Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Two elements in the second transition series (Y through Cd) have four unpaired electrons in their 3+ ions. What elements fit this description?

Short Answer

Expert verified
Molybdenum (Mo) and Technetium (Tc) fit this description.

Step by step solution

01

Understand the elements in the second transition series

The second transition series of elements includes the elements Yttrium (Y) through Cadmium (Cd) on the periodic table. These elements are characterized by their partially filled d-orbitals.
02

Determine the electronic configuration of 3+ ions

For each element (Y through Cd), determine the electron configuration of their 3+ ions. Removing three electrons typically starts from the outermost shell, usually involving the s and d orbitals.
03

Identify elements with four unpaired electrons

For each 3+ ion configuration, count the number of unpaired electrons in the d-orbitals. We are looking for configurations showing exactly four unpaired electrons.
04

List the suitable elements

From the configurations, identify those which, as a 3+ ion, align with having exactly four unpaired electrons in their d-orbitals. Specifically, look for the electronic configuration ending in d⁵, as it represents having four unpaired electrons.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Configuration
Electron configuration is key to understanding the chemical behavior of transition metals. It's the distribution of electrons among the different orbitals of an atom. Transition metals have electrons filling their "d" orbitals, which is what makes them intriguing. These orbitals can hold up to 10 electrons. Often, electron removal or addition affects these d-orbitals.
When we form 3+ ions from transition metals, we must remove three electrons. To do this, we usually start with the outermost electrons, typically from the "s" as well as "d" orbitals. This results in a modified configuration of the ion compared to its neutral atom. Understanding these changes helps us predict the properties of these ions. It's essential to also consider factors like stability and energy when determining these configurations.
Unpaired Electrons
Unpaired electrons are electrons that reside alone in an orbital. This makes them important for understanding the magnetic properties of a material.
In transition metals, it's the unpaired electrons in the d-orbitals that play a significant role. Orbital pairing is when electrons occupy the same orbital but have opposite spins. Naturally, transition metals can have varying numbers of unpaired electrons. These unpaired electrons lead to unique characteristics, such as paramagnetism.
  • Paramagnetism is when unpaired electrons align with external magnetic fields, causing attraction.
  • More unpaired electrons lead to stronger magnetic properties.
Specifically, the requirement for a 3+ ion having four unpaired electrons involves achieving a d⁵ configuration. This situation arises when five electrons occupy the d-orbitals, leaving one less in each, thus all being unpaired.
Transition Series Elements
The second transition series consists of elements from Yttrium (Y) to Cadmium (Cd). These elements share the characteristic of having partially filled d-orbitals. Transition metals, including these series, are crucial in various industries due to their unique properties like malleability and conductivity.
The series also shows variability in oxidation states, meaning the ability of an element to lose electrons and form positive ions. This variability is due to the relatively low energy differences between the s and d-orbitals, allowing for different combinations of electron loss.
  • Yttrium (Y) sits at the start of the series, known for a singular stable oxidation state.
  • Cadmium (Cd), the last element, is less prone to forming 3+ ions, often forming Cd²⁺.
Studying this series of elements helps us understand how small changes in electron configurations can lead to various chemical behaviors and properties, heightening our knowledge of transition metal chemistry.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Arrange the following elements in order of increasing size: Al, B, C, K, and Na. (Try doing it without looking at Figure \(7.6,\) then check yourself by looking up the necessary atomic radii.)

Which ions in the following list are not likely to be found in chemical compounds: \(\mathrm{K}^{2+}, \mathrm{Cs}^{+}, \mathrm{Al}^{4+}, \mathrm{F}^{2-},\) and \(\mathrm{Se}^{2-} ?\) Explain briefly.

Name the element corresponding to each characteristic below. (a) the element with the electron configuration \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{3}\) (b) the alkaline earth element with the smallest atomic radius (c) the element with the largest ionization energy in Group \(5 \mathrm{A}\) (d) the element whose \(2+\) ion has the configuration \([\mathrm{Kr}] 4 d^{5}\) (e) the element with the most negative electron attachment enthalpy in Group \(7 \mathrm{A}\) (f) the element whose electron configuration is \([\mathrm{Ar}] 3 d^{10} 4 s^{2}\)

A possible excited state for the H atom has an electron in a \(4 p\) orbital. List all possible sets of quantum numbers \(\left(n, \ell, m_{\ell}, m_{\mathrm{s}}\right)\) for this electron.

Answer each of the following questions: (a) Of the elements \(\mathrm{S}\), Se, and Cl, which has the largest atomic radius? (b) Which has the larger radius, Br or Br'? (c) Which should have the largest difference between the first and second ionization energy: Si, Na, P, or Mg? (d) Which has the largest ionization energy: \(\mathrm{N}, \mathrm{P}\), or \(\mathrm{As}\) ? (e) Which of the following has the largest radius: \(\mathbf{O}^{2-}\) \(\mathrm{N}^{3-},\) or \(\mathrm{F}^{-} ?\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free