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Hydrazine \(\left(\mathrm{H}_{2} \mathrm{NNH}_{2}\right)\), hydrogen peroxide \((\mathrm{HOOH})\), and water \(\left(\mathrm{H}_{2} \mathrm{O}\right)\) all have exceptionally high surface tensions compared with other substances of comparable molecular weights. (a) Draw the Lewis structures for these three compounds. (b) What structural property do these substances have in common, and how might that account for the high surface tensions?

Short Answer

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The Lewis structures for hydrazine (H2NNH2), hydrogen peroxide (HOOH), and water (H2O) are: H2NNH2: ``` H - N - N - H | | H H ``` HOOH: ``` H - O - O - H | | | ``` H2O: ``` O | | H H ``` The common structural property among these molecules is their ability to form hydrogen bonds due to the presence of highly electronegative atoms (N in H2NNH2, O in HOOH and H2O) bonded to hydrogen atoms. This results in stronger intermolecular forces, leading to higher surface tensions compared to other substances with similar molecular weights.

Step by step solution

01

Draw Lewis structures for H2NNH2, HOOH, and H2O

To draw the Lewis structures, we need to count the valence electrons for each atom and distribute them among bonds and lone pairs. Hydrazine (H2NNH2): - N has 5 valence electrons - H has 1 valence electron Total valence electrons: 2(5) + 4(1) = 10 + 4 = 14. Lewis structure for H2NNH2: ``` H - N - N - H | | H H ``` Hydrogen peroxide (HOOH): - O has 6 valence electrons - H has 1 valence electron Total valence electrons: 2(6) + 2(1) = 12 + 2 = 14. Lewis structure for HOOH: ``` H - O - O - H | | | ``` Water (H2O): - O has 6 valence electrons - H has 1 valence electron Total valence electrons: 6 + 2(1) = 6 + 2 = 8. Lewis structure for H2O: ``` O | | H H ```
02

Identify the structural property and discuss its relationship to surface tension

All three molecules, H2NNH2, HOOH, and H2O, exhibit a common structural property: they can form hydrogen bonds. In each molecule, there is a highly electronegative atom (N in H2NNH2, O in HOOH and H2O) bonded to a hydrogen atom, making the molecule polar and capable of hydrogen bonding. Hydrogen bonding leads to stronger intermolecular forces between molecules. High surface tension is a consequence of strong intermolecular forces that make it more difficult for molecules to escape the surface and enter the gas or vapor phase. In summary, all three molecules can form hydrogen bonds, which results in stronger intermolecular forces and, consequently, higher surface tensions compared to other substances of similar molecular weights.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lewis Structures
Understanding Lewis structures is fundamental in chemistry as they provide a simple way to represent molecules and understand their bonding. A Lewis structure shows how valence electrons are distributed among atoms in a molecule.
To draw a Lewis structure, start by counting all the valence electrons for each atom involved. Distribute these electrons to form bonds between atoms and satisfy the octet rule, which states that atoms tend to have eight electrons in their outer shell.
For hydrazine (\( ext{H₄} \text{N₂}\)), nitrogen has five valence electrons while hydrogen has one. You create a bridge of electrons that form bonds between N atoms and H atoms. Similarly, hydrogen peroxide (\( ext{HOOH}\)) follows a similar procedure with oxygen's 6 valence electrons bonding with 1 of hydrogen.
Finally, water (\( ext{H₂O}\)), with oxygen's own six valence electrons used to bond with hydrogen atoms, making it a molecule with strong polar bonds.
Lewis structures not only illustrate the connectivity of the atoms but also help in predicting the molecule's shape, reactivity, and properties like surface tension.
Hydrogen Bonding
Hydrogen bonding is a special type of dipole-dipole attraction between molecules, which occurs when a hydrogen atom covalently bonded to a highly electronegative atom like nitrogen, oxygen, or fluorine is near another electronegative atom.
This bond is much stronger than a typical dipole-dipole interaction because of the high electronegativity difference creating a significant dipole.
  • In \( ext{H₂NNH₂}\) (hydrazine), each nitrogen atom in the structure shares electrons with hydrogen atoms, allowing for potential hydrogen bonding due to nitrogen's electronegativity.
  • \( ext{HOOH}\) (hydrogen peroxide) features oxygen atoms that engage in extensive hydrogen bonding, heightening its intermolecular attractions.
  • In \( ext{H₂O}\) (water), the classic hydrogen bonds occur because each water molecule can form bonds with up to four others, leading to the unique properties of water, including its high surface tension.
Hydrogen bonds are essential for determining the characteristics of many compounds, including their phase at room temperature and their interactions in biological systems such as DNA structure and protein folding.
Intermolecular Forces
Intermolecular forces are the forces of attraction or repulsion which act between neighboring particles like atoms, molecules, or ions. They are crucial in determining the physical properties of substances.
Hydrogen bonding is one such force, but there are others:
  • London Dispersion Forces (LDF): These are weak forces arising from temporary dipoles induced in atoms or molecules, significant in larger and non-polar molecules.
  • Dipole-Dipole Forces: These occur in molecules with permanent dipoles, and are weaker than hydrogen bonds but stronger than London forces.

For \( ext{H₂NNH₂}\), \( ext{HOOH}\), and \( ext{H₂O}\), hydrogen bonding is the prevailing intermolecular force, leading to their exceptionally high surface tension compared to other molecules of similar weight.
These strong intermolecular forces make it energetically more difficult for the molecules to separate from one another, affecting the melting and boiling points of these substances and their behavior in various states of matter. Understanding the different types of intermolecular forces helps to comprehend the complexity of molecular interactions and solubility.

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Most popular questions from this chapter

NaF has the same structure as \(\mathrm{NaCl}\). (a) Use ionic radii from Chapter 7 to estimate the length of the unit cell edge for NaF. (b) Use the unit cell size calculated in part (a) to estimate the density of NaF.

List the three states of matter in order of (a) increasing molecular disorder and (b) increasing intermolecular attractions. (c) Which state of matter is most easily compressed?

The fluorocarbon compound \(\mathrm{C}_{2} \mathrm{Cl}_{3} \mathrm{~F}_{3}\) has a normal boiling point of \(47.6^{\circ} \mathrm{C}\). The specific heats of \(\mathrm{C}_{2} \mathrm{Cl}_{3} \mathrm{~F}_{3}(l)\) and \(\mathrm{C}_{2} \mathrm{Cl}_{3} \mathrm{~F}_{3}(\mathrm{~g})\) are \(0.91 \mathrm{~J} / \mathrm{g}-\mathrm{K}\) and \(0.67 \mathrm{~J} / \mathrm{g}-\mathrm{K}\), respectively. The heat of vaporization for the compound is \(27.49 \mathrm{~kJ} / \mathrm{mol}\). Calculate the heat required to convert \(50.0 \mathrm{~g}\) of \(\mathrm{C}_{2} \mathrm{Cl}_{3} \mathrm{~F}_{3}\) from a liquid at \(10.00^{\circ} \mathrm{C}\) to a gas at \(85.00^{\circ} \mathrm{C}\).

Liquid butane, \(\mathrm{C}_{4} \mathrm{H}_{10}\), is stored in cylinders, to be used as a fuel. The normal boiling point of butane is listed as \(-0.5^{\circ} \mathrm{C}\). (a) Suppose the tank is standing in the sun and reaches a temperature of \(35^{\circ} \mathrm{C}\). Would you expect the pressure in the tank to be greater or less than atmospheric pressure? How does the pressure within the tank depend on how much liquid butane is in it? (b) Suppose the valve to the tank is opened and a few liters of butane are allowed to escape rapidly. What do you expect would happen to the temperature of the remaining liquid butane in the tank? Explain. (c) How much heat must be added to vaporize \(250 \mathrm{~g}\) of butane if its heat of vaporization is \(21.3 \mathrm{~kJ} / \mathrm{mol}\) ? What volume does this much butane occupy at 755 torr and \(35^{\circ} \mathrm{C}\) ?

Explain the following observations: (a) The surface tension of \(\mathrm{CHBr}_{3}\) is greater than that of \(\mathrm{CHCl}_{3}\). (b) As temperature increases, oil flows faster through a narrow tube. (c) Raindrops that collect on a waxed automobile hood take on a nearly spherical shape. (d) Oil droplets that collect on a waxed automobile hood take on a flat shape.

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