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One of the many remarkable enzymes in the human body is carbonic anhydrase, which catalyzes the interconversion of carbonic acid with carbon dioxide and water. If it were not for this enzyme, the body could not rid itself rapidly enough of the \(\mathrm{CO}_{2}\) accumulated by cell metabolism. The enzyme catalyzes the dehydration (release to air) of up to \(10^{7} \mathrm{CO}_{2}\) molecules per second. Which components of this description correspond to the terms enzyme, substrate, and turnover number?

Short Answer

Expert verified
In the given description, the enzyme is carbonic anhydrase, which catalyzes the interconversion of the substrate, carbonic acid, with carbon dioxide and water. The turnover number is \(10^7\) molecules of \(\mathrm{CO}_{2}\) per second.

Step by step solution

01

Define Key Terms

Before we can identify the components in the description, let's define the key terms. 1. Enzyme: A protein that acts as a catalyst, speeding up a specific biochemical reaction. 2. Substrate: The molecule upon which an enzyme acts. 3. Turnover number: The number of substrate molecules an enzyme can convert into product per unit time.
02

Identify the Enzyme

In the given description, the enzyme is mentioned directly: "One of the many remarkable enzymes in the human body is carbonic anhydrase." Thus, the enzyme in this case is carbonic anhydrase.
03

Identify the Substrate

The description provides information about the biochemical reaction that carbonic anhydrase catalyzes: "catalyzes the interconversion of carbonic acid with carbon dioxide and water." Therefore, the substrate for the enzyme carbonic anhydrase is carbonic acid.
04

Identify the Turnover Number

The turnover number is mentioned in the description: "The enzyme catalyzes the dehydration (release to air) of up to \(10^7 \mathrm{CO}_{2}\) molecules per second." In this case, the turnover number is \(10^7\) molecules of \(\mathrm{CO}_{2}\) per second. In conclusion: Enzyme: Carbonic anhydrase Substrate: Carbonic acid Turnover number: \(10^7\) molecules of \(\mathrm{CO}_{2}\) per second.

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Most popular questions from this chapter

You study the effect of temperature on the rate of two reactions and graph the natural logarithm of the rate constant for each reaction as a function of \(1 / T\). How do the two graphs compare (a) if the activation energy of the second reaction is higher than the activation energy of the first reaction but the two reactions have the same frequency factor, and (b) if the frequency factor of the second reaction is higher than the frequency factor of the first reaction but the two reactions have the same activation energy? [Section \(14.5\)

Consider a hypothetical reaction between \(\mathrm{A}, \mathrm{B}\), and \(\mathrm{C}\) that is firstorder in \(A\), zero order in \(B\), and second order in C. (a) Write the rate law for the reaction. (b) How does the rate change when \([\mathrm{A}]\) is doubled and the other reactant concentrations are held constant? (c) How does the rate change when [B] is tripled and the other reactant concentrations are held constant? (d) How does the rate change when \([\mathrm{C}]\) is tripled and the other reactant concentrations are held constant? (e) By what factor does the rate change when the concentrations of all three reactants are tripled?

(a) Consider the combustion of \(\mathrm{H}_{2}(g): 2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g)\) \(\longrightarrow 2 \mathrm{H}_{2} \mathrm{O}(g) .\) If hydrogen is buming at the rate of \(0.85 \mathrm{~mol} / \mathrm{s}\), what is the rate of consumption of oxygen? What is the rate of formation of water vapor? (b) The reaction \(2 \mathrm{NO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{NOCl}(g)\) is carried out in a closed vessel. If the partial pressure of \(\mathrm{NO}\) is decreasing at the rate of 23 torr/min, what is the rate of change of the total pressure of the vessel?

There are literally thousands of enzymes at work in complex living systems such as human beings. What properties of the enzymes give rise to their ability to distinguish one substrate from another?

The first-order rate constant for reaction of a particular organic compound with water varies with temperature as follows: $$ \begin{array}{ll} \hline \text { Temperature (K) } & \text { Rate Constant (s }^{-1} \text { ) } \\\ \hline 300 & 3.2 \times 10^{-11} \\ 320 & 1.0 \times 10^{-9} \\ 340 & 3.0 \times 10^{-8} \\ 355 & 2.4 \times 10^{-7} \\ \hline \end{array} $$ From these data, calculate the activation energy in units of \(\mathrm{kJ} / \mathrm{mol}\).

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