Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The reaction \(2 \mathrm{NO}(g)+\mathrm{Cl}_{2}(g)-\rightarrow 2 \mathrm{NOCl}(g)\) obeys the rate law, rate \(=k[\mathrm{NO}]^{2}\left[\mathrm{Cl}_{2}\right]\). The following mechanism has been proposed for this reaction: $$ \begin{aligned} \mathrm{NO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{~g}) & \longrightarrow \mathrm{NOCl}_{2}(g) \\ \mathrm{NOCl}_{2}(g)+\mathrm{NO}(g) & \cdots & 2 \mathrm{NOCl}(g) \end{aligned} $$ (a) What would the rate law be if the first step were rate determining? (b) Based on the observed rate law, what can we conclude about the relative rates of the two steps?

Short Answer

Expert verified
The rate law considering the first step as rate-determining would be \(\text{rate} = k_1[\mathrm{NO}][\mathrm{Cl}_{2}]\). Comparing this with the observed rate law, \(\text{rate} = k[\mathrm{NO}]^{2}[\mathrm{Cl}_{2}]\), we notice a difference in the concentration terms of \(\mathrm{NO}\). Based on this discrepancy, we can infer that the second step is likely to be the rate-determining step in the mechanism, with a comparatively slower rate than the first step.

Step by step solution

01

(a) Finding the rate law considering the first step as rate determining

To find the rate law considering the first step as rate-determining, we should apply the rate law only to the first reaction. The first reaction is \[ \mathrm{NO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{g}) \longrightarrow \mathrm{NOCl}_{2}(g) . \] If this step is rate-determining, then the rate law for this step would be: \[ \text{rate} = k_1[\mathrm{NO}][\mathrm{Cl}_{2}] , \] where \(k_1\) is the rate constant for the first step.
02

(b) Comparing observed rate law with the rate law obtained in (a)

Now, we will compare the rate law we got in (a) with the given observed rate law, which is: \[\text{rate} = k[\mathrm{NO}]^{2}[\mathrm{Cl}_{2}] .\] When comparing the two rate laws, we notice that the rate law obtained in (a) lacks the squared concentration of \(\mathrm{NO}\) and the observed rate law has the squared concentration of \(\mathrm{NO}\). This difference in rate laws suggests that the first step cannot be the rate-determining step because it doesn't match the observed rate law. Therefore, we can conclude that the second step is likely to be the rate-determining step. By comparing the observed rate law with the proposed reaction mechanism, we can conclude that the second step is comparatively slower than the first step, as it is more likely to be the rate-determining step.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Law
Understanding the rate law is crucial for grasping how chemical reactions occur. Essentially, the rate law expresses the relationship between the concentration of reactants and the rate of the reaction.

The rate law for a reaction is often determined experimentally and is usually of the form \[ \text{rate} = k[\text{Reactant}_1]^{m}[\text{Reactant}_2]^{n} \], where \( k \) is the rate constant and \( m \) and \( n \) are the reaction orders for the respective reactants. These orders are not generally equal to the stoichiometric coefficients in the balanced equation for the reaction.

When you encounter an exercise involving rate laws, it's vital to compare the proposed reaction mechanism with the observed rate law. If the rate law derived from the proposed mechanism matches the observed rate law, the mechanism is plausible. However, if there is a discrepancy, like a difference in the reaction orders, it might suggest that the proposed mechanism does not accurately describe the steps of the reaction.
Reaction Mechanism
Diving deeper, the reaction mechanism tells the story of how reactants are transformed into products at the molecular level. It’s a step-by-step description that shows the sequences of elementary reactions that take place.

When considering a mechanism, chemists break it down into elementary steps—each step has its own rate law. For an overall reaction, such as \(2 \mathrm{NO}(g) + \mathrm{Cl}_2(g) \rightarrow 2 \mathrm{NOCl}(g)\), a proposed mechanism might involve several species that do not appear in the overall balanced equation. These are called intermediates.

By analyzing each step, we can deduce which step is the slowest, also known as the rate-determining step, which has a significant effect on the overall reaction rate. It's like a bottleneck in a production line—no matter how fast the earlier steps are, if one step is slow, it limits the overall rate of production. Similarly, in a reaction, the slowest elementary step determines the reaction rate.
Rate-Determining Step
The rate-determining step is akin to the slowest runner in a relay race—it sets the pace for the whole reaction. It’s the slowest step in the proposed reaction mechanism, and it controls the speed at which the overall reaction proceeds.

In our given exercise, we compared the rate law from the rate-determining step in the proposed mechanism to the experimentally determined rate law. The discrepancy between the two helped us identify that the first step couldn't be the rate-determining step because it failed to match the complexity of the observed rate law that included a squared concentration of \(\mathrm{NO}\).

This process is fundamental in chemical kinetics because understanding which step is rate-determining in a reaction allows chemists to tweak reaction conditions to achieve desired rates or to understand better why certain reactions happen the way they do. Remember, the rate-determining step will always give you insight into the kinetics of the reaction, even if the overall mechanism is still under investigation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

NO catalyzes the decomposition of \(\mathrm{N}_{2} \mathrm{O}\), possibly by the following mechanism: $$ \begin{array}{r} \mathrm{NO}(\mathrm{g})+\mathrm{N}_{2} \mathrm{O}(\mathrm{g}) \longrightarrow \mathrm{N}_{2}(g)+\mathrm{NO}_{2}(g) \\ 2 \mathrm{NO}_{2}(g) \longrightarrow 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \end{array} $$ (a) What is the chemical equation for the overall reaction? Show how the two steps can be added to give the overall equation. (b) Why is NO considered a catalyst and not an intermediate? (c) If experiments show that during the decomposition of \(\mathrm{N}_{2} \mathrm{O}, \mathrm{NO}_{2}\) does not accumulate in measurable quantities, does this rule out the proposed mechanism? If you think not, suggest what might be going on.

The reaction \(2 \mathrm{NO}_{2} \longrightarrow 2 \mathrm{NO}+\mathrm{O}_{2}\) has the rate constant \(k=0.63 \mathrm{M}^{-1} \mathrm{~s}^{-1}\). Based on the units for \(k\), is the reaction first or second order in \(\mathrm{NO}_{2} ?\) If the initial concentration of \(\mathrm{NO}_{2}\) is \(0.100 \mathrm{M}\), how would you determine how long it would take for the concentration to decrease to \(0.025 \mathrm{M} ?\)

The oxidation of \(\mathrm{SO}_{2}\) to \(\mathrm{SO}_{3}\) is catalyzed by \(\mathrm{NO}_{2}\). Thereaction proceeds as follows: $$ \begin{aligned} &\mathrm{NO}_{2}(g)+\mathrm{SO}_{2}(g) \longrightarrow \mathrm{NO}(g)+\mathrm{SO}_{3}(g) \\ &2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{NO}_{2}(g) \end{aligned} $$ (a) Show that the two reactions can be summed to give the overall oxidation of \(\mathrm{SO}_{2}\) by \(\mathrm{O}_{2}\) to give \(\mathrm{SO}_{3}\). (Hint: The top reaction must be multiplied by a factor so the \(\mathrm{NO}\) and \(\mathrm{NO}_{2}\) cancel out.) (b) Why do we consider \(\mathrm{NO}_{2}\) a catalyst and not an intermediate in this reaction? (c) Is this an example of homogeneous catalysis or heterogeneous catalysis?

What is the molecularity of each of the following elementary reactions? Write the rate law for each. (a) \(\mathrm{Cl}_{2}(g) \rightarrow 2 \mathrm{Cl}(g)\) (b) \(\mathrm{OCl}^{-}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{HOCl}(a q)+\mathrm{OH}^{-}(a q)\) (c) \(\mathrm{NO}(g)+\mathrm{Cl}_{2}(g) \longrightarrow \mathrm{NOCl}_{2}(g)\)

(a) Consider the combustion of \(\mathrm{H}_{2}(g): 2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g)\) \(\longrightarrow 2 \mathrm{H}_{2} \mathrm{O}(g) .\) If hydrogen is buming at the rate of \(0.85 \mathrm{~mol} / \mathrm{s}\), what is the rate of consumption of oxygen? What is the rate of formation of water vapor? (b) The reaction \(2 \mathrm{NO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{NOCl}(g)\) is carried out in a closed vessel. If the partial pressure of \(\mathrm{NO}\) is decreasing at the rate of 23 torr/min, what is the rate of change of the total pressure of the vessel?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free