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Carry out the following operations, and express the answer with the appropriate number of significant figures. (a) \(320.5-(6104.5 / 2.3)\) (b) \(\left[\left(285.3 \times 10^{5}\right)-\left(1.200 \times 10^{3}\right)\right] \times 2.8954\) (c) \((0.0045 \times 20,000.0)+(2813 \times 12)\) (d) \(863 \times[1255-(3.45 \times 108)]\)

Short Answer

Expert verified
The short answers for each part are: (a) \(-2333.6\) (b) \(8.2597 \times 10^7\) (c) \(33846\) (d) \(761 \times 10^3\)

Step by step solution

01

Perform Division First

According to the order of operations, we need to perform the division before the subtraction. Calculate 6104.5 divided by 2.3. \[6104.5 \div 2.3 = 2654.1304...\] When dividing, the result should have the same number of significant figures as the value with the least number of significant figures. In this case, 6104.5 has the least number of significant figures (5). Thus, our result should be rounded to 5 significant figures: \[2654.1\]
02

Perform Subtraction

Now, subtract the result obtained in step 1 from 320.5. \[320.5 - 2654.1 = -2333.6\] Since both values have 4 significant digits, the result should also have 4 significant digits. Thus, the final answer is: \[-2333.6\] #b) [(285.3 x 10^5) - (1.200 x 10^3)] x 2.8954#
03

Perform Multiplications

First, perform the two multiplications: - 285.3 x 10^5 - 1.200 x 10^3 \[285.3 \times 10^5 = 2.853 \times 10^7\] \[1.200 \times 10^3 = 1.200 \times 10^3\]
04

Perform Subtraction

Next, subtract the two results: \[(2.853 \times 10^7) - (1.200 \times 10^3) = 2.852998 \times 10^7\]
05

Perform Final Multiplication

Finally, multiply the result obtained in step 2 by 2.8954: \[(2.852998 \times 10^7) \times 2.8954 = 8.2596916 \times 10^{7}\] Our answer should have the least number of significant figures, which is 5 in this case: \[8.2597 \times 10^7\] #c) (0.0045 x 20,000.0) + (2813 x 12)#
06

Perform Multiplication

First, perform the multiplication 0.0045 x 20,000.0: \[0.0045 \times 20,\!000.0 = 90.0\]
07

Perform Another Multiplication

Now, perform the multiplication 2813 x 12: \[2813 \times 12 = 33756\]
08

Perform Addition

Finally, add the two results obtained in step 1 and 2: \[90.0 + 33756 = 33846\] Keep the result with the lowest decimal places, which is 1 in this case: \[33846\] #d) 863 x [1255 - (3.45 x 108)]#
09

Perform Multiplication

First, perform the multiplication 3.45 x 108: \[3.45 \times 108 = 372.6\]
10

Perform Subtraction

Now, subtract the result obtained in step 1 from 1255: \[1255 - 372.6 = 882.4\]
11

Perform Final Multiplication

Finally, multiply the result obtained in step 2 by 863: \[863 \times 882.4 = 761450.2\] Our answer should have the least number of significant figures, which is 3 in this case: \[761 \times 10^3\]

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Most popular questions from this chapter

(a) To identify a liquid substance, a student determined its density. Using a graduated cylinder, she measured out a 45-mLsample of the substance. She then measured the mass of the sample, finding that it weighed \(38.5 \mathrm{~g}\) She knew that the substance had to be either isopropyl alcohol (density \(0.785 \mathrm{~g} / \mathrm{mL}\) ) or toluene (density \(0.866 / \mathrm{mL})\). What are the calculated density and the probable identity of the substance? (b) An experiment requires \(45.0 \mathrm{~g}\) of ethylene glycol, a liquid whose density is \(1.114 \mathrm{~g} / \mathrm{mL}\). Rather than weigh the sample on a balance, a chemist chooses to dispense the liquid using a graduated cylinder. What volume of the liquid should he use? (c) A cubic piece of metal measures \(5.00 \mathrm{~cm}\) on each edge. If the metal is nickel, whose density is \(8.90 \mathrm{~g} / \mathrm{cm}^{3}\), what is the mass of the cube?

Indicate which of the following are exact numbers: (a) the mass of a \(32-\mathrm{oz}\) can of coffee, \((\mathrm{b})\) the number of students in your chemistry class, (c) the temperature of the surface of the sun, (d) the mass of a postage stamp, (e) the number of milliliters in a cubic meter of water, (f) the average height of students in your school.

(a) After the label fell off a bottle containing a clear liquid believed to be benzene, a chemist measured the density of the liquid to verify its identity. A 25.0-mL portion of the liquid had a mass of \(21.95 \mathrm{~g}\). A chemistry handbook lists the density of benzene at \(15^{\circ} \mathrm{C}\) as \(0.8787 \mathrm{~g} / \mathrm{mL}\). Is the calculated density in agreement with the tabulated value? (b) An experiment requires \(15.0 \mathrm{~g}\) of cyclohexane, whose density at \(25{ }^{\circ} \mathrm{C}\) is \(0.7781 \mathrm{~g} / \mathrm{mL}\). What volume of cyclohexane should be used? (c) A spherical ball of lead has a diameter of \(5.0 \mathrm{~cm}\). What is the mass of the sphere if lead has a density of \(11.34 \mathrm{~g} / \mathrm{cm}^{3}\) ? (The volume of a sphere is \(\left(\frac{4}{3}\right) \pi r^{3}\) where \(r\) is the radius.)

Three spheres of equal size are composed of aluminum (density \(\left.=2.70 \mathrm{~g} / \mathrm{cm}^{3}\right)\), silver (density \(\left.=10.49 \mathrm{~g} / \mathrm{cm}^{3}\right)\), and nickel (density \(\left.=8.90 \mathrm{~g} / \mathrm{cm}^{3}\right)\). List the spheres from lightest to heaviest.

A match is lit and held under a cold piece of metal. The following observations are made: (a) The match burns. (b) The metal gets warmer. (c) Water condenses on the metal. (d) Soot (carbon) is deposited on the metal. Which of these occurrences are due to physical changes, and which are due to chemical changes?

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