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Indicate the type of crystal (molecular, metallic, covalent-network, or ionic) each of the following would form upon solidification: (a) \(\mathrm{CaCO}_{3},(\mathrm{~b}) \mathrm{Pt}\), (c) \(\mathrm{ZrO}_{2}\) (melting point, \(2677^{\circ} \mathrm{C}\) ), (d) table sugar \(\left(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\right)\), (e) benzene, (f) \(I_{2}\).

Short Answer

Expert verified
(a) CaCO3: Ionic solid (b) Pt: Metallic solid (c) ZrO2: Ionic solid (d) C12H22O11 (table sugar): Molecular solid (e) Benzene: Molecular solid (f) I2: Molecular solid

Step by step solution

01

Identify the components

In this step, identify the different elements and ions that constitute each compound. (a) CaCO3: calcium (Ca), carbonate ion (CO3^2-) (b) Pt: platinum (c) ZrO2: zirconium (Zr), oxide ion (O^2-) (d) C12H22O11: carbon (C), hydrogen (H), and oxygen (O) (e) Benzene: carbon (C), hydrogen (H) (f) I2: iodine (I)
02

Determine the type of bond

In this step, determine the type of bond(s) formed between the components of each compound. (a) CaCO3: Ionic (metal and polyatomic ion) (b) Pt: Metallic (single metal element) (c) ZrO2: Ionic (metal and non-metal ion) (d) C12H22O11: Covalent (non-metal elements) (e) Benzene: Covalent (non-metal elements) (f) I2: Covalent (single non-metal element)
03

Classify each compound as a type of solid

Now, based on the type of bond formed, classify each compound as a molecular, metallic, covalent-network, or ionic solid. (a) CaCO3: Ionic solid (b) Pt: Metallic solid (c) ZrO2: Ionic solid (high melting point indicates strong ionic bonding) (d) C12H22O11 (table sugar): Molecular solid (covalent bond, but not in extensive network structure) (e) Benzene: Molecular solid (covalent bond, but not in extensive network structure) (f) I2: Molecular solid (weak Van der Waals forces between the I2 molecules)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionic Bonds
Ionic bonds are the electrical forces that hold together ions in an ionic compound. When metals react with non-metals, electrons are typically transferred from the metal atoms to the nonmetal atoms. This process results in the formation of positive metal cations and negative non-metal anions. These oppositely charged ions attract, forming a strong ionic bond.
For example, calcium carbonate ( CaCO_3 ) forms an ionic bond. Calcium, a metal, donates electrons to the carbonate, a polyatomic non-metal ion. These ionic bonds give calcium carbonate its solid structure and relatively high melting point.
  • Ionic bonds result in the creation of ionic solids, which are usually hard and brittle.
  • They often dissolve well in water and conduct electricity in their molten state or when dissolved.
Taking zirconium dioxide ( ZrO_2 ) as another example, it's comprised of a metal (zirconium) and a non-metal (oxygen), demonstrating how such ionic binding can lead to high melting points.
Covalent Bonds
Covalent bonds are formed when two non-metal atoms share pairs of electrons. These shared electrons allow each atom to achieve a full outer electron shell, contributing to a stable electronic arrangement. Covalent bonds can involve single, double, or even triple sharing of electrons.
Molecules like table sugar ( C_{12}H_{22}O_{11} ) and benzene consist of atoms bonded covalently, forming molecular solids. Though these solids can form intricate molecular architectures, they do not create the extensive network structure akin to diamond or quartz.
  • In molecular solids, covalent ties bind molecules inside the units, but intermolecular forces maintain the overall solid form.
  • These solids usually have low melting points and might not conduct electricity well.
Iodine ( I_2 ) is another example of a molecular solid with covalent bonds within each diatomic molecule.
Metallic Bonds
Metallic bonds occur between metal atoms. In a metallic bond, electrons are not just transferred or shared between specific atoms. Instead, they form a 'sea of electrons' that are free to move between multiple atoms. This delocalization contributes to metals’ conductivity and malleability.
For instance, platinum ( Pt ) showcases metallic bonds. The atoms are closely packed together, and the free electrons allow for the conduction of electricity and heat.
  • Metallic solids are generally shiny, conductive, and malleable.
  • They form dense solid structures because of the tightly packed atom arrangement.
This explanation can be additionally applied to numerous metals found in various industrial and residential applications.
Molecular Solids
Molecular solids are formed by molecules bound together by Van der Waals forces, dipole-dipole interactions, or hydrogen bonds, rather than covalent or ionic forces. These intermolecular forces are weaker, generally resulting in lower melting and boiling points.
An example is benzene, which comprises covalently bonded carbon and hydrogen atoms. Though each individual molecule is strong, the forces between multiple benzene molecules are weak.
  • Molecular solids often appear as gases or liquids at room temperature, due to weak interactions.
  • They display varying degrees of solubility depending on the nature of the molecules and the solvent.
Table sugar ( C_{12}H_{22}O_{11} ) also illustrates a typical molecular solid, showing sweetness in numerous foods and drinks.
Classification of Solids
The classification of solids involves grouping them based on the types of bonds present and the overall structure they form. This classification helps in understanding the physical properties and behaviors of solid materials.
Here are the main categories:
  • Ionic Solids: Composed of ions held together by ionic bonds. Example: CaCO_3 (Calcium Carbonate).
  • Molecular Solids: Molecules held together by intermolecular forces, like Van der Waals. Example: Iodine ( I_2 ), Benzene, and Table Sugar.
  • Metallic Solids: Metal atoms held together by metallic bonds, characterized by delocalized electrons. Example: Platinum ( Pt ).
  • Covalent-Network Solids: Atoms connected by an extensive network of covalent bonds, leading to high melting points. Note: None from the given examples.
These classifications are paramount in material science, allowing predictions and adjustments of properties for practical applications in engineering and technology.

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Most popular questions from this chapter

Propyl alcohol \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\right)\) and isopropyl alcohol \(\left[\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHOH}\right]\), whose space- filling models are shown, have boiling points of \(97.2^{\circ} \mathrm{C}\) and \(82.5^{\circ} \mathrm{C}\), respectively. Explain why the boiling point of propyl alcohol is higher, even though both have the molecular formula of \(\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}\).

Ethyl chloride \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}\right)\) boils at \(12{ }^{\circ} \mathrm{C}\). When liquid \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}\) under pressure is sprayed on a room-temperature \(\left(25^{\circ} \mathrm{C}\right)\) surface in air, the surface is cooled considerably. (a) What does this observation tell us about the specific heat of \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}(g)\) as compared with \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}(l) ?\) (b) Assume that the heat lost by the surface is gained by ethyl chloride. What enthalpies must you consider if you were to calculate the final temperature of the surface?

The normal melting and boiling points of \(\mathrm{O}_{2}\) are \(-218{ }^{\circ} \mathrm{C}\) and \(-183{ }^{\circ} \mathrm{C}\) respectively. Its triple point is at \(-219^{\circ} \mathrm{C}\) and \(1.14\) torr, and its critical point is at \(-119^{\circ} \mathrm{C}\) and \(49.8\) atm. (a) Sketch the phase diagram for \(\mathrm{O}_{2}\), showing the four points given and indicating the area in which each phase is stable. (b) Will \(\mathrm{O}_{2}(s)\) float on \(\mathrm{O}_{2}(I)\) ? Explain. (c) As it is heated, will solid \(\mathrm{O}_{2}\) sublime or melt under a pressure of 1 atm?

The table shown here lists the molar heats of vaporization for several organic compounds. Use specific examples from this list to illustrate how the heat of vaporization varies with (a) molar mass, (b) molecular shape, (c) molecular polarity, (d) hydrogen-bonding interactions. Explain these comparisons in terms of the nature of the intermolecular forces at work. You may find it helpful to draw out the structural formula for each compound.) $$ \begin{array}{ll} \hline \text { Compound } & \begin{array}{l} \text { Heat of } \\ \text { Vaporization (kJ/mol) } \end{array} \\ \hline \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{3} & 19.0 \\ \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3} & 27.6 \\ \mathrm{CH}_{3} \mathrm{CHBrCH}_{3} & 31.8 \\ \mathrm{CH}_{3} \mathrm{COCH}_{3} & 32.0 \\ \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br} & 33.6 \\ \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH} & 47.3 \\ \hline \end{array} $$

The relative humidity of air equals the ratio of the partial pressure of water in the air to the equilibrium vapor pressure of water at the same temperature, times \(100 \%\). If the relative humidity of the air is \(58 \%\) and its temperature is \(68^{\circ} \mathrm{F}\), how many molecules of water are present in a room measuring \(12 \mathrm{ft} \times 10 \mathrm{ft} \times 8 \mathrm{ft}\) ?

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