Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Make the following conversions. In each case, tell whether the solution is acidic or basic. \(\mathbf{p} \mathbf{H}$$\quad$$\left[\mathbf{H}_{3} \mathbf{O}^{*}\right]\) (a) \(\quad\)______\(\quad 6.7 \times 10^{-10} \mathrm{M}\) (b) \(\quad\)______\(\quad2.2 \times 10^{-6} \mathrm{M}\) (c) 5.25\(\quad\)_____ (d) ______\(\quad2.5 \times 10^{-2} \mathrm{M}\)

Short Answer

Expert verified
(a) pH 9.17, basic; (b) pH 5.66, acidic; (c) [H3O+] = 5.62 × 10^-6 M, acidic; (d) pH 1.60, acidic.

Step by step solution

01

Understanding pH and Hydronium Ion Concentration

In chemistry, pH is a measure of the acidity or basicity of an aqueous solution. It is calculated using the formula: \[ \text{pH} = -\log[\text{H}_3\text{O}^+] \]where \([\text{H}_3\text{O}^+]\) is the hydronium ion concentration. A pH less than 7 is acidic, while a pH greater than 7 is basic.
02

Calculate pH for (a)

For (a), given the hydronium ion concentration \([\text{H}_3\text{O}^+] = 6.7 \times 10^{-10} \text{M}\), calculate the pH:\[\text{pH} = -\log(6.7 \times 10^{-10}) = 9.17\]Since the pH is greater than 7, the solution is basic.
03

Calculate pH for (b)

For (b), given the hydronium ion concentration \([\text{H}_3\text{O}^+] = 2.2 \times 10^{-6} \text{M}\), calculate the pH:\[\text{pH} = -\log(2.2 \times 10^{-6}) = 5.66\]Since the pH is less than 7, the solution is acidic.
04

Calculate Hydronium Ion Concentration for (c)

For (c), given \(\text{pH} = 5.25\), calculate \([\text{H}_3\text{O}^+]\):\[[\text{H}_3\text{O}^+] = 10^{-5.25} = 5.62 \times 10^{-6} \text{M}\]Since the pH is less than 7, the solution is acidic.
05

Calculate pH for (d)

For (d), given the hydronium ion concentration \([\text{H}_3\text{O}^+] = 2.5 \times 10^{-2} \text{M}\), calculate the pH:\[\text{pH} = -\log(2.5 \times 10^{-2}) = 1.60\]Since the pH is less than 7, the solution is acidic.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acid-Base Chemistry
Understanding whether a solution is acidic or basic is central to acid-base chemistry. At the heart of this concept is the pH scale, which is a numeric scale used to specify the acidity or basicity of an aqueous solution.
A pH value is a simple way to measure the activity of hydrogen ions in a solution. If a solution has a pH less than 7, it is acidic, meaning it has more hydrogen ions ( [H^+ ]) than hydroxide ions ( [OH^- ]). Conversely, a pH greater than 7 indicates a basic solution, where hydroxide ions outnumber hydrogen ions.
  • An acidic solution has a higher concentration of hydronium ions (H3O+).
  • A basic solution has a lower concentration of hydronium ions compared to pure water.
  • Neutral solutions, like pure water, have a pH of 7.
This concept is fundamental in chemical reactions, biological systems, and industrial processes, as it influences how substances interact and behave.
Hydronium Ion Concentration
The concentration of hydronium ions ([H_3O^+]) in a solution directly influences its acidity or basicity. The hydronium ion is a water molecule with an extra hydrogen ion, commonly formed when an acid is dissolved in water.
Hydronium ion concentration can be derived from or used to calculate pH values, establishing a clear relationship between them. For example, using the formula:\[ [\text{H}_3\text{O}^+] = 10^{-\text{pH}} \]
This formula shows how to reverse the pH calculation to find [H_3O^+] from a known pH value.
  • Higher concentrations of hydronium ions result in a lower pH, meaning the solution is more acidic.
  • Lower hydronium ion concentrations increase the pH, indicating a more basic solution.
  • This concentration is crucial in explaining why different solutions have different pH values.
Understanding hydronium ion concentration helps students link the molecular world to observable properties, like acidity.
Logarithmic Function in Chemistry
In chemistry, the logarithmic function plays a crucial role in simplifying calculations related to acidity and basicity. The pH scale is logarithmic, meaning each whole number change in pH represents a tenfold change in hydronium ion concentration.
This can be expressed mathematically as:\[ \text{pH} = -\log[\text{H}_3\text{O}^+] \]
This formula shows that when the hydronium concentration changes by a factor of ten, the pH changes by 1. The negative sign in the function is essential because it converts smaller, more positive concentrations into larger, manageable pH numbers.
  • This property makes the logarithmic function valuable as it compresses a vast range of hydrogen ion activities into a convenient scale.
  • This function aids in understanding non-linear relationships in chemistry.
  • The use of a base-10 logarithm is practical for simplifying the multiplicative relationship between ion concentrations and their observed pH values.
Grasping the use of logarithms helps students better understand how dramatically small changes in ion concentration can affect pH and consequently the behavior of the solution.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

\(A A .000-g\) sample containing \(K C l\) and \(K C 1 O_{4}\) was dis. solved in sufficient water to give \(250.00 \mathrm{mL}\) of solution. A \(50.00-\mathrm{mL}\) portion of the solution required \(41.00 \mathrm{mL}\) of \(0.0750 \mathrm{M} \mathrm{AgNO}_{3}\) in a Mohr titration (page 187 ). Next, a \(25.00-\mathrm{mL}\), portion of the original solution was treated with \(\mathrm{V}_{2}\left(\mathrm{SO}_{4}\right)_{3}\) to reduce the perchlorate ion to chloride, \(8 \mathrm{V}^{3+}(\mathrm{aq})+\mathrm{ClO}_{4}^{-}(\mathrm{aq})+12 \mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow\) $$ \mathrm{Cl}^{-}(\mathrm{aq})+8 \mathrm{VO}^{2+}(\mathrm{aq})+8 \mathrm{H}_{3} \mathrm{O}^{+}(\mathrm{aq}) $$ and the resulting solution was tirrated with AgNO, This titration required \(38.12 \mathrm{mL}\) of \(0.0750 \mathrm{M} \mathrm{AgNO}_{3} .\) What is the mass percent of \(\mathrm{KCl}\) and \(\mathrm{KClO}_{4}\) in the mixture?

What is the mass of solute, in grams, in 125 mL. of a \(1.023 \times 10^{-3} \mathrm{M}\) solution of \(\mathrm{Na}_{3} \mathrm{PO}_{4} ?\) What is the molar concentration of the \(\mathrm{Na}^{+}\) and \(\mathrm{PO}_{4}^{3-}\) ion?

A pesticide contains thallium(I) sulfate, \(\mathrm{TI}_{2} \mathrm{SO}_{4}\). Dissolving a \(10.20-\mathrm{g}\) sample of impure pesticide in water and adding sodium iodide precipitates \(0.1964 \mathrm{g}\) of thallium(I) iodide, TII. $$ \mathrm{TI}_{2} \mathrm{SO}_{4}(\mathrm{aq})+2 \mathrm{NaI}(\mathrm{aq}) \rightarrow 2 \mathrm{TII}(\mathrm{s})+\mathrm{Na}_{2} \mathrm{SO}_{4}(\mathrm{aq}) $$ What is the mass percent of \(\mathrm{TI}_{2} \mathrm{SO}_{4}\) in the original \(10.20-\mathrm{g}\) sample?

You have a mixture of oxalic acid, \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4},\) and another solid that does not react with sodium hydroxide. If \(29.58 \mathrm{mL}\) of \(0.550 \mathrm{M} \mathrm{NaOH}\) is required to titrate the oxalic acid in the 4.554 -g sample to the second equivalence point, what is the mass percent of oxalic acid in the mixture? Oxalic acid and NaOH react according to the equation \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}(\mathrm{aq})+2 \mathrm{NaOH}(\mathrm{aq}) \rightarrow\) $$ \mathrm{Na}_{2} \mathrm{C}_{2} \mathrm{O}_{4}(\mathrm{aq})+2 \mathrm{H}_{2} \mathrm{O}(\ell) $$

If 38.55 mL of \(\mathrm{HCl}\) is required to titrate \(2.150 \mathrm{g}\) of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) according to the following equation, what is the concentration \((\mathrm{mol} / \mathrm{L})\) of the HCl solution? \(\mathrm{Na}_{2} \mathrm{CO}_{3}(\mathrm{aq})+2 \mathrm{HCl}(\mathrm{aq}) \rightarrow\) \(2 \mathrm{NaCl}(\mathrm{aq})+\mathrm{CO}_{2}(\mathrm{g})+\mathrm{H}_{2} \mathrm{O}(\ell)\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free