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A particular reaction is spontaneous at \(450 \mathrm{~K}\). The enthalpy change for the reaction is \(+34.5 \mathrm{~kJ} .\) What can you conclude about the sign and magnitude of \(\Delta S\) for the reaction?

Short Answer

Expert verified
The entropy change (ΔS) for the reaction is positive and has a magnitude of 0.07667 kJ/K. This indicates an increase in the reaction's entropy, which is consistent with a spontaneous reaction at 450 K.

Step by step solution

01

Recall the Gibbs free energy equation

The Gibbs free energy (ΔG) equation is given by: \(ΔG = ΔH - TΔS\) A reaction is spontaneous if ΔG is negative. In this case, we know that the reaction is spontaneous at 450 K, and we are given the enthalpy change (ΔH) as +34.5 kJ.
02

Calculate ΔG from the given information

Since the reaction is spontaneous at 450 K, ΔG must be negative. We can rewrite the Gibbs free energy equation to find the entropy change (ΔS) in terms of ΔH and temperature (T): \(ΔS = \frac{ΔH - ΔG}{T}\) We'll now plug in the values we know. We'll assume ΔG to be a small negative number (e.g., -0.001 kJ) to ensure the reaction is spontaneous.
03

Plug in the known values and solve for ΔS

Using the given values and our assumption from step 2, we can solve for ΔS: \(ΔS = \frac{(+34.5\,\text{kJ}) - (-0.001\,\text{kJ})}{450\,\mathrm{K}}\) \(ΔS = \frac{34.501\,\text{kJ}}{450\,\mathrm{K}}\) \(ΔS = 0.07667\,\text{kJ/K}\)
04

Interpret the result for the sign and magnitude of ΔS

The calculated value for the entropy change (ΔS) is positive (0.07667 kJ/K). This means that the reaction's entropy is increasing, making it consistent with a spontaneous reaction at 450 K. The magnitude of ΔS is 0.07667 kJ/K, which tells us the extent of the increase in the reaction's entropy.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Entropy
Entropy, symbolized as \( \Delta S \) in chemistry, is a measure of the disorder or randomness in a system. The concept originates from the Second Law of Thermodynamics, which states that the total entropy of an isolated system can never decrease over time. This implies that natural processes tend to lead towards more disordered states. \(
\)\(
\)Entropy is crucial in predicting the behavior of a chemical reaction because it can determine the feasibility of a reaction occurring without external energy input. In simple terms, a reaction that leads to an increase in entropy (\( \Delta S > 0 \) ) is often more likely to occur spontaneously, as it aligns with the universe's tendency towards higher disorder.\(
\)\(
\)For example, when we dissolve salt in water, the salt ions spread out and move freely in the solvent, increasing the system's disorder. Therefore, the entropy increases. On the other hand, a decrease in entropy (\( \Delta S < 0 \) ) could indicate that a reaction may need outside energy to proceed, such as a decrease in gas volume or the formation of a crystal from a solution.\(
\)\(
\)It is important to understand that entropy is one of several factors that affect the spontaneity of a reaction. Changes in entropy must be considered in conjunction with other thermodynamic properties, like enthalpy, to fully predict reaction behavior.\(
\)\(
\)In the exercise provided, we conclude that the sign of \( \Delta S \) must be positive for the reaction to be spontaneous at 450 K, given the positive enthalpy change. The magnitude of \( \Delta S \) gives us an idea of how much disorder is increasing because of the reaction.
Enthalpy
Enthalpy, represented by \( \Delta H \), is a thermodynamic quantity equivalent to the total heat content of a system. It encompasses internal energy within the system plus the energy required to make room for it by displacing its environment and establishing its volume and pressure.\(
\)\(
\)In the context of chemical reactions, we often discuss changes in enthalpy, \( \Delta H \). A negative \( \Delta H \), known as exothermicity, signifies that the reaction releases heat into its surroundings, which can be felt as warmth. Conversely, a positive \( \Delta H \), or endothermicity, indicates that the reaction absorbs heat, often leading to a cooling effect.\(
\)\(
\)The enthalpy change is key to understanding chemical reactions together with entropy. While entropy measures disorder and probability, enthalpy represents the energy changes that occur during a reaction. A reaction that is both exothermic \( \Delta H < 0 \) and increases entropy \( \Delta S > 0 \) is typically spontaneous, as it meets both criteria favorably.\(
\)\(
\)In our exercise scenario, the positive \( \Delta H \) value implies we have an endothermic reaction. We use the knowledge of enthalpy change in conjunction with the Gibbs free energy concept to analyze the reaction's spontaneity. For the reaction to be spontaneous at a particular temperature, the relative magnitudes of enthalpy and entropy changes play a pivotal role.
Spontaneous Reaction
A spontaneous reaction is defined as a process that can proceed on its own, without needing to be driven by an external energy source. However, 'spontaneous' does not necessarily mean that the reaction occurs quickly—it could still be a slow process. Spontaneity depends on the thermodynamic properties of the reacting system, mainly the changes in enthalpy and entropy and the temperature at which the reaction occurs.\(
\)\(
\)The Gibbs free energy \( \Delta G \) serves as the criterion for spontaneity in a reaction. If \( \Delta G \) is negative, the process is spontaneous; if it's positive, the process is non-spontaneous and requires external energy to occur. The Gibbs free energy equation, \( \Delta G = \Delta H - T\Delta S \), beautifully integrates both enthalpy and entropy, describing the balance between the energy exchanged and the distribution of energy into disorder within a system.\(
\)\(
\)The exercise presented offers us a scenario where a reaction is spontaneously occurring at a specific temperature of 450 K with a known positive enthalpy change. To maintain spontaneity (\( \Delta G < 0 \) ), the entropy change \( \Delta S \) must compensate for the positive enthalpy value. Thus, we can conclude that the entropy change needs to be positive—in other words, the process must lead to an increase in disorder within the system. This resulting positive entropy change helps to drive the reaction forward spontaneously, even though the reaction itself is endothermic.\(
\)\(
\)Understanding these fundamental thermodynamic conditions for a reaction's spontaneity helps students grasp why a reaction proceeds the way it does and why external conditions such as temperature can dramatically affect the outcome.

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Most popular questions from this chapter

Consider the vaporization of liquid water to steam at a pressure of 1 atm. (a) Is this process endothermic or exothermic? (b) In what temperature range is it a spontaneous process? (c) In what temperature range is it a nonspontaneous process? (d) At what temperature are the two phases in equilibrium?

Indicate whether each of the following statements is true or false. If it is false, correct it. (a) The feasibility of manufacturing \(\mathrm{NH}_{3}\) from \(\mathrm{N}_{2}\) and \(\mathrm{H}_{2}\) depends entirely on the value of \(\Delta H\) for the process \(\mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{NH}_{3}(g)\) (b) The reaction of \(\mathrm{Na}(\mathrm{s})\) with \(\mathrm{Cl}_{2}(\mathrm{~g})\) to form \(\mathrm{NaCl}(\mathrm{s})\) is a spontaneous process. (c) A spontaneous process can in principle be conducted reversibly. (d) Spontaneous processes in general require that work be done to force them to proceed. (e) Spontaneous processes are those that are exothermic and that lead to a higher degree of order in the system.

A system goes from state 1 to state 2 and back to state 1 . (a) What is the relationship between the value of \(\Delta E\) for going from state 1 to state 2 to that for going from state 2 back to state 1 ? (b) Without further information, can you conclude anything about the amount of heat transferred to the system as it goes from state 1 to state 2 as compared to that upon going from state 2 back to state \(1 ?\) (c) Suppose the changes in state are reversible processes. Can you conclude any thing about the work done by the system upon going from state 1 to state 2 as compared to that upon going from state 2 back to state \(1 ?\)

(a) Express the second law of thermodynamics as a mathematical equation. (b) In a particular spontaneous process the entropy of the system decreases. What can you conclude about the sign and magnitude of \(\Delta S_{\text {surr }}\) ? (c) During a certain reversible process, the surroundings undergo an entropy change, \(\Delta S_{\text {surr }}=-78 \mathrm{~J} / \mathrm{K} .\) What is the entropy change of the system for this process?

(a) For a process that occurs at constant temperature, express the change in Gibbs free energy in terms of changes in the enthalpy and entropy of the system. (b) For a certain process that occurs at constant \(T\) and \(P\), the value of \(\Delta G\) is positive. What can you conclude? (c) What is the relationship between \(\Delta G\) for a process and the rate at which it occurs?

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