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Propyl alcohol \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\right)\) and isopropyl alcohol \(\left[\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHOH}\right]\), whose space- filling models are shown, have boiling points of \(97.2^{\circ} \mathrm{C}\) and \(82.5^{\circ} \mathrm{C}\), respectively. Explain why the boiling point of propyl alcohol is higher, even though both have the molecular formula of \(\mathrm{C}_{3} \mathrm{H}_{8} \mathrm{O}\).

Short Answer

Expert verified
The boiling point of propyl alcohol is higher than isopropyl alcohol because its linear structure allows for stronger intermolecular forces due to increased opportunities for hydrogen bonding between neighboring molecules. This results in more energy required to overcome these forces and turn the substance from a liquid to a gas. On the other hand, isopropyl alcohol has a more branched structure, resulting in weaker intermolecular forces and a lower boiling point.

Step by step solution

01

Understand the molecular structures of propyl alcohol and isopropyl alcohol.

The molecular structure of propyl alcohol is CH3CH2CH2OH, while the molecular structure of isopropyl alcohol is (CH3)2CHOH. Although both alcohols have the molecular formula C3H8O, their structures are quite different.
02

Examine the type of intermolecular forces present in each alcohol.

Both propyl alcohol and isopropyl alcohol exhibit hydrogen bonding due to the presence of the hydroxyl group (OH) in their structures. Hydrogen bonding occurs when the hydrogen atom is bonded to a highly electronegative atom (like oxygen), causing a partial positive charge on hydrogen and a partial negative charge on oxygen. This creates a strong attraction between the positively charged hydrogen atom of one molecule and the negatively charged oxygen atom of another molecule.
03

Evaluate the effect of molecule size and shape on hydrogen bonding.

Even though both alcohols exhibit hydrogen bonding, propyl alcohol has a more linear structure compared to the branched structure of isopropyl alcohol. This linear structure allows propyl alcohol molecules to be more closely packed together, leading to stronger intermolecular forces due to increased opportunities for hydrogen bonding between neighboring molecules.
04

Consider the relationship between intermolecular forces and boiling points.

A substance's boiling point is influenced by the strength of its intermolecular forces. The stronger the intermolecular forces, the more energy (in the form of heat) is required to overcome these forces and turn the substance from a liquid to a gas.
05

Explain the difference in boiling points.

Since propyl alcohol has a more linear structure, its molecules can be more closely packed together, leading to stronger intermolecular forces due to increased opportunities for hydrogen bonding. As a result, propyl alcohol has a higher boiling point compared to isopropyl alcohol, which has a more branched structure and weaker intermolecular forces. This difference in boiling points (97.2°C for propyl alcohol and 82.5°C for isopropyl alcohol) can be attributed to the differences in molecular structure and the corresponding strength of intermolecular forces present in each substance.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hydrogen Bonding
Hydrogen bonding is a special type of intermolecular force that significantly affects the physical properties of many substances, including alcohols. It occurs when a hydrogen atom is covalently bonded to a highly electronegative atom such as oxygen. This creates a situation where the hydrogen atom becomes partially positive, while the electronegative atom, like oxygen, becomes partially negative.

In the case of alcohols, the hydroxyl group (OH) means that both propyl alcohol and isopropyl alcohol can participate in hydrogen bonding. This attraction acts like a temporary "glue" holding the molecules together. These bonds are stronger than typical dipole-dipole interactions, but weaker than covalent bonds. Because of this added interaction, substances with hydrogen bonds generally have higher boiling points.
  • Hydrogen bonding occurs specifically when H is bonded to elements like O, N, or F.
  • It contributes to unexpected physical properties, such as abnormal boiling points.
  • In alcohols, this bonding plays a pivotal role in the liquid's physical behavior.
Molecular Structure
The molecular structure of a compound dictates how its molecules interact with each other. Propyl alcohol (\(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\)) and isopropyl alcohol (\([\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHOH}]\)) provide an excellent contrast between a linear and a branched structure.

The linear form of propyl alcohol allows the molecules to pack closely together. In contrast, the branched structure of isopropyl alcohol introduces kinks and disruptions that prevent the same level of closeness. These differences in molecular packing can influence how effectively the molecules can engage in intermolecular forces such as hydrogen bonding.
  • Linear molecules tend to pack more efficiently, strengthening intermolecular interactions.
  • Branched molecules have less effective intermolecular interaction, leading to reduced force strength.
  • The molecular arrangement impacts not only physical state but also properties like boiling point.
Boiling Point Comparison
The boiling point of any given substance is deeply influenced by the strength of intermolecular forces acting among its molecules. Stronger intermolecular forces require more energy to break, resulting in a higher boiling point. This is precisely why propyl alcohol has a boiling point of 97.2°C, compared to isopropyl alcohol's 82.5°C.

Despite having the same molecular formula, the structural differences mean that propyl alcohol has more opportunities for hydrogen bonding due to its linear configuration. The straight-chain structure allows molecules to approach each other more closely, enhancing these interactions.
  • Substances with stronger intermolecular forces have higher boiling points.
  • Linear molecules benefit from closer packing, thereby heightening the intermolecular attractions.
  • Comparisons of boiling points often reflect these fundamental intermolecular differences.
Alcohol Chemistry
Alcohols are a fascinating class of organic compounds that feature the hydroxyl (-OH) group as a defining characteristic. The chemistry of alcohols is highly influenced by the presence of this group, which not only determines their ability to bond with other molecules but also dictates their solubility in water and other polar solvents.

Understanding alcohol chemistry entails recognizing how structural variations, even with similar molecular formulas like in propyl and isopropyl alcohols, lead to differences in physical and chemical properties. The hydroxyl group is responsible for hydrogen bonding, a feature that fundamentally modifies their behavior when interacting with other molecules.
  • Alcohols' reactivity is largely determined by the presence of the \(-OH\) group.
  • Structural variation among alcohols impacts solubility and boiling points.
  • Hydrogen bonds play crucial roles in the defining characteristics of alcohols.

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Most popular questions from this chapter

Compounds like \(\mathrm{CCl}_{2} \mathrm{~F}_{2}\) are known as chlorofluorocarbons, or CFCs. These compounds were once widely used as refrigerants but are now being replaced by compounds that are believed to be less harmful to the environment. The heat of vaporization of \(\mathrm{CCl}_{2} \mathrm{~F}_{2}\) is \(289 \mathrm{~J} / \mathrm{g}\). What mass of this substance must evaporate to freeze \(200 \mathrm{~g}\) of water initially at \(15^{\circ} \mathrm{C} ?\) (The heat of fusion of water is \(334 \mathrm{~J} / \mathrm{g} ;\) the specific heat of water is \(4.18 \mathrm{~J} / \mathrm{g}-\mathrm{K}\).)

Using the following list of normal boiling points for a series of hydrocarbons, estimate the normal boiling point for octane, \(\mathrm{C}_{8} \mathrm{H}_{18}:\) propane \(\left(\mathrm{C}_{3} \mathrm{H}_{8},-42.1{ }^{\circ} \mathrm{C}\right)\), bu- tane \(\left(\mathrm{C}_{4} \mathrm{H}_{10},-0.5^{\circ} \mathrm{C}\right)\), pentane \(\left(\mathrm{C}_{5} \mathrm{H}_{12}, 36.1^{\circ} \mathrm{C}\right)\), hexane \(\left(\mathrm{C}_{6} \mathrm{H}_{14}, 68.7^{\circ} \mathrm{C}\right)\), heptane \(\left(\mathrm{C}_{7} \mathrm{H}_{16}, 98.4{ }^{\circ} \mathrm{C}\right)\). Explain the trend in the boiling points.

You are given a white substance that sublimes at \(3000^{\circ} \mathrm{C}\); the solid is a nonconductor of electricity and is insoluble in water. Which type of solid (Table 11.7) might this substance be?

In a certain type of nuclear reactor, liquid sodium metal is employed as a circulating coolant in a closed system, protected from contact with air or water. Much like the coolant that circulates in an automobile engine, the liquid sodium carries heat from the hot reactor core to heat exchangers. (a) What properties of the liquid sodium are of special importance in this application? (b) The viscosity of liquid sodium varies with temperature as follows: $$ \begin{array}{ll} \hline \text { Temperature }\left({ }^{\circ} \mathrm{C}\right) & \text { Viscosity }\left(\mathrm{kg} \mathrm{m}^{-1} \mathrm{~s}^{-1}\right) \\ \hline 100 & 7.05 \times 10^{-4} \\ 200 & 4.50 \times 10^{-4} \\ 300 & 3.45 \times 10^{-4} \\ 600 & 2.10 \times 10^{-4} \\ \hline \end{array} $$ What forces within the liquid sodium are likely to be the major contributors to the viscosity? Why does viscosity decrease with increasing temperature?

The vapor pressure of a volatile liquid can be determined by slowly bubbling a known volume of gas through it at a known temperature and pressure. In an experiment, \(5.00 \mathrm{~L}\) of \(\mathrm{N}_{2}\) gas is passed through \(7.2146 \mathrm{~g}\) of liquid benzene, \(\mathrm{C}_{6} \mathrm{H}_{6}\), at \(26.0{ }^{\circ} \mathrm{C}\). The liquid remaining after the experiment weighs \(5.1493 \mathrm{~g}\). Assuming that the gas becomes saturated with benzene vapor and that the total gas volume and temperature remain constant, what is the vapor pressure of the benzene in torr?

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