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Lactic acid (CH \(\left._{3} \mathrm{CH}(\mathrm{OH}) \mathrm{COOH}\right)\) has one acidic hydrogen. A \(0.10 \mathrm{M}\) solution of lactic acid has a \(\mathrm{pH}\) of \(2.44\) Calculate \(K_{a}\)

Short Answer

Expert verified
The acid dissociation constant, \(K_a\), for lactic acid is approximately \(1.85 \times 10^{-4}\).

Step by step solution

01

Determine the concentration of hydrogen ions (H+)

Based on the given pH value of the solution, we can calculate the concentration of hydrogen ions (H+) present. The formula for this is: \[ \mathrm{pH} = - \log[H^+] \] We need to solve this equation for [H+].
02

Calculate the concentration of hydroxide ions (OH-)

Given the concentration of hydrogen ions, we can now calculate the concentration of the conjugate base (lactate ions, CH3CH(OH)COO-) using the formula for Ka and the information we have about the concentration of lactic acid. The equation for Ka is: \[ K_a = \frac{[\mathrm{CH3CH(OH)COO^-}][\mathrm{H^+}]}{[\mathrm{CH3CH(OH)COOH}]}\]
03

Calculate the Ka value

Now that we have the concentration of hydrogen ions and lactate ions, we can finally calculate the Ka value. Plug in the values determined in the previous steps into the formula for Ka and solve for Ka.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

pH Calculation
Understanding pH is crucial when studying acids and bases in chemistry. The pH scale measures how acidic or basic a solution is. It ranges from 0 to 14, with 7 being neutral, below 7 acidic, and above 7 basic. The pH value is a negative logarithm of the hydrogen ion concentration in a solution.

Mathematically, it is expressed as: \[ \text{pH} = - \log[H^+] \]. Say, for example, a solution has a pH of 2.44. To find the hydrogen ion concentration represented as [H+], we need to reverse the pH calculation: \[ [H^+] = 10^{-\text{pH}} = 10^{-2.44} \]. This calculation gives us insight into the actual concentration of hydrogen ions present in the solution.
Hydrogen Ion Concentration
The hydrogen ion concentration, or [H+], is a measure of the amount of hydrogen ions present in a solution. On the molecular level, these ions are responsible for the acidic nature of substances. When we talk about the strength of an acid, we're discussing its ability to donate these H+ ions to a solution.

In the context of our exercise, once the pH is known, the hydrogen ion concentration can be determined through the equation: \[ [H^+] = 10^{-\text{pH}} \]. This step is essential because the hydrogen ion concentration is pivotal for further calculations, such as determining the acid dissociation constant, Ka, which helps quantify an acid’s strength.
Lactic Acid
When we delve into the world of organic acids, lactic acid, with the chemical formula \( \text{C3H6O3} \), is a prime example. It possesses one carboxyl group (\( -COOH \)), which is capable of donating a hydrogen ion, thus making it an acid. It can be found in various biological systems and foods, such as fermented dairy products.

In biochemical scenarios, lactic acid acts as an intermediate in the lactic acid fermentation process, which is essential for energy production in cells when oxygen is scarce. For our pH calculation, understanding that lactic acid can release a hydrogen ion into solution is crucial, as this is the event that defines its acidic properties and influences the solution's pH.
Chemical Equilibrium
The concept of chemical equilibrium is foundational in understanding various chemical reactions, including acid-base reactions. At equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction, resulting in a constant ratio of product and reactant concentration over time, though both reactions are still occurring.

For acids, the acid dissociation constant, Ka, represents the equilibrium constant for the dissociation of an acid into its conjugate base and hydrogen ions. The equilibrium expression for a weak acid like lactic acid dissociating in water \( \text{HA} \rightleftharpoons \text{H+} + \text{A-} \) would be: \[ K_a = \frac{[\text{A-}][\text{H+}]}{[\text{HA}]} \]. Understanding this helps in calculating the exact strength of the acid, as knowing Ka allows chemists to predict how much acid will dissociate in a solution.

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Most popular questions from this chapter

How many milliliters of concentrated hydrochloric acid solution \((36.0 \%) \mathrm{HCl}\) by mass, density \(=1.18 \mathrm{~g} / \mathrm{mL}\) ) are required to produce \(10.0 \mathrm{~L}\) of a solution that has a pH of \(2.05 ?\)

What are the concentrations of \(\mathrm{H}^{+}, \mathrm{H}_{2} \mathrm{PO}_{4}^{-}, \mathrm{HPO}_{4}^{2-}\), and \(\mathrm{PO}_{4}{ }^{3-}\) in a \(0.0250 \mathrm{M}\) solution of \(\mathrm{H}_{3} \mathrm{PO}_{4}\) ?

Many moderately large organic molecules containing basic nitrogen atoms are not very soluble in water as neutral molecules, but they are frequently much more soluble as their acid salts. Assuming that \(\mathrm{pH}\) in the stomach is \(2.5\), indicate whether each of the following compounds would be present in the stomach as the neutral base or in the protonated form: nicotine, \(K_{b}=7 \times 10^{-7} ;\) caffeine, \(K_{b}=4 \times 10^{-14} ;\) strychnine, \(K_{b}=1 \times 10^{-6} ;\) quinine, \(K_{b}=1.1 \times 10^{-6}\)

Determine the pH of each of the following solutions \(\left(K_{a}\right.\) and \(K_{b}\) values are given in Appendix D): (a) \(0.095 M\) hypochlorous acid, (b) \(0.0085 \mathrm{M}\) phenol, (c) \(0.095 \mathrm{M}\) hydroxylamine.

Calculate the \(\mathrm{pH}\) of each of the following strong acid solutions: (a) \(8.5 \times 10^{-3} \mathrm{M} \mathrm{HBr}\), (b) \(1.52 \mathrm{~g}\) of \(\mathrm{HNO}_{3}\) in \(575 \mathrm{~mL}\) of solution, \((\mathrm{c}) 5.00 \mathrm{~mL}\) of \(0.250 \mathrm{M} \mathrm{HClO}_{4}\) diluted to \(50.0 \mathrm{~mL}\), (d) a solution formed by mixing \(10.0 \mathrm{~mL}\) of \(0.100 \mathrm{M} \mathrm{HBr}\) with \(20.0 \mathrm{~mL}\) of \(0.200 \mathrm{M} \mathrm{HCl}\)

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