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Arrange the following \(0.10 \mathrm{M}\) solutions in order of increasing acidity (decreasing pH): (i) \(\mathrm{NH}_{4} \mathrm{NO}_{3}\), (ii) \(\mathrm{NaNO}_{3}\), (iii) \(\mathrm{CH}_{3} \mathrm{COONH}_{4}\) (iv) \(\mathrm{NaF}\), (v) \(\mathrm{CH}_{3} \mathrm{COONa}\)

Short Answer

Expert verified
The solutions arranged in order of increasing acidity (decreasing pH) are: (iv) \(\mathrm{NaF}\), (v) \(\mathrm{CH}_{3} \mathrm{COONa}\), (ii) \(\mathrm{NaNO}_{3}\), (iii) \(\mathrm{CH}_{3} \mathrm{COONH}_{4}\), and (i) \(\mathrm{NH}_{4} \mathrm{NO}_{3}\).

Step by step solution

01

Identify Acidic, Basic or Neutral Compounds in the List

(i) \(\mathrm{NH}_{4} \mathrm{NO}_{3}\): This compound dissociates into \(\mathrm{NH}_{4}^{+}\) and \(\mathrm{NO}_{3}^{-}\) ions. \(\mathrm{NH}_{4}^{+}\) is the conjugate acid of the weak base \(\mathrm{NH}_{3}\) and will make the solution acidic. The ion \(\mathrm{NO}_{3}^{-}\) does not hydrolyze in water, so it does not contribute to the acidity or basicity of the solution. (ii) \(\mathrm{NaNO}_{3}\): This compound dissociates into \(\mathrm{Na}^{+}\) and \(\mathrm{NO}_{3}^{-}\) ions. The ions \(\mathrm{Na}^{+}\) and \(\mathrm{NO}_{3}^{-}\) do not hydrolyze in water, so they do not contribute to the acidity or basicity of the solution, making it a neutral solution. (iii) \(\mathrm{CH}_{3} \mathrm{COONH}_{4}\): This compound dissociates into \(\mathrm{NH}_{4}^{+}\) and \(\mathrm{CH}_{3}\mathrm{COO}^{-}\) ions. The ion \(\mathrm{NH}_{4}^{+}\) is the conjugate acid of the weak base \(\mathrm{NH}_{3}\) and will make the solution acidic. The ion \(\mathrm{CH}_{3}\mathrm{COO}^{-}\) is the conjugate base of the weak acid \(\mathrm{CH}_{3}\mathrm{COOH}\), but its effect on the acidity/basicity of the solution will be less than that of \(\mathrm{NH}_{4}^{+}\). (iv) \(\mathrm{NaF}\): This compound dissociates into \(\mathrm{Na}^{+}\) and \(\mathrm{F}^{-}\) ions. The ion \(\mathrm{Na}^{+}\) does not hydrolyze in water, so it does not contribute to the acidity or basicity of the solution. The ion \(\mathrm{F}^{-}\) is the conjugate base of the weak acid \(\mathrm{HF}\) and will make the solution basic. (v) \(\mathrm{CH}_{3} \mathrm{COONa}\): This compound dissociates into \(\mathrm{Na}^{+}\) and \(\mathrm{CH}_{3}\mathrm{COO}^{-}\) ions. The ion \(\mathrm{CH}_{3}\mathrm{COO}^{-}\) is the conjugate base of the weak acid \(\mathrm{CH}_{3}\mathrm{COOH}\) and will make the solution basic. The ion \(\mathrm{Na}^{+}\) does not hydrolyze in water, so it does not contribute to the acidity or basicity of the solution.
02

Arrange the Solutions in Order of Increasing Acidity

Now that we have identified the acidic, basic and neutral nature of the given solutions, we can arrange them in order of increasing acidity (decreasing pH values). Based on the analysis, we can arrange the solutions in the following order: 1. Most acidic (lowest pH): (i) \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) 2. More acidic: (iii) \(\mathrm{CH}_{3} \mathrm{COONH}_{4}\) 3. Neutral: (ii) \(\mathrm{NaNO}_{3}\) 4. More basic: (v) \(\mathrm{CH}_{3} \mathrm{COONa}\) 5. Most basic (highest pH): (iv) \(\mathrm{NaF}\) Thus, the solutions, arranged in order of increasing acidity, are: (iv) \(\mathrm{NaF}\), (v) \(\mathrm{CH}_{3} \mathrm{COONa}\), (ii) \(\mathrm{NaNO}_{3}\), (iii) \(\mathrm{CH}_{3} \mathrm{COONH}_{4}\), and (i) \(\mathrm{NH}_{4} \mathrm{NO}_{3}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acidity
Acidity refers to the presence and concentration of hydrogen ions \( \left( \ce{H^+} \right) \) in a solution. A higher concentration of hydrogen ions results in a lower pH value, indicating a more acidic solution. When a compound dissociates in water, it releases ions that might increase the concentration of \( \ce{H^+} \). For example, ammonium nitrate \( \ce{NH4NO3} \) dissociates into \( \ce{NH4+} \) and \( \ce{NO3-} \) ions. The ammonium ion \( \ce{NH4+} \) acts as a weak acid because it can donate a proton to water molecules, increasing the solution's acidity. Therefore, when ranking substances by acidity, we consider how their ion dissociation contributes to the hydrogen ion concentration.
Basicity
Basicity measures the ability of a solution to capture hydrogen ions, often described as the concentration of hydroxide ions \( \ce{OH^-} \). Basic solutions have higher pH values due to lower concentrations of \( \ce{H^+} \) ions. Compounds like sodium fluoride \( \ce{NaF} \) dissociate into sodium ions \( \ce{Na^+} \) and fluoride ions \( \ce{F^-} \). The fluoride ion can accept a hydrogen ion from water, forming the weak acid hydrofluoric acid \( \ce{HF} \), thus leaving behind excess hydroxide ions \( \ce{OH^-} \). This process makes the solution basic.To judge basicity, we examine ions that absorb \( \ce{H^+} \), impacting the available \( \ce{OH^-} \) ions in the solution.
Neutral Solutions
Neutral solutions have equal concentrations of hydrogen and hydroxide ions. This balance results in a pH of 7, indicating a neutral state. The dissociation of compounds such as sodium nitrate \( \ce{NaNO3} \) results in sodium ions \( \ce{Na^+} \) and nitrate ions \( \ce{NO3^-} \), neither of which significantly interacts with water to alter the ion balance. Thus, \( \ce{NaNO3} \) solutions remain neutral because these ions do not partake in reactions that either increase \( \ce{H^+} \) or \( \ce{OH^-} \) concentrations.When deciding if a solution is neutral, we need to check if the dissolved species interact with water to modify acidity or basicity.
Ion Dissociation
Ion dissociation involves the separation of a compound into its individual ions in solution. This process is fundamental in determining a solution's pH, as ions can affect the \( \ce{H^+} \) or \( \ce{OH^-} \) concentration. Take sodium acetate \( \ce{CH3COONa} \) for instance, it dissociates into sodium ions \( \ce{Na^+} \) and acetate ions \( \ce{CH3COO^-} \). The acetate ion reacts with water, slightly increasing the solution's pH by decreasing \( \ce{H^+} \) ions.To fully grasp how solutions behave, it's crucial to understand how different ions from a compound will interact with water. This interaction underlies whether a solution will be acidic, basic, or neutral.

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Most popular questions from this chapter

Calculate [OH \(^{-}\) ] for each of the following solutions, and indicate whether the solution is acidic, basic, or neutral: (a) \(\left[\mathrm{H}^{+}\right]=0.0045 \mathrm{M}\); (b) \(\left[\mathrm{H}^{+}\right]=1.5 \times 10^{-9} \mathrm{M} ;\) (c) a solution in which \(\left[\mathrm{H}^{+}\right]\) is 10 times greater than \([\mathrm{OH}]\).

Write the chemical equation and the \(K_{b}\) expression for the reaction of each of the following bases with water. (a) propylamine, \(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{NH}_{2}\) i (b) monohydrogen phosphate ion, \(\mathrm{HPO}_{4}{ }^{2-} ;\) (c) benzoate ion, \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CO}_{2}^{-}\)

The acid-dissociation constant for hypochlorous acid (HClO) is \(3.0 \times 10^{-8}\). Calculate the concentrations of \(\mathrm{H}_{3} \mathrm{O}^{+}, \mathrm{ClO}^{-}\), and \(\mathrm{HClO}\) at equilibrium if the initial concentration of \(\mathrm{HClO}\) is \(0.0090 \mathrm{M}\).

Explain the following observations: (a) \(\mathrm{HCl}\) is a stronger acid than \(\mathrm{H}_{2} \mathrm{~S} ;\) (b) \(\mathrm{H}_{3} \mathrm{PO}_{4}\) is a stronger acid than \(\mathrm{H}_{3} \mathrm{As} \mathrm{O}_{4}\); (c) \(\mathrm{HBrO}_{3}\) is a stronger acid than \(\mathrm{HBr} \mathrm{O}_{2}\); (d) \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\) is a stronger acid than \(\mathrm{HC}_{2} \mathrm{O}_{4}^{-} ;(\mathrm{e})\) benzoic acid \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}\right)\) is a stronger acid than phenol \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\right)\) ).

Carbon dioxide in the atmosphere dissolves in raindrops to produce carbonic acid \(\left(\mathrm{H}_{2} \mathrm{CO}_{3}\right)\), causing the \(\mathrm{pH}\) of clean, unpolluted rain to range from about \(5.2\) to \(5.6\). What are the ranges of \(\left[\mathrm{H}^{+}\right]\) and \(\left[\mathrm{OH}^{-}\right]\) in the raindrops?

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