Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Determine whether energy as heat is evolved or required, and whether work was done on the system or whether the system does work on the surroundings, in the following processes at constant pressure: (a) Ozone, \(\mathrm{O}_{3},\) decomposes to form \(\mathrm{O}_{2}\) (b) Methane burns: \(\mathrm{CH}_{4}(\mathrm{g})+2 \mathrm{O}_{2}(\mathrm{g}) \rightarrow \mathrm{CO}_{2}(\mathrm{g})+2 \mathrm{H}_{2} \mathrm{O}(\ell)\)

Short Answer

Expert verified
(a) Heat is evolved, no work done. (b) Heat is evolved, work done on the system.

Step by step solution

01

Understanding Energy Evolved or Required

In any chemical reaction, if energy in the form of heat is released, it is termed as an exothermic reaction. Conversely, if energy is required for the reaction, it's an endothermic process. We'll analyze both processes separately to determine the nature of energy change.
02

Identifying Heat Change in Ozone Decomposition

The decomposition of ozone, \(\mathrm{O}_3\), into \(\mathrm{O}_2\) typically releases energy, meaning it is an exothermic reaction. Decomposition processes often release energy that was stored in the molecular bonds of the compound.
03

Analyzing Heat in Methane Combustion

The combustion of methane is a reaction that releases a significant amount of energy as heat. This is typical for combustion reactions, thus it is an exothermic process. The reactants (methane and oxygen) yield products (carbon dioxide and water) while releasing energy.
04

Understanding Work Done on System or Surroundings

Work done during a process is related to changes in volume at constant pressure. When a system expands, it does work on the surroundings. Conversely, if the surroundings compress the system, work is done on the system.
05

Work Associated with Ozone Decomposition

In the reaction \( \mathrm{O}_3 \rightarrow \mathrm{O}_2 \), there is a decrease in the number of gas molecules (3 moles of \( \mathrm{O}_2 \) to 2 moles of \( \mathrm{O}_3 \)). The system does not perform work on the surroundings, as typically, decomposition reactions involve no significant volume change.
06

Work in Methane Combustion

In the combustion of methane \(\mathrm{CH}_4(\mathrm{g})+2 \mathrm{O}_2(\mathrm{g}) \rightarrow \mathrm{CO}_2(\mathrm{g})+2 \mathrm{H}_2\mathrm{O}(\ell)\), the number of gas moles decreases (3 moles of gas reactants form 1 mole of gas product and 2 moles of liquid water), suggesting the system loses gas volume. Hence, the surroundings do work on the system.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exothermic reaction
Exothermic reactions are fascinating phenomena where a chemical reaction releases energy in the form of heat. A simple way to remember this concept is to associate the prefix 'exo' with 'exit', as energy exits the system and goes into the surroundings.

These reactions are marked by a noticeable increase in temperature, making them easy to spot.

  • Common examples include combustion, like burning wood or gas.
  • The formation of snowflakes is an exothermic process because heat is released as water vapor turns into ice.
In our exercise, methane combustion is a classic example of an exothermic reaction. As methane reacts with oxygen to form carbon dioxide and water, a great deal of heat is released. This release of energy is what powers many processes in everyday life, such as your car's engine. Understanding exothermic reactions is crucial for grasping how energy transfers in chemical processes and affects our environment and technology.
Endothermic reaction
Endothermic reactions are the chemical processes that absorb energy from their surroundings. The prefix 'endo' signifies 'inside', indicating that these reactions take in heat.

Unlike exothermic reactions, endothermic ones often result in a temperature drop in the surrounding area, since energy is being absorbed.

  • A classic example of an endothermic reaction is photosynthesis. Plants absorb sunlight to convert carbon dioxide and water into glucose and oxygen.
  • The melting of ice is another example, wherein the ice absorbs heat to transform into water.
Even though our current exercise does not focus on endothermic reactions, understanding them helps balance the overall concept of thermochemistry. In these reactions, energy must be supplied for the reaction to proceed, often making them feel energy-consuming.
Combustion
Combustion is a type of chemical reaction where a substance combines with oxygen, releasing energy in the form of heat and light. It is essentially a fast exothermic reaction.

This process is vital to numerous real-world applications, from heating homes to powering vehicles.

  • In the combustion reaction of methane, the natural gas burns with oxygen to produce carbon dioxide, water, and plenty of heat.
  • Combustion reactions typically have hydrocarbons, like gasoline or wood as fuel, making them omnipresent in both nature and industry.
Typically, combustion is part of a larger subset of reactions, known for being efficient in energy release. These reactions are not only reliable but are often used for their high energy outputs and economic value.
Decomposition reactions
Decomposition reactions involve breaking down a compound into simpler substances. It is a fundamental chemical process where one reactant yields multiple products.

This type of reaction can either absorb or release energy, making them not exclusively exothermic or endothermic.

  • An example is the decomposition of ozone, (\( \mathrm{O}_3 \rightarrow \mathrm{O}_2 \)), which releases energy as it occurs.
  • In decomposition reactions, the energy difference between bonds in the reactants and products determines if it will be an energy-releasing or absorbing process.
Understanding decomposition helps us appreciate the diverse ways that matter can transform and sustain energy flows. Decomposition processes are crucial in recycling elements within ecosystems, such as breaking down organic matter into simpler molecules.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In lab, you plan to carry out a calorimetry experiment to determine \(\Delta_{\mathrm{r}} H\) for the exothermic reaction of \(\mathrm{Ca}(\mathrm{OH})_{2}(\mathrm{s})\) and \(\mathrm{HCl}(\mathrm{aq}) .\) Predict how each of the following will affect the calculated value of \(\Delta_{\mathrm{r}} H\). (The value calculated for \(\Delta_{\mathrm{r}} H\) for this reaction is a negative value so choose your answer from the following: \(\Delta_{r} H\) will be too low [that is, a larger negative value], \(\Delta_{\mathrm{r}} H\) will be unaffected, \(\Delta_{\mathrm{r}} H\) will be too high \([\) that is, a smaller negative value. \(]\) )(a) You spill a little bit of the \(\mathrm{Ca}(\mathrm{OH})_{2}\) on the benchtop before adding it to the calorimeter. (b) Because of a miscalculation, you add an excess of HCl to the measured amount of \(\mathrm{Ca}(\mathrm{OH})_{2}\) in the calorimeter. (c) \(\mathrm{Ca}(\mathrm{OH})_{2}\) readily absorbs water from the air. The \(\mathrm{Ca}(\mathrm{OH})_{2}\) sample you weighed had been exposed to the air prior to weighing and had absorbed some water. (d) After weighing out \(\mathrm{Ca}(\mathrm{OH})_{2},\) the sample sat in an open beaker and absorbed water. (e) You delay too long in recording the final temperature. (f) The insulation in your coffee-cup calorimeter was poor, so some energy as heat was lost to the surroundings during the experiment. (g) You have ignored the fact that energy as heat also raised the temperature of the stirrer and the thermometer in your system.

A 237 -g piece of molybdenum, initially at \(100.0^{\circ} \mathrm{C},\) was dropped into \(244 \mathrm{g}\) of water at \(10.0^{\circ} \mathrm{C} .\) When the system came to thermal equilibrium, the temperature was \(15.3^{\circ} \mathrm{C} .\) What is the specific heat capacity of molybdenum?

You are attending summer school and living in a very old dormitory. The day is oppressively hot, there is no air-conditioner, and you can't open the windows of your room. There is a refrigerator in the room, however. In a stroke of genius, you open the door of the refrigerator, and cool air cascades out. The relief does not last long, though. Soon the refrigerator motor and condenser begin to run, and not long thereafter the room is hotter than it was before. Why did the room warm up?

Insoluble \(\mathrm{PbBr}_{2}(\mathrm{s})\) precipitates when solutions of \(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq})\) and \(\mathrm{NaBr}(\mathrm{aq})\) are mixed. \(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq})+2 \mathrm{NaBr}(\mathrm{aq}) \rightarrow \mathrm{PbBr}_{2}(\mathrm{s})+2 \mathrm{NaNO}_{3}(\mathrm{aq})\) $$ \Delta_{\mathrm{r}} H^{\circ}=? $$ To measure the enthalpy change, \(200 .\) mL of \(0.75 \mathrm{M}\) \(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq})\) and \(200 . \mathrm{mL}\) of \(1.5 \mathrm{M} \mathrm{NaBr}(\mathrm{aq})\) are mixed in a coffee-cup calorimeter. The temperature of the mixture rises by \(2.44^{\circ} \mathrm{C} .\) Calculate the enthalpy change for the precipitation of \(\mathrm{PbBr}_{2}(\mathrm{s}),\) in \(\mathrm{k} \mathrm{J} / \mathrm{mol}\). (Assume the density of the solution is \(1.0 \mathrm{g} / \mathrm{mL},\) and its specific heat capacity is \(4.2 \mathrm{J} / \mathrm{g} \cdot \mathrm{K}\).

You should use care when dissolving \(\mathrm{H}_{2} \mathrm{SO}_{4}\) in water because the process is highly exothermic. To measure the enthalpy change, \(5.2 \mathrm{g}\) of concentrated \(\mathrm{H}_{2} \mathrm{SO}_{4}(\ell)\) was added (with stirring) to 135 g of water in a coffee-cup calorimeter. This resulted in an increase in temperature from \(20.2^{\circ} \mathrm{C}\) to \(28.8^{\circ} \mathrm{C} .\) Calculate the enthalpy change for the process \(\mathrm{H}_{2} \mathrm{SO}_{4}(\ell) \rightarrow \mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{aq}),\) in \(\mathrm{kJ} / \mathrm{mol}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free