Chapter 5: Problem 8
How much energy as heat is required to raise the temperature of \(50.00 \mathrm{mL}\) of water from \(25.52^{\circ} \mathrm{C}\) to \(28.75^{\circ} \mathrm{C} ?\) (Density of water at this temperature = \(0.997 \mathrm{g} / \mathrm{mL} .)\)
Short Answer
Expert verified
The heat required is 672.96 J.
Step by step solution
01
Determine the Mass of Water
The density of water is given as 0.997 g/mL, and the volume of water is 50.00 mL. We use the formula for mass: mass = density × volume. So, the mass of water is 0.997 g/mL × 50.00 mL = 49.85 g.
02
Calculate the Temperature Change
To find the change in temperature, we subtract the initial temperature from the final temperature: \( \Delta T = 28.75^{\circ} \mathrm{C} - 25.52^{\circ} \mathrm{C} = 3.23^{\circ} \mathrm{C} \).
03
Use the Specific Heat Formula
The formula for heat energy is \( q = m \times c \times \Delta T \), where:- \( q \) is the heat energy,- \( m \) is the mass (49.85 g),- \( c \) is the specific heat capacity of water (4.18 J/g°C),- \( \Delta T \) is the temperature change (3.23°C).
04
Calculate the Heat Energy
Substitute the known values into the formula: \( q = 49.85 \times 4.18 \times 3.23 \). This gives the heat energy \( q = 672.96 \) J.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Specific Heat Capacity
Specific heat capacity is a key concept in understanding how substances absorb or release energy as heat. It is defined as the amount of heat required to change the temperature of one gram of a substance by one degree Celsius. Each substance has its own specific heat capacity, meaning different materials require different amounts of energy to change temperature.
Here's a practical example: Water has a specific heat capacity of 4.18 J/g°C, which is relatively high compared to other substances. This means it can absorb a lot of heat without a large change in temperature. This is why water is excellent for regulating temperature in environments, such as in oceans and even our bodies.
When calculating energy changes with specific heat, you'll see it in formulas as the variable 'c'. This "c" value is crucial for determining how much heat is absorbed or released. To solve problems involving specific heat, you use the formula \( q = m \times c \times \Delta T \), where \( q \) is the heat energy involved, \( m \) is the mass, \( c \) is the specific heat capacity, and \( \Delta T \) is the temperature change of the substance.
Here's a practical example: Water has a specific heat capacity of 4.18 J/g°C, which is relatively high compared to other substances. This means it can absorb a lot of heat without a large change in temperature. This is why water is excellent for regulating temperature in environments, such as in oceans and even our bodies.
When calculating energy changes with specific heat, you'll see it in formulas as the variable 'c'. This "c" value is crucial for determining how much heat is absorbed or released. To solve problems involving specific heat, you use the formula \( q = m \times c \times \Delta T \), where \( q \) is the heat energy involved, \( m \) is the mass, \( c \) is the specific heat capacity, and \( \Delta T \) is the temperature change of the substance.
Temperature Change
Temperature change, denoted \( \Delta T \), is the difference in temperature between the final and initial states of a system. Understanding temperature change is crucial because it helps us determine how much energy is transferred during a heating or cooling process.
In the context of heat energy calculations, you calculate the change in temperature by subtracting the initial temperature \( T_i \) from the final temperature \( T_f \):
For example, if you have water that starts at \( 25.52^{\circ}\mathrm{C} \) and is heated to \( 28.75^{\circ}\mathrm{C} \), the temperature change is \( 3.23^{\circ}\mathrm{C} \). This difference is crucial in calculating how much energy is required to achieve this change. The greater the temperature change, the more energy needed, assuming mass and specific heat remain constant.
Always check your initial and final temperatures carefully, since any mistake could lead to incorrect conclusions about the amount of energy required.
In the context of heat energy calculations, you calculate the change in temperature by subtracting the initial temperature \( T_i \) from the final temperature \( T_f \):
- \( \Delta T = T_f - T_i \)
For example, if you have water that starts at \( 25.52^{\circ}\mathrm{C} \) and is heated to \( 28.75^{\circ}\mathrm{C} \), the temperature change is \( 3.23^{\circ}\mathrm{C} \). This difference is crucial in calculating how much energy is required to achieve this change. The greater the temperature change, the more energy needed, assuming mass and specific heat remain constant.
Always check your initial and final temperatures carefully, since any mistake could lead to incorrect conclusions about the amount of energy required.
Mass Calculations
Mass calculations are an essential part of determining the amount of energy required to change a substance’s temperature. The mass of a substance directly affects the total energy needed, essentially acting as a "multiplier" in energy calculations.
In many exercises, you might be given density and volume, like in our original exercise, where water's density is 0.997 g/mL, and the volume is 50.00 mL. You would calculate the mass using the formula:
Understanding mass is vital because even a small change in mass can significantly alter the heat calculations. More mass means more substance to heat and thus more energy required. Calculating mass correctly ensures that you're using the right amount of substance in your heat calculations.
Always double-check your mass calculations, especially when converting from volume, to ensure the accuracy of your entire heat calculation.
In many exercises, you might be given density and volume, like in our original exercise, where water's density is 0.997 g/mL, and the volume is 50.00 mL. You would calculate the mass using the formula:
- mass = density × volume
- mass = 0.997 g/mL × 50.00 mL = 49.85 g
Understanding mass is vital because even a small change in mass can significantly alter the heat calculations. More mass means more substance to heat and thus more energy required. Calculating mass correctly ensures that you're using the right amount of substance in your heat calculations.
Always double-check your mass calculations, especially when converting from volume, to ensure the accuracy of your entire heat calculation.