ligands are different. In this case, MA₂B₂ has two of the same ligands (A and B), so there won't be any optical isomers.
03

Determining the geometry of the complex based on isomers

Given that the complex MA₂B₂ has two different isomers, and we know that square planar complexes can have two geometrical isomers (cis and trans), it is likely that the complex is square planar. On the other hand, this tetrahedral complex does not have any isomers, as discussed in step 2. Thus, from the information given about the isomers, we can determine that the complex is square planar.

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Most popular questions from this chapter

Consider an octahedral complex \(\mathrm{MA}_{3} \mathrm{~B}_{3}\). How many geometric isomers are expected for this compound? Will any of the isomers be optically active? If so, which ones?

(a) Draw the two linkage isomers of \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{SCN}\right]^{2+}\). (b) Draw the two geometric isomers of \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{3} \mathrm{Cl}_{3}\right]^{2+}\). (c) Two compounds with the formula \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{ClBr}\) can be prepared. Use structural formulas to show how they differ. What kind of isomerism does this illustrate?

(a) What is themeaning of the term coordination number as it applies to metal complexes? (b) Generally speaking, what structural feature characterizes substances that can serve as ligands in metal complexes? Give an example of a ligand that is neutral and one that is negatively charged. (c) Would you expect ligands that are positively charged to be common? Explain. (d) What type of chemical bonding is characteristic of coordination compounds? Illustrate with the compound \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6} \mathrm{Cl}_{3}\)

Sketch the structure of the complex in each of the following compounds: (a) \(c i s-\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}\right]\left(\mathrm{NO}_{3}\right)_{2}\) (b) \(\mathrm{Na}_{2}\left[\mathrm{Ru}\left(\mathrm{H}_{2} \mathrm{O}\right) \mathrm{Cl}_{5}\right]\) (c) \(\operatorname{trans}-\mathrm{NH}_{4}\left[\mathrm{Co}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{2}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}\right]\) (d) \(c i s-\left[\operatorname{Ru}(e n)_{2} C l_{2}\right]\)

Give the number of \(d\) electrons associated with the central metal ion in each of the following complexes: (a) \(\mathrm{K}_{3}\left[\mathrm{TiCl}_{6}\right]\), (b) \(\mathrm{Na}_{3}\left[\mathrm{Co}\left(\mathrm{NO}_{2}\right)_{6}\right]\), (c) \(\left[\operatorname{Ru}(\mathrm{en})_{3}\right] \mathrm{Br}_{3}\), (d) \([\mathrm{Mo}(\mathrm{EDTA})] \mathrm{ClO}_{4},(\mathrm{e}) \mathrm{K}_{3}\left[\mathrm{ReCl}_{6}\right]\).

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