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In each of the following pairs, which compound would you expect to have the higher standard molar entropy: (a) \(\mathrm{C}_{2} \mathrm{H}_{2}(g)\) or \(\mathrm{C}_{2} \mathrm{H}_{6}(\mathrm{~g})\); (b) \(\mathrm{CO}_{2}(g)\) or \(\mathrm{CO}(g) ?\) Explain.

Short Answer

Expert verified
We would expect C2H6(g) to have a higher standard molar entropy than C2H2(g) due to its higher number of atoms and molecular complexity. Similarly, we would expect CO2(g) to have a higher standard molar entropy than CO(g) for the same reasons.

Step by step solution

01

(a) Comparing standard molar entropy of C2H2(g) and C2H6(g)

First, we need to analyse their molecular structure. C2H2, or ethyne, is a simple hydrocarbon with two carbon atoms triple-bonded together and one hydrogen atom bonded to each carbon atom. In contrast, C2H6, or ethane, is a more complex hydrocarbon in which two carbon atoms are bonded together and each carbon atom is bonded to three hydrogen atoms. Since C2H6 has more atoms and is more complex, its molecules can arrange themselves in more ways, leading to a higher degree of disorder. Therefore, we would expect C2H6(g) to have a higher standard molar entropy than C2H2(g).
02

(b) Comparing standard molar entropy of CO2(g) and CO(g)

Now, let's analyse the molecular structure of these two compounds. CO2, or carbon dioxide, is a linear molecule with a carbon atom double-bonded to two oxygen atoms, one on each side. On the other hand, CO, or carbon monoxide, is also a linear molecule but with a carbon atom triple-bonded to only one oxygen atom. Since CO2 has more atoms and is slightly more complex than CO, we would expect CO2(g) to have a higher standard molar entropy than CO(g).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Entropy and Molecular Complexity
Entropy is a fundamental concept in thermodynamics, relating to the measure of disorder or randomness in a system. The more ways in which the particles of a substance can be arranged without changing the overall state, the higher the entropy. When it comes to molecular complexity, this concept becomes particularly interesting. Complex molecules like those with multiple atoms and varied configurations can have more microstates - that is, different ways the molecules can be arranged. This multiplicity leads to increased entropy.

For instance, consider a complex hydrocarbon versus a simpler one; the complex one will typically have a greater number of molecular configurations and thus, a higher standard molar entropy. This relationship is critical when comparing the entropy values of substances, as it underpins the reason why molecules with a larger number of atoms and potential interactions generally have higher entropy values.
Comparison of Molar Entropy
When tasked with comparing the standard molar entropy between different substances, it's vital to consider both the number of particles and their structural complexity. Standard molar entropy is an intrinsic property of a substance that indicates how much energy per mole is dispersed at a standard temperature. The more complex the molecule, the greater the number of possible states it can have, which correlates with higher entropy.

Looking at hydrocarbons with equal numbers of carbon atoms, the one with greater molecular complexity, meaning more bonds or more varied types of bonds, will typically exhibit a higher standard molar entropy. Similarly, for molecules with the same number of atoms, variations in bonding and structure can lead to different entropies. This is why substances with larger or more complex molecular structures often have higher standard molar entropies than their simpler counterparts.
Molecular Structure and Entropy
Molecular structure has a profound effect on a substance's entropy. The geometry and bonding patterns of a molecule dictate the number of ways the molecule can exist in different energy states or spatial orientations. Linear molecules, for example, have fewer possible orientations than non-linear ones, and this constrains their possible microstates.

A molecule with double or triple bonds may have a different range of motion and interaction potential compared to one with only single bonds, impacting the entropy. Additionally, symmetry within a molecule can decrease the number of distinguishable microstates, thus affecting its entropy. As we delve into molecules of increasing size and complexity, the entropy considerations become more intricate. By breaking down the molecular structure, we can better understand and predict the entropy behavior of substances.

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Most popular questions from this chapter

Which of the following processes are spontaneous: (a) the melting of ice cubes at \(10^{\circ} \mathrm{C}\) and 1 atm pressure; (b) separating a mixture of \(\mathrm{N}_{2}\) and \(\mathrm{O}_{2}\) into two separate samples, one that is pure \(\mathrm{N}_{2}\) and one that is pure \(\mathrm{O}_{2}\); (c) alignment of iron filings in a magnetic field; (d) the reaction of sodium metal with chlorine gas to form sodium chloride; (e) the dissolution of \(\mathrm{HCl}(g)\) in water to form concentrated hydrochloric acid?

Ammonium nitrate dissolves spontaneously and endothermally in water at room temperature. What can you deduce about the sign of \(\Delta S\) for this solution process?

About \(86 \%\) of the world's electrical energy is produced by using steam turbines, a form of heat engine. In his analysis of an ideal heat engine, Sadi Carnot concluded that the maximum possible efficiency is defined by the total work that could be done by the engine, divided by the quantity of heat available to do the work (for example from hot steam produced by combustion of a fuel such as coal or methane). This efficiency is given by the ratio \(\left(T_{\text {high }}-T_{\text {low }}\right) / T_{\text {high }}\), where \(T_{\text {high }}\) is the temperature of the heat going into the engine and \(T_{\text {low }}\) is that of the heat leaving the engine. (a) What is the maximum possible efficiency of a heat engine operating between an input temperature of \(700 \mathrm{~K}\) and an exit temperature of \(288 \mathrm{~K} ?(\mathrm{~b})\) Why is it important that electrical power plants be located near bodies of relatively cool water? (c) Under what conditions could a heat engine operate at or near \(100 \%\) efficiency? (d) It is often said that if the energy of combustion of a fuel such as methane were captured in an electrical fuel cell instead of by burning the fuel in a heat engine, a greater fraction of the energy could be put to useful work. Make a qualitative drawing like that in Figure \(5.10\) that illustrates the fact that in principle the fuel cell route will produce more useful work than the heat engine route from combustion of methane.

A particular reaction is spontaneous at \(450 \mathrm{~K}\). The enthalpy change for the reaction is \(+34.5 \mathrm{~kJ} .\) What can you conclude about the sign and magnitude of \(\Delta S\) for the reaction?

Suppose we vaporize a mole of liquid water at \(25^{\circ} \mathrm{C}\) and another mole of water at \(100{ }^{\circ} \mathrm{C}\). (a) Assuming that the enthalpy of vaporization of water does not change much between \(25^{\circ} \mathrm{C}\) and \(100^{\circ} \mathrm{C}\), which process involves the larger change in entropy? (b) Does the entropy change in either process depend on whether we carry out the process reversibly or not? Explain.

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