Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Many moderately large organic molecules containing basic nitrogen atoms are not very soluble in water as neutral molecules, but they are frequently much more soluble as their acid salts. Assuming that \(\mathrm{pH}\) in the stomach is \(2.5\), indicate whether each of the following compounds would be present in the stomach as the neutral base or in the protonated form: nicotine, \(K_{b}=7 \times 10^{-7} ;\) caffeine, \(K_{b}=4 \times 10^{-14} ;\) strychnine, \(K_{b}=1 \times 10^{-6} ;\) quinine, \(K_{b}=1.1 \times 10^{-6}\)

Short Answer

Expert verified
In the stomach (pH 2.5), nicotine, strychnine, and quinine will be present in their protonated forms, while caffeine will be present as the neutral base.

Step by step solution

01

Calculate the \(pK_b\) for nicotine

\[\mathrm{p}K_b=-\log(7\times 10^{-7})\approx 6.15\]
02

Calculate the \(pK_a\) for nicotine

\[\mathrm{p}K_a=14-\mathrm{p}K_b=14-6.15\approx 7.85\]
03

Determine the form of nicotine

Since \(pK_a > pH\) (7.85 > 2.5), nicotine will be present in the protonated form in the stomach. ##Caffeine##
04

Calculate the \(pK_b\) for caffeine

\[\mathrm{p}K_b=-\log(4\times 10^{-14})\approx 13.40\]
05

Calculate the \(pK_a\) for caffeine

\[\mathrm{p}K_a=14-\mathrm{p}K_b=14-13.40\approx 0.60\]
06

Determine the form of caffeine

Since \(pK_a < pH\) (0.60 < 2.5), caffeine will be present as the neutral base in the stomach. ##Strychnine##
07

Calculate the \(pK_b\) for strychnine

\[\mathrm{p}K_b=-\log(1\times 10^{-6})\approx 6.00\]
08

Calculate the \(pK_a\) for strychnine

\[\mathrm{p}K_a=14-\mathrm{p}K_b=14-6.00\approx 8.00\]
09

Determine the form of strychnine

Since \(pK_a > pH\) (8.00 > 2.5), strychnine will be present in the protonated form in the stomach. ##Quinine##
10

Calculate the \(pK_b\) for quinine

\[\mathrm{p}K_b=-\log(1.1\times 10^{-6})\approx 5.96\]
11

Calculate the \(pK_a\) for quinine

\[\mathrm{p}K_a=14-\mathrm{p}K_b=14-5.96\approx 8.04\]
12

Determine the form of quinine

Since \(pK_a > pH\) (8.04 > 2.5), quinine will be present in the protonated form in the stomach. To summarize, nicotine, strychnine, and quinine will be present in their protonated forms in the stomach, while caffeine will be present as the neutral base.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

At the freezing point of water \(\left(0^{\circ} \mathrm{C}\right), K_{w}=1.2 \times 10^{-15}\). Calculate \(\left[\mathrm{H}^{+}\right]\) and \(\left[\mathrm{OH}^{-}\right]\) for a neutral solution at this temperature.

How many moles of \(\mathrm{HF}\left(K_{a}=6.8 \times 10^{-4}\right)\) must be present in \(0.200 \mathrm{~L}\) to form a solution with a \(\mathrm{pH}\) of \(3.25\) ?

Calculate [OH \(^{-}\) ] for each of the following solutions, and indicate whether the solution is acidic, basic, or neutral: (a) \(\left[\mathrm{H}^{+}\right]=0.0045 \mathrm{M}\); (b) \(\left[\mathrm{H}^{+}\right]=1.5 \times 10^{-9} \mathrm{M} ;\) (c) a solution in which \(\left[\mathrm{H}^{+}\right]\) is 10 times greater than \([\mathrm{OH}]\).

Calculate the \(\mathrm{pH}\) of a solution made by adding \(2.50 \mathrm{~g}\) of lithium oxide \(\left(\mathrm{Li}_{2} \mathrm{O}\right)\) to enough water to make \(1.500 \mathrm{~L}\) of solution.

A hypothetical acid \(\mathrm{H}_{2} \mathrm{X}\) is both a strong acid and a diprotic acid. (a) Calculate the pH of a \(0.050 \mathrm{M}\) solution of \(\mathrm{H}_{2} \mathrm{X}\), assuming that only one proton ionizes peracid molecule. (b) Calculate the \(\mathrm{pH}\) of the solution from part (a), now assuming that both protons of each acid molecule completely ionize. (c) In an experiment it is observed that the \(\mathrm{pH}\) of a \(0.050 \mathrm{M}\) solution of \(\mathrm{H}_{2} \mathrm{X}\) is \(1.27 .\) Comment on the relative acid strengths of \(\mathrm{H}_{2} \mathrm{X}\) and \(\mathrm{HX}^{-}\). (d) Would a solution of the salt \(\mathrm{NaH} \mathrm{X}\) be acidic, basic, or neutral? Explain.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free