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(a) Identify the Bronsted-Lowry acid and the BrønstedLowry base in the following reaction: (b) Identify the Lewis acid and the Lewis base in the reaction. [Sections \(16.2\) and \(16.11]\)

Short Answer

Expert verified
In the reaction NH3(aq) + H2O(l) ⇌ NH4⁺(aq) + OH⁻(aq), the Bronsted-Lowry Acid is H2O, the Bronsted-Lowry Base is NH3, the Lewis Acid is H2O, and the Lewis Base is NH3.

Step by step solution

01

Identify the Bronsted-Lowry Acid and Base

In this step, we determine which species donates a proton and which species accepts a proton. In the given reaction, NH3 accepts a proton from H2O to form NH4⁺, while H2O donates a proton to form OH⁻. Thus: - Bronsted-Lowry Acid: H2O - Bronsted-Lowry Base: NH3
02

Identify the Lewis Acid and Base

In this step, we determine which species donates an electron pair and which species accepts an electron pair. Since NH3 has a lone pair of electrons, it donates an electron pair to H2O to share a proton and form the NH4⁺ ion. So: - Lewis Base: NH3 In the case of H2O sharing a proton with NH3, it can be considered as the species accepting an electron pair. Thus: - Lewis Acid: H2O To summarize, in the reaction NH3(aq) + H2O(l) ⇌ NH4⁺(aq) + OH⁻(aq): - Bronsted-Lowry Acid: H2O - Bronsted-Lowry Base: NH3 - Lewis Acid: H2O - Lewis Base: NH3

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Brønsted-Lowry Acid-Base Theory
The Brønsted-Lowry theory is all about protons, or hydrogen ions ( H^+ ). This is a very handy way to look at reactions where proton transfer happens between molecules. In this theory, an acid is defined as a substance that donates a proton, and a base is a substance that accepts a proton. For example, in the reaction of NH_3 with H_2O , water ( H_2O ) acts as the acid. It donates a proton ( H^+ ) to ammonia ( NH_3 ), which plays the role of the base. So:
  • Brønsted-Lowry Acid: H_2O (because it donates a proton)
  • Brønsted-Lowry Base: NH_3 (because it accepts a proton)
Understanding this theory makes predicting the outcomes of reactions much simpler. Emphasizing proton movement helps clarify how substances change in these reactions.
Lewis Acid-Base Theory
In contrast to the Brønsted-Lowry theory, the Lewis acid-base theory focuses on electron pairs rather than protons. It describes acids and bases in terms of their ability to accept or donate electron pairs. Here, a Lewis acid is a species that can accept an electron pair, while a Lewis base is a species that can donate an electron pair. In the example reaction, ammonia ( NH_3 ) provides a lone pair of electrons to the water molecule. This donation of electrons allows NH_3 to connect to the H_2O molecule, forming NH_4^+ . Hence:
  • Lewis Acid: H_2O (accepts an electron pair)
  • Lewis Base: NH_3 (donates an electron pair)
This theory broadens our understanding of acid-base interactions beyond just protons by highlighting the importance of electron exchange.
Proton Transfer
Proton transfer is a crucial concept in acid-base chemistry, particularly in the Brønsted-Lowry framework. It involves the movement of a hydrogen ion ( H^+ ) from one molecule to another. This transfer of protons is what classifies substances as acids or bases in the Brønsted-Lowry theory.
In our particular reaction, proton transfer occurs when H_2O donates a proton to NH_3 , transforming into OH^- and forming NH_4^+ from NH_3 . This fundamental movement of protons is why such reactions are often called proton-exchange reactions.
  • Proton Donor (Acid): H_2O
  • Proton Acceptor (Base): NH_3
It's this transfer that enables acids and bases to neutralize one another and allows for the transformation of molecules.
Electron Pair Donation
Electron pair donation is a core concept in the Lewis theory of acids and bases. It describes how a base donates its pair of electrons to form a new bond with an acid. In our provided reaction, ammonia ( NH_3 ) acts as the Lewis base by donating an electron pair to H_2O .
The electron pair donation from NH_3 forms a bond between the nitrogen atom of ammonia and the hydrogen ion from water, resulting in the ammonium ion ( NH_4^+ ). This shows:
  • Electron Pair Donor (Base): NH_3
  • Electron Pair Acceptor (Acid): H_2O
This process is central in reactions where electron-sharing creates larger or more complex molecules. It's essential in understanding reactions beyond simple proton transfers.

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Most popular questions from this chapter

A hypothetical acid \(\mathrm{H}_{2} \mathrm{X}\) is both a strong acid and a diprotic acid. (a) Calculate the pH of a \(0.050 \mathrm{M}\) solution of \(\mathrm{H}_{2} \mathrm{X}\), assuming that only one proton ionizes peracid molecule. (b) Calculate the \(\mathrm{pH}\) of the solution from part (a), now assuming that both protons of each acid molecule completely ionize. (c) In an experiment it is observed that the \(\mathrm{pH}\) of a \(0.050 \mathrm{M}\) solution of \(\mathrm{H}_{2} \mathrm{X}\) is \(1.27 .\) Comment on the relative acid strengths of \(\mathrm{H}_{2} \mathrm{X}\) and \(\mathrm{HX}^{-}\). (d) Would a solution of the salt \(\mathrm{NaH} \mathrm{X}\) be acidic, basic, or neutral? Explain.

The iodate ion is reduced by sulfite according to the following reaction: $$ \mathrm{IO}_{3}^{-}(a q)+3 \mathrm{SO}_{3}{ }^{2-}(a q) \longrightarrow \mathrm{I}^{-}(a q)+3 \mathrm{SO}_{4}{ }^{2-}(a q) $$ The rate of this reaction is found to be first order in \(\mathrm{IO}_{3}\). first order in \(\mathrm{SO}_{3}{ }^{2-}\), and first order in \(\mathrm{H}^{+}\). (a) Write the rate law for the reaction. (b) By what factor will the rate of the reaction change if the \(\mathrm{pH}\) is lowered from \(5.00\) to 3.50? Does the reaction proceed faster or slower at the lower pH? (c) By using the concepts discussed in Section 14.6, explain how the reaction can be pH- dependent

By what factor does \(\left[\mathrm{H}^{+}\right]\) change for a \(\mathrm{pH}\) change of (a) \(2.00\) units, (b) \(0.50\) units?

What is the boiling point of a \(0.10 \mathrm{M}\) solution of \(\mathrm{NaHSO}_{4}\) if the solution has a density of \(1.002 \mathrm{~g} / \mathrm{mL} ?\)

Many moderately large organic molecules containing basic nitrogen atoms are not very soluble in water as neutral molecules, but they are frequently much more soluble as their acid salts. Assuming that \(\mathrm{pH}\) in the stomach is \(2.5\), indicate whether each of the following compounds would be present in the stomach as the neutral base or in the protonated form: nicotine, \(K_{b}=7 \times 10^{-7} ;\) caffeine, \(K_{b}=4 \times 10^{-14} ;\) strychnine, \(K_{b}=1 \times 10^{-6} ;\) quinine, \(K_{b}=1.1 \times 10^{-6}\)

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