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(a) Explain the difference between solubility and solubility-product constant. (b) Write the expression for the solubility-product constant for each of the following ionic compounds: \(\mathrm{MnCO}_{3}, \mathrm{Hg}(\mathrm{OH})_{2}\), and \(\mathrm{Cu}_{3}\left(\mathrm{PO}_{4}\right)_{2}\).

Short Answer

Expert verified
Solubility is the maximum amount of solute that can dissolve in a solvent, while the solubility-product constant (Ksp) is an equilibrium constant representing the extent of dissolution of a sparingly soluble ionic compound. For the given compounds: \(\mathrm{MnCO}_{3}\): \(K_{sp} = [\mathrm{Mn^{2+}}][\mathrm{CO}_3^{\mathrm{2}-}]\) \(\mathrm{Hg(OH)}_{2}\): \(K_{sp} = [\mathrm{Hg^{2+}}][\mathrm{OH}^-]^2\) \(\mathrm{Cu}_{3}(\mathrm{PO}_{4})_{2}\): \(K_{sp} = [\mathrm{Cu}^{2+}]^3[\mathrm{PO}_{4}^{\mathrm{3}-}]^2\)

Step by step solution

01

A. Explaining the difference between solubility and solubility-product constant

Solubility is the maximum amount of solute that can dissolve in a given amount of solvent at a specific temperature, expressed in units such as grams per liter (g/L) or molarity (M). It is a measure of how well a solute dissolves in a solvent and depends on factors such as temperature, pressure, and the nature of both solute and solvent. The solubility-product constant (Ksp) is an equilibrium constant that represents the extent of dissolution of a sparingly soluble ionic compound in a solution. It is defined as the product of the equilibrium concentrations of the ions in the saturated solution, each raised to the power of their coefficients in the balanced chemical equation. The Ksp value does not have a unit and depends only on temperature.
02

B. Determining the solubility-product constant expression for \(\mathrm{MnCO}_{3}\)

First, we need to write the dissolution equilibrium expression for the ionic compound. The balanced chemical equation for \(\mathrm{MnCO}_{3}\): \[\mathrm{MnCO}_{3} \rightleftharpoons \mathrm{Mn^{2+}} + \mathrm{CO}_3^{\mathrm{2}-}\] The expression for solubility-product constant (Ksp) is: \[K_{sp} = [\mathrm{Mn^{2+}}][\mathrm{CO}_3^{\mathrm{2}-}]\]
03

C. Determining the solubility-product constant expression for \(\mathrm{Hg(OH)}_{2}\)

The balanced chemical equation for \(\mathrm{Hg(OH)}_{2}\) is: \[\mathrm{Hg(OH)}_{2} \rightleftharpoons \mathrm{Hg^{2+}} + 2\mathrm{OH}^-\] The expression for solubility-product constant (Ksp) is: \[K_{sp} = [\mathrm{Hg^{2+}}][\mathrm{OH}^-]^2\]
04

D. Determining the solubility-product constant expression for \(\mathrm{Cu}_{3}(\mathrm{PO}_{4})_{2}\)

The balanced chemical equation for \(\mathrm{Cu}_{3}(\mathrm{PO}_{4})_{2}\) is: \[\mathrm{Cu}_{3}\left(\mathrm{PO}_{4}\right)_{2} \rightleftharpoons 3\mathrm{Cu}^{2+} + 2\mathrm{PO}_{4}^{\mathrm{3}-}\] The expression for solubility-product constant (Ksp) is: \[K_{sp} = [\mathrm{Cu}^{2+}]^3[\mathrm{PO}_{4}^{\mathrm{3}-}]^2\]

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Most popular questions from this chapter

Calculate the \(\mathrm{pH}\) at the equivalence point for titrating \(0.200 \mathrm{M}\) solutions of each of the following bases with \(0.200 \mathrm{M} \mathrm{HBr}\) : (a) sodium hydroxide \((\mathrm{NaOH})\), (b) hydroxylamine \(\left(\mathrm{NH}_{2} \mathrm{OH}\right)\), (c) aniline \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\right)\).

Suppose you want to do a physiological experiment that calls for a pH \(6.5\) buffer. You find that the organism with which you are working is not sensitive to the weak acid \(\mathrm{H}_{2} \mathrm{X}\left(K_{a 1}=2 \times 10^{-2} ; K_{a 2}=5.0 \times 10^{-7}\right)\) or its sodium salts. You have available a \(1.0 \mathrm{M}\) solution of this acid and a \(1.0 \mathrm{M}\) solution of \(\mathrm{NaOH}\). How much of the \(\mathrm{NaOH}\) solution should be added to \(1.0 \mathrm{~L}\) of the acid to give a buffer at \(\mathrm{pH}\) 6.50? (lgnore any volume change.)

How many milliliters of \(0.105 \mathrm{M} \mathrm{HCl}\) are needed to titrate each of the following solutions to the equivalence point: (a) \(45.0 \mathrm{~mL}\) of \(0.0950 \mathrm{M} \mathrm{NaOH}\), (b) \(22.5 \mathrm{~mL}\) of \(0.118 \mathrm{M} \mathrm{NH}_{3}\), (c) \(125.0 \mathrm{~mL}\) of a solution that contains \(1.35 \mathrm{~g}\) of \(\mathrm{NaOH}\) per liter?

(a) Consider the equilibrium \(\mathrm{B}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons\) \(\mathrm{HB}^{+}(a q)+\mathrm{OH}^{-}(a q) .\) Using Le Châtelier's principle, explain the effect of the presence of a salt of \(\mathrm{HB}^{+}\) on the ionization of B. (b) Give an example of a salt that can decrease the ionization of \(\mathrm{NH}_{3}\) in solution.

For each of the following slightly soluble salts, write the net ionic equation, if any, for reaction with acid: (a) MnS, (b) \(\mathrm{PbF}_{2}\), (c) \(\mathrm{AuCl}_{3}\) (d) \(\mathrm{Hg}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\) (e) CuBr.

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