Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Introduction of carbon into a metallic lattice generally results in a harder, less ductile substance with lower electrical and thermal conductivities. Explain why this might be so.

Short Answer

Expert verified
The introduction of carbon into a metallic lattice causes a distortion in the lattice structure due to the smaller carbon atoms occupying interstitial positions. This distortion leads to stronger atomic bonds, increasing hardness and decreasing ductility. Furthermore, the distorted lattice impedes electron mobility, resulting in lower electrical and thermal conductivities.

Step by step solution

01

Basic structure of a metallic lattice

In a metallic lattice, metal atoms are arranged in a regular repeating pattern. The electrons in the outer shells of these metal atoms are free to move, forming a 'sea of electrons.' This electron sea is responsible for the characteristic properties of metals like good electrical and thermal conductivity and ductility.
02

Effect of carbon on the metallic lattice structure

When carbon is introduced into the metallic lattice, it usually occupies interstitial positions between the metal atoms. Carbon atoms are smaller than the metal atoms, causing a distortion in the lattice structure. This distortion results in stronger atomic bonds, making the lattice harder and less ductile.
03

Effect on hardness and ductility

As the carbon atoms occupy interstitial positions and distort the lattice structure, the metal atoms are forced together, causing stronger atomic bonds. This increased bond strength makes it more difficult for the atoms to slide over one another, leading to increased hardness and decreased ductility of the metallic substance.
04

Effect on electrical conductivity

The presence of carbon atoms in the lattice structure also affects the electrical conductivity. Since the electrons in the outer shells of metal atoms form a 'sea of electrons,' their mobility is crucial for good electrical conductivity. The distortion in the lattice structure caused by the carbon atoms results in a decrease in electron mobility. With fewer free-moving electrons, the electrical conductivity of the metallic substance is reduced.
05

Effect on thermal conductivity

Similarly, the presence of carbon atoms in the lattice structure affects the thermal conductivity of the metallic substance. The distortion in the lattice structure impedes the movement of heat-carrying electrons, restricting the flow of heat throughout the material. This results in a lower thermal conductivity of the metallic substance. In conclusion, the introduction of carbon into a metallic lattice results in a harder, less ductile substance with lower electrical and thermal conductivities due to the distortion in lattice structure, the increased atomic bond strength, and the decrease in electron mobility.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The two most important iron oxide minerals are magnetite, \(\mathrm{Fe}_{3} \mathrm{O}_{4}\), and hematite, \(\mathrm{Fe}_{2} \mathrm{O}_{3}\). One is a ferrimagnetic material, while the other is an antiferromagnetic material. (a) Based on the oxidation states of iron, which one is more likely to be ferrimagnetic? (b) Would it be possible to use magnetic fields to separate these minerals?

Write balanced chemical equations for each of the following verbal descriptions: (a) Vanadium oxytrichloride \(\left(\mathrm{VOCl}_{3}\right)\) is formed by the reaction of vanadium(III) chloride with oxygen. (b) Niobium(V) oxide is reduced to the metal with hydrogen gas. (c) Iron(III) ion in aqueous solution is reduced to iron(II) ion in the presence of zinc dust. (d) Niobium(V) chloride reacts with water to yield crystals of niobic acid \(\left(\mathrm{HNbO}_{3}\right)\).

What is the major reducing agent in the reduction of iron ore in a blast furnace? Write a balanced chemical equation for the reduction process.

The element tin is generally recovered from deposits of the ore cassiterite \(\left(\mathrm{SnO}_{2}\right)\). The oxide is reduced with carbon, and the crude metal is purified by electrolysis. Write balanced chemical equations for the reduction process and for the electrode reactions in the electrolysis. (Assume that an acidic solution of \(\mathrm{SnSO}_{4}\) is employed as an electrolyte in the electrolysis.)

The element vanadium exhibits multiple oxidation states in its compounds, including \(+2\). The compound \(\mathrm{VCl}_{2}\) is known, whereas \(\mathrm{ScCl}_{2}\) is unknown. Use electron configurations and effective nuclear charges to account for this difference in behavior.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free