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True or false: (a) \(\mathrm{CBr}_{4}\) is more volatile than \(\mathrm{CCl}_{4}\). (b) \(\mathrm{CBr}_{4}\) has a higher boiling point than \(\mathrm{CCl}_{4}\). (c) \(\mathrm{CBr}_{4}\) has weaker intermolecular forces than \(\mathrm{CCl}_{4}\). (d) \(\mathrm{CBr}_{4}\) has a higher vapor pressure at the same temperature than \(\mathrm{CCl}_{4}\)

Short Answer

Expert verified
(a) False (b) True (c) False (d) False

Step by step solution

01

Understanding Volatility

Volatility is the ability of a substance to evaporate or turn into a vapor at a given temperature. In general, substances with weaker intermolecular forces tend to have higher volatility as less energy is required to separate the molecules. To determine whether \(\mathrm{CBr}_{4}\) is more volatile than \(\mathrm{CCl}_{4}\), we need to compare their intermolecular forces.
02

Comparing Intermolecular Forces

The dominant intermolecular forces between \(\mathrm{CBr}_{4}\) and \(\mathrm{CCl}_{4}\) are London Dispersion Forces (LDF), which are temporary attractive forces that result from the constant motion of electrons. LDFs are stronger in molecules with more electrons, as they have larger electron clouds which can create stronger temporary dipoles. Since bromine has more electrons than chlorine, \(\mathrm{CBr}_{4}\) has stronger LDFs than \(\mathrm{CCl}_{4}\).
03

Answering Statement (a)

Since \(\mathrm{CBr}_{4}\) has stronger LDFs than \(\mathrm{CCl}_{4}\), it will require more energy to separate the molecules and is therefore less volatile. Statement (a) is false.
04

Understanding Boiling Points

The boiling point of a substance is the temperature at which its vapor pressure equals atmospheric pressure. In general, substances with stronger intermolecular forces have higher boiling points, as more energy is required to separate the molecules and overcome the attractive forces.
05

Answering Statement (b)

Since \(\mathrm{CBr}_{4}\) has stronger LDFs than \(\mathrm{CCl}_{4}\), it will have a higher boiling point. Statement (b) is true.
06

Answering Statement (c)

We already established that \(\mathrm{CBr}_{4}\) has stronger LDFs than \(\mathrm{CCl}_{4}\). Statement (c) is false.
07

Understanding Vapor Pressure

Vapor pressure is the pressure exerted by a vapor in equilibrium with its liquid phase at a given temperature. Substances with higher volatility have higher vapor pressures, as they evaporate more readily.
08

Answering Statement (d)

Since \(\mathrm{CBr}_{4}\) is less volatile than \(\mathrm{CCl}_{4}\) due to its stronger LDFs, it will have a lower vapor pressure at the same temperature. Statement (d) is false.

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Most popular questions from this chapter

The following molecules have the same molecular formula \(\left(\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}\right)\), yet they have different normal boiling points, as shown. Rationalize the difference in boiling points. [Sections \(11.2\) and 11.5]

The table shown here lists the molar heats of vaporization for several organic compounds. Use specific examples from this list to illustrate how the heat of vaporization varies with (a) molar mass, (b) molecular shape, (c) molecular polarity, (d) hydrogen-bonding interactions. Explain these comparisons in terms of the nature of the intermolecular forces at work. You may find it helpful to draw out the structural formula for each compound.) $$ \begin{array}{ll} \hline \text { Compound } & \begin{array}{l} \text { Heat of } \\ \text { Vaporization (kJ/mol) } \end{array} \\ \hline \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{3} & 19.0 \\ \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3} & 27.6 \\ \mathrm{CH}_{3} \mathrm{CHBrCH}_{3} & 31.8 \\ \mathrm{CH}_{3} \mathrm{COCH}_{3} & 32.0 \\ \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br} & 33.6 \\ \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH} & 47.3 \\ \hline \end{array} $$

Identify the types of intermolecular forces present in each of the following substances, and select the substance in each pair that has the higher boiling point: (a) \(\mathrm{C}_{6} \mathrm{H}_{14}\) or \(\mathrm{C}_{8} \mathrm{H}_{18}\) (b) \(\mathrm{C}_{3} \mathrm{H}_{8}\) or \(\mathrm{CH}_{3} \mathrm{OCH}_{3},(\mathrm{c}) \mathrm{HOOH}\) or \(\mathrm{HSSH}\), (d) \(\mathrm{NH}_{2} \mathrm{NH}_{2}\) or \(\mathrm{CH}_{3} \mathrm{CH}_{3}\)

Refer to Figure \(11.27(\mathrm{a})\), and describe all the phase changes that would occur in each of the following cases: (a) Water vapor originally at \(0.005 \mathrm{~atm}\) and \(-0.5^{\circ} \mathrm{C}\) is slowly compressed at constant temperature until the final pressure is \(20 \mathrm{~atm} .\) (b) Water originally at \(100.0^{\circ} \mathrm{C}\) and \(0.50 \mathrm{~atm}\) is cooled at constant pressure until the temperature is \(-10^{\circ} \mathrm{C}\).

When an atom or group of atoms is substituted for an atom in benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)\), the boiling pointchanges. Explair the order of the following boiling points: \(\mathrm{C}_{6} \mathrm{H}_{6}\left(80^{\circ} \mathrm{C}\right)\) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{Cl}\left(132{ }^{\circ} \mathrm{C}\right), \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{Br}\left(156^{\circ} \mathrm{C}\right), \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\left(182{ }^{\circ} \mathrm{C}\right) .\)

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