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When the following reactions come to equilibrium, does the equilibrium mixture contain mostly reactants or mostly products? (a) N2(g)+O2(g)2NO(g);Kc=1.5×1010 (b) 2SO2(g)+O2(g)2SO3(g);Kp=2.5×109

Short Answer

Expert verified
For the given reactions: (a) N2(g)+O2(g)2NO(g) with Kc=1.5×1010 - The equilibrium mixture will contain mostly reactants, due to the small equilibrium constant. (b) 2SO2(g)+O2(g)2SO3(g) with Kp=2.5×109 - The equilibrium mixture will contain mostly products, due to the large equilibrium constant.

Step by step solution

01

The equilibrium constant (Kc or Kp) is the ratio of the concentrations or partial pressures of the products to the reactants at equilibrium. A larger value of the equilibrium constant indicates that the equilibrium is more towards the products, while a smaller value indicates that the equilibrium is more towards the reactants. #Step 2: Analyze Reaction (a)#

For reaction (a) N2(g)+O2(g)2NO(g), the equilibrium constant Kc is given as 1.5×1010. Since Kc is very small, this means that the equilibrium lies more towards the reactants. Therefore, the equilibrium mixture will contain mostly reactants for Reaction (a). #Step 3: Analyze Reaction (b)#
02

For reaction (b) 2SO2(g)+O2(g)2SO3(g), the equilibrium constant Kp is given as 2.5×109. Since Kp is very large, this means that the equilibrium lies more towards the products. Therefore, the equilibrium mixture will contain mostly products for Reaction (b). #Step 4: Summary of results#

Based on the given equilibrium constants, the equilibrium mixtures for the given reactions are as follows: (a) N2(g) + O2(g) ↔ 2 NO(g): Mostly reactants, due to a small equilibrium constant. (b) 2 SO2(g) + O2(g) ↔ 2 SO3(g): Mostly products, due to a large equilibrium constant.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Reaction Equilibrium
In any chemical reaction, reaching reaction equilibrium means the rate of the forward reaction equals the rate of the reverse reaction. At this stage, the concentration of reactants and products remains constant. This doesn't necessarily mean they are equal in concentration. It simply means they no longer change with time. Equilibrium does not imply that a reaction has halted; instead, both forward and reverse reactions continue but at the same rate.
  • When the forward reaction produces products at the same rate they revert to reactants, equilibrium is achieved.
  • Equilibrium is dynamic, meaning changes at the molecular level still occur even though macroscopic changes cease.
By examining equilibrium constants, students can deduce which direction a reaction favors at equilibrium.
The Role of Chemical Reactions
Chemical reactions involve the transformation of substances through the breaking and forming of bonds, resulting in different substances called products. In reversible reactions, this process can occur in both directions, leading to the establishment of an equilibrium position.
The initial concentration of the reactants, temperature, and the specific properties of the substances influence how the reaction progresses.
  • In reversible reactions, the same substances can convert back to initial reactants from products.
  • The speed of these changes depends on factors like temperature and pressure.
Chemical reactions form the basis for calculating the equilibrium constant, providing insights into the reaction's balance between products and reactants.
Characteristics of an Equilibrium Mixture
An equilibrium mixture is a combination of reactants and products in a chemical reaction that occurs at equilibrium. This mixture reflects the concentrations present when a reversible reaction reaches equilibrium. A major tool for understanding this is the equilibrium constant (K), which gives insight into the ratio of products to reactants.
  • If the equilibrium constant is large, the equilibrium mixture contains mostly products, like in reaction (b) with a Kp of 2.5×109.
  • A small equilibrium constant indicates a mixture with mostly reactants, as seen in reaction (a) with a Kc of 1.5×1010.
These constants help determine the "position" of the equilibrium, informing whether a mixture favors the formation of products or the retention of reactants at equilibrium.

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Most popular questions from this chapter

Consider the following equilibrium, for which ΔH<0 2SO2(g)+O2(g)2SO3(g) How will each of the following changes affect an equilibrium mixture of the three gases? (a) O2(g) is added to the system; (b) the reaction mixture is heated; (c) the volume of the reaction vessel is doubled; (d) a catalyst is. added to the mixture; (e) the total pressure of the system is increased by adding a noble gas; (f) SO3(g) is removed from the system.

For a certain gas-phase reaction, the fraction of products in an equilibrium mixture is increased by increasing the temperature and increasing the volume of the reaction vessel. (a) What can you conclude about the reaction from the influence of temperature on the equilibrium? (b) What can you conclude from the influence of increasing the volume?

Write the expression for Kc for the following reactions. In each case indicate whether the reaction is homogeneous or heterogeneous. (a) 3NO(g)N2O(g)+NO2(g) (b) CH4(g)+2H2 S(g)CS2(g)+4H2(g) (c) Ni(CO)4(g)Ni(s)+4CO(g) (d) HF(aq)H+(aq)+F(aq) (e) 2Ag(s)+Zn2+(aq)2Ag+(aq)+Zn(s)

Consider the hypothetical reaction A(g)+2 B( g)= 2C(g), for which Kc=0.25 at some temperature. A 1.00-L reaction vessel is loaded with 1.00 mol of compound C, which is allowed to reach equilibrium. Let the variable x represent the number of mol/L of compound A present at equilibrium. (a) In terms of x, what are the equilibrium concentrations of compounds B and C ? (b) What limits must be placed on the value of x so that all concentrations are positive? (c) By putting the equilibrium concentrations (in terms of x ) into the equilibriumconstant expression, derive an equation that can be solved for x. (d) The equation from part (c) is a cubic equation (one that hasthe form ax3+bx2+cx+d=0 ) In general, cubic equations cannot be solved in closed form. However, you can estimate the solution by plotting the cubic equation in the allowed range of x that you specified in part (b). The point at which the cubic equation crosses the x -axis is the solution. (e) From the plot in part (d), estimate the equilibrium concentrations of A,B, and C. (Hint: You can check the accuracy of your answer by substituting these concentrations into the equilibrium expression.)

At 700 K the equilibrium constant for the reaction CCl4(g)C(s)+2Cl2(g) is Kp=0.76. A flask is charged with 2.00 atm of CCl4, which then reaches equilibrium at 700 K. (a) What fraction of the CCl4 is converted into C and Cl2? (b) What are the partial pressures of CCl4 and Cl2 at equilibrium?

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