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The oxidation of \(\mathrm{SO}_{2}\) to \(\mathrm{SO}_{3}\) is catalyzed by \(\mathrm{NO}_{2}\). Thereaction proceeds as follows: $$ \begin{aligned} &\mathrm{NO}_{2}(g)+\mathrm{SO}_{2}(g) \longrightarrow \mathrm{NO}(g)+\mathrm{SO}_{3}(g) \\ &2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{NO}_{2}(g) \end{aligned} $$ (a) Show that the two reactions can be summed to give the overall oxidation of \(\mathrm{SO}_{2}\) by \(\mathrm{O}_{2}\) to give \(\mathrm{SO}_{3}\). (Hint: The top reaction must be multiplied by a factor so the \(\mathrm{NO}\) and \(\mathrm{NO}_{2}\) cancel out.) (b) Why do we consider \(\mathrm{NO}_{2}\) a catalyst and not an intermediate in this reaction? (c) Is this an example of homogeneous catalysis or heterogeneous catalysis?

Short Answer

Expert verified
The overall reaction for the oxidation of \(\mathrm{SO}_{2}\) to \(\mathrm{SO}_{3}\) is \(2\mathrm{SO}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2\mathrm{SO}_{3}(g)\). \(\mathrm{NO}_{2}\) is considered a catalyst because it increases the reaction rate without being consumed in the overall reaction. This is an example of homogeneous catalysis since the catalyst and reactants are all in the gaseous phase.

Step by step solution

01

Combining the Reactions to Get the Overall Reaction

We are given the following two reactions: \( \mathrm{NO}_{2}(g)+\mathrm{SO}_{2}(g) \longrightarrow \mathrm{NO}(g)+\mathrm{SO}_{3}(g) \\ 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{NO}_{2}(g) \) To cancel out \(\mathrm{NO}\) and \(\mathrm{NO}_{2}\), we will multiply the first reaction by 2 and then add it to the second reaction: \( 2[\mathrm{NO}_{2}(g)+\mathrm{SO}_{2}(g) \longrightarrow \mathrm{NO}(g)+\mathrm{SO}_{3}(g)] \\ \) This gives us: \( 2 \mathrm{NO}_{2}(g) + 2\mathrm{SO}_{2}(g) \longrightarrow 2\mathrm{NO}(g)+ 2\mathrm{SO}_{3}(g) \) Now we add this to the second reaction: \( (2 \mathrm{NO}_{2}(g) + 2\mathrm{SO}_{2}(g)) + (2 \mathrm{NO}(g)+\mathrm{O}_{2}(g)) \longrightarrow (2\mathrm{NO}(g)+ 2\mathrm{SO}_{3}(g)) + (2 \mathrm{NO}_{2}(g)) \) After canceling out the common terms, we get the overall reaction: \( 2\mathrm{SO}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2\mathrm{SO}_{3}(g) \)
02

Explaining Why \(\mathrm{NO}_{2}\) is a Catalyst

A catalyst is a substance that increases the rate of a chemical reaction without being consumed in the reaction. An intermediate is a species formed in one step of a reaction then consumed in another step. In our case, \(\mathrm{NO}_{2}\) is present at the beginning of the first reaction and formed at the end of the second reaction. As it is not consumed throughout the entire process, we consider \(\mathrm{NO}_{2}\) as a catalyst.
03

Identifying the Type of Catalysis

There are two types of catalysis: homogeneous and heterogeneous. Homogeneous catalysis occurs when the catalyst and reactants are in the same phase (e.g., both are in the gaseous phase), while heterogeneous catalysis occurs when the catalyst and reactants are in different phases. In our case, all the reactants and the catalyst, \(\mathrm{NO}_{2}\), are in the gaseous phase. Therefore, this is an example of homogeneous catalysis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation
Oxidation is a crucial part of many chemical reactions and refers to the process where a substance loses electrons. In the context of the given reactions, the oxidation process involves the conversion of sulfur dioxide (\(\mathrm{SO}_{2}\)) into sulfur trioxide (\(\mathrm{SO}_{3}\)). This conversion happens through an increase in the oxidation state of sulfur, essentially involving the addition of oxygen atoms to \(\mathrm{SO}_{2}\).
The overall reaction represents the oxidation of sulfur dioxide, where it gains oxygen atoms from the oxygen molecule \(\mathrm{O}_{2}\). This reaction is represented by the equation:
  • 2\(\mathrm{SO}_{2}(g) + \mathrm{O}_{2}(g) \rightarrow 2\mathrm{SO}_{3}(g)\)
This equation highlights the role of oxygen in the oxidation process.
In oxidation reactions, the substance that loses electrons is oxidized, here being \(\mathrm{SO}_{2}\), transforming into \(\mathrm{SO}_{3}\). Understanding oxidation helps in grasping how substances transform during chemical reactions.
Reaction Mechanism
A reaction mechanism describes the step-by-step process by which a chemical reaction occurs. Each step of the reaction can involve the breaking and forming of bonds to reach the final products. In this exercise, the transformation from \(\mathrm{SO}_{2}\) to \(\mathrm{SO}_{3}\) catalyzed by \(\mathrm{NO}_{2}\) is a multi-step process.
Initially, \(\mathrm{NO}_{2}\) reacts with \(\mathrm{SO}_{2}\) to produce \(\mathrm{NO}\) and \(\mathrm{SO}_{3}\). Then, \(\mathrm{NO}\) quickly reacts with \(\mathrm{O}_{2}\) to regenerate \(\mathrm{NO}_{2}\). The overall mechanism can be summarized as:
  • \(\mathrm{NO}_{2}(g)+\mathrm{SO}_{2}(g) \rightarrow \mathrm{NO}(g)+\mathrm{SO}_{3}(g)\)
  • \(2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \rightarrow 2 \mathrm{NO}_{2}(g)\)
Combining these two steps and cancelling out the intermediates results in the overall oxidation reaction. Understanding each step of these mechanisms is crucial, as they explain how reactants convert into products through different stages.
Chemical Kinetics
Chemical kinetics is the field that studies the speed or rate of chemical reactions and the factors that affect these rates. For the oxidation of \(\mathrm{SO}_{2}\) to \(\mathrm{SO}_{3},\) the presence of \(\mathrm{NO}_{2}\) affects the kinetics significantly. As a catalyst, \(\mathrm{NO}_{2}\) provides an alternate pathway with a lower activation energy for the reaction.
This lower activation energy means that the reaction can proceed faster than it would without the catalyst. It doesn’t alter the equilibrium of the reaction but merely increases the rate at which equilibrium is reached. Key factors affecting chemical kinetics include:
  • Concentration of reactants
  • Temperature
  • Presence of a catalyst (such as \(\mathrm{NO}_{2}\) in this case)
These factors play a vital role in the efficiency and speed of chemical reactions in both laboratory and industrial settings.
Homogeneous Catalysis
Homogeneous catalysis occurs when the catalyst is in the same phase as the reactants. In our reaction, both the reactants and the catalyst \(\mathrm{NO}_{2}\) are gases. This setup of all species in the gaseous phase exemplifies homogeneous catalysis.
In this type of catalysis, the catalyst and reactants freely mix, allowing the reaction to occur uniformly through the medium. The homogeneous catalyst (\(\mathrm{NO}_{2}\)) facilitates the reaction between \(\mathrm{SO}_{2}\) and \(\mathrm{O}_{2}\).
The advantages of homogeneous catalysis include:
  • Ease of mixing and interaction between catalyst and reactants
  • Uniform reactions throughout the medium
  • Simplicity in controlling reaction conditions
However, separating the catalyst from the products can sometimes be challenging, which is a consideration in process design. Homogeneous catalysis is vital in processes where uniformity and consistency are key requirements.

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Most popular questions from this chapter

(a) Most heterogeneous catalysts of importance are extremely finely divided solid materials. Why is particle size important? (b) What role does adsorption play in the action of a heterogeneous catalyst?

A flask is charged with \(0.100 \mathrm{~mol}\) of \(\mathrm{A}\) and allowed to react to form \(B\) according to the hypothetical gas-phase reaction \(\mathrm{A}(\mathrm{g}) \longrightarrow \mathrm{B}(\mathrm{g})\). The following data are collected: \begin{tabular}{lccccc} \hline Time (s) & 0 & 40 & 80 & 120 & 160 \\ \hline Moles of A & \(0.100\) & \(0.067\) & \(0.045\) & \(0.030\) & \(0.020\) \\ \hline \end{tabular} (a) Calculate the number of moles of \(\mathrm{B}\) at each time in the table. (b) Calculate the average rate of disappearance of \(\mathrm{A}\) for each \(40-\mathrm{s}\) interval, in units of \(\mathrm{mol} / \mathrm{s}\). (c) What additional information would be needed to calculate the rate in units of concentration per time?

In a hydrocarbon solution, the gold compound \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{AuPH}_{3}\) decomposes into ethane \(\left(\mathrm{C}_{2} \mathrm{H}_{6}\right)\) and a dif- ferent gold compound, \(\left(\mathrm{CH}_{3}\right) \mathrm{AuPH}_{3}\). The following mechanism has been proposed for the decomposition of \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{AuPH}_{3}:\) Step 1: \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{AuPH}_{3} \underset{k_{-1}}{\stackrel{k_{1}}{\rightleftharpoons}\left(\mathrm{CH}_{3}\right)_{3} \mathrm{Au}+\mathrm{PH}_{3} \quad \text { (fast) }}\) Step 2: \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{Au} \stackrel{\mathrm{k}_{2}}{\longrightarrow} \mathrm{C}_{2} \mathrm{H}_{6}+\left(\mathrm{CH}_{3}\right) \mathrm{Au} \quad\) (slow) Step 3: \(\left(\mathrm{CH}_{3}\right) \mathrm{Au}+\mathrm{PH}_{3} \stackrel{k_{2}}{\longrightarrow}\left(\mathrm{CH}_{3}\right) \mathrm{AuPH}_{3} \quad\) (fast) (a) What is the overall reaction? (b) What are the intermediates in the mechanism? (c) What is the molecularity of each of the elementary steps? (d) What is the ratedetermining step? (e) What is the rate law predicted by this mechanism? (f) What would be the effect on the reaction rate of adding \(\mathrm{PH}_{3}\) to the solution of \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{AuPH}_{3} ?\)

The rates of many atmospheric reactions are accelerated by the absorption of light by one of the reactants. For example, consider the reaction between methane and chlorine to produce methyl chloride and hydrogen chloride: Reaction 1: \(\mathrm{CH}_{4}(\mathrm{~g})+\mathrm{Cl}_{2}(\mathrm{~g}) \longrightarrow \mathrm{CH}_{3} \mathrm{Cl}(\mathrm{g})+\mathrm{HCl}(\mathrm{g})\) This reaction is very slow in the absence of light. However, \(\mathrm{Cl}_{2}(g)\) can absorb light to form \(\mathrm{Cl}\) atoms: $$ \text { Reaction 2: } \mathrm{Cl}_{2}(g)+h v \longrightarrow 2 \mathrm{Cl}(g) $$ Once the \(\mathrm{Cl}\) atoms are generated, they can catalyze the reaction of \(\mathrm{CH}_{4}\) and \(\mathrm{Cl}_{2}\), according to the following proposed mechanism: Reaction 3: \(\mathrm{CH}_{4}(\mathrm{~g})+\mathrm{Cl}(\mathrm{g}) \longrightarrow \mathrm{CH}_{3}(\mathrm{~g})+\mathrm{HCl}(\mathrm{g})\) Reaction 4: \(\mathrm{CH}_{3}(\mathrm{~g})+\mathrm{Cl}_{2}(g) \longrightarrow \mathrm{CH}_{3} \mathrm{Cl}(g)+\mathrm{Cl}(g)\) The enthalpy changes and activation energies for these two reactions are tabulated as follows: $$ \begin{array}{lll} \hline \text { Reaction } & \Delta H_{\mathrm{ran}}^{\circ}(\mathrm{kJ} / \mathrm{mol}) & E_{a}(\mathrm{~kJ} / \mathrm{mol}) \\ \hline 3 & +4 & 17 \\ 4 & -109 & 4 \end{array} $$ (a) By using the bond enthalpy for \(\mathrm{Cl}_{2}\) (Table \(8.4\) ), determine the longest wavelength of light that is energetic enough to cause reaction 2 to occur. In which portion of the electromagnetic spectrum is this light found? (b) By using the data tabulated here, sketch a quantitative energy profile for the catalyzed reaction represented by reactions 3 and 4. (c) By using bond enthalpies, estimate where the reactants, \(\mathrm{CH}_{4}(g)+\mathrm{Cl}_{2}(g)\), should be placed on your diagram in part (b). Use this result to estimate the value of \(E_{a}\) for the reaction \(\mathrm{CH}_{4}(g)+\mathrm{Cl}_{2}(g) \longrightarrow\) \(\mathrm{CH}_{3}(g)+\mathrm{HCl}(g)+\mathrm{Cl}(g) .\) (d) The species \(\mathrm{Cl}(g)\) and \(\mathrm{CH}_{3}(\mathrm{~g})\) in reactions 3 and 4 are radicals, that is, atoms or molecules with unpaired electrons. Draw a Lewis structure of \(\mathrm{CH}_{3}\), and verify that is a radical. (e) The sequence of reactions 3 and 4 comprise a radical chain mechanism. Why do you think this is called a "chain reaction"? Propose a reaction that will terminate the chain reaction.

As described in Exercise \(14.37\), the decomposition of sulfuryl chloride \(\left(\mathrm{SO}_{2} \mathrm{Cl}_{2}\right)\) is a first-order process. The rate constant for the decomposition at \(660 \mathrm{~K}\) is \(4.5 \times 10^{-2} \mathrm{~s}^{-1}\). (a) If we begin with an initial \(\mathrm{SO}_{2} \mathrm{Cl}_{2}\) pressure of 375 torr, what is the pressure of this substance after 65 s? (b) At what time will the pressure of \(\mathrm{SO}_{2} \mathrm{Cl}_{2}\) decline to one-tenth its initial value?

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