Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Make the following conversions. In each case, tell whether the solution is acidic or basic. \(\mathbf{p} \mathbf{H}$$\quad$$\left[\mathbf{H}_{3} \mathbf{O}^{*}\right]\) (a) 1.00\(\quad\)______ (b) 10.50\(\quad\)______ (c) ______\(\quad1.3 \times 10^{-3} \mathrm{M}\) (d) ______\(\quad2.3 \times 10^{-8} \mathrm{M}\)

Short Answer

Expert verified
(a) 0.1 M, acidic; (b) \(3.16 \times 10^{-11}\) M, basic; (c) pH 2.89, acidic; (d) pH 7.64, basic.

Step by step solution

01

Understanding the pH and Hydrogen Ion Concentration Relationship

The pH of a solution is related to the concentration of hydronium ions, \([H_3O^+]\), by the equation \[pH = -\log_{10}[H_3O^+]\]. This tells us that a low pH corresponds to a high concentration of \([H_3O^+]\), while a high pH corresponds to a low concentration.
02

Converting pH 1.00 to Hydronium Ion Concentration

For pH 1.00, use the formula \[pH = -\log_{10}[H_3O^+]\]. Solving for \([H_3O^+]\), we have \[1 = -\log_{10}[H_3O^+]\]. Therefore, \([H_3O^+] = 10^{-1} = 0.1 \text{ M}\). Since pH 1.00 is less than 7, this solution is acidic.
03

Converting pH 10.50 to Hydronium Ion Concentration

For pH 10.50, we apply the same formula: \[10.50 = -\log_{10}[H_3O^+]\]. Thus, \([H_3O^+] = 10^{-10.50} \approx 3.16 \times 10^{-11} \text{ M}\). Since pH 10.50 is greater than 7, this solution is basic.
04

Finding pH From Hydronium Ion Concentration 1.3 x 10^{-3} M

Given \([H_3O^+] = 1.3 \times 10^{-3} \text{ M}\), find pH using the formula \[pH = -\log_{10}(1.3 \times 10^{-3})\]. Calculating, \[-\log_{10}(1.3) - (-3) \approx 2.89\]. Since 2.89 is less than 7, the solution is acidic.
05

Finding pH From Hydronium Ion Concentration 2.3 x 10^{-8} M

Given \([H_3O^+] = 2.3 \times 10^{-8} \text{ M}\), find pH using the formula \[pH = -\log_{10}(2.3 \times 10^{-8})\]. Calculating, \[-\log_{10}(2.3) - (-8) \approx 7.64\]. Since 7.64 is greater than 7, the solution is basic.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hydronium Ion Concentration
The hydronium ion concentration is a measure of the acidity or alkalinity of a solution. When we discuss \([H_3O^+]\), we are referring to the concentration of hydronium ions present in the solution. A higher concentration of \([H_3O^+]\) indicates a more acidic solution, while a lower concentration suggests the solution is more basic.
Understanding this concept is crucial to grasping pH-related calculations effectively. Hydronium ions are formed when hydrogen ions, \( H^+ \), in a solution associate with water molecules, resulting in \( H_3O^+ \).
Knowing the hydronium concentration enables us to calculate the pH and thereby determine the nature of the solution - either acidic or basic.
Acidic and Basic Solutions
Acidic and basic solutions are essential concepts in chemistry related to pH value. A solution is classified as acidic if its pH value is less than 7. Neutral solutions have a pH of 7, typical of pure water, while solutions with a pH higher than 7 are considered basic or alkaline.
  • Acidic solutions have a high concentration of hydronium ions \([H_3O^+]\).
  • Basic solutions have a low concentration of hydronium ions and often a higher concentration of hydroxide ions \([OH^-]\).
Understanding whether a solution is acidic or basic is essential in various scientific fields like biology, chemistry, and environmental science. This knowledge helps in predicting the behavior of chemical reactions and processes in solutions.
Logarithmic Relationship of pH
The logarithmic scale of pH helps us manage the vast range of hydronium ion concentrations found in different solutions.
The equation \( pH = -\log_{10}[H_3O^+] \) defines this logarithmic relationship, allowing us to convert the ion concentration into a simpler scale of pH. This scale ranges from 0-14, providing an accessible way to read and understand acidity or basicity levels.
Let's break it down a bit:
  • A small change in pH represents a tenfold change in the hydronium ion concentration because of the logarithmic nature.
  • A decrease of 1 pH unit signifies the hydronium ion concentration increased by a factor of 10.
This relationship underscores the sensitivity of the pH scale and highlights why careful measurement and calculationare crucial in studies related to chemistry and biology.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What volume of \(0.123 \mathrm{M} \mathrm{NaOH},\) in milliliters, contains \(25.0 \mathrm{g}\) of \(\mathrm{NaOH} ?\)

In the photographic developing process, silver bromide is dissolved by adding sodium thiosulfate. \(\mathrm{AgBr}(\mathrm{s})+2 \mathrm{Na}_{2} \mathrm{S}_{2} \mathrm{O}_{3}(\mathrm{aq}) \rightarrow\) $$ \mathrm{Na}_{3} \mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}\right)_{2}(\mathrm{aq})+\mathrm{NaBr}(\mathrm{aq}) $$ If you want to dissolve \(0.225 \mathrm{g}\) of \(\mathrm{AgBr}\), what volume of \(0.0138 \mathrm{M} \mathrm{Na}_{2} \mathrm{S}_{2} \mathrm{O}_{3},\) in milliliters, should be used? (IMAGE CANNOT COPY)

What volume of \(0.955 \mathrm{M}\) HCl, in milliliters, is required to titrate \(2.152 \mathrm{g}\) of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) to the equivalence point? \(\mathrm{Na}_{2} \mathrm{CO}_{3}(\mathrm{aq})+2 \mathrm{HCl}(\mathrm{aq}) \rightarrow\) $$ \mathrm{H}_{2} \mathrm{O}(\ell)+\mathrm{CO}_{2}(\mathrm{g})+2 \mathrm{NaCl}(\mathrm{aq}) $$

A Phosphate in urine can be determined by spectrophotometry. After removing protein from the sample, it is treated with a molybdenum compound to give, ultimately, a deep blue polymolybdate. The absorbance of the blue polymolybdate can be measured at \(650 \mathrm{nm}\) and is directly related to the urine phosphate concentration. A 24 -hour urine sample was collected from a patient; the volume of urine was 1122 mL. The phosphate in a \(1.00 \mathrm{mL}\), portion of the urine sample was converted to the blue polymolybdate and diluted to \(50.00 \mathrm{mL} .\) A calibration curve was prepared using phosphate-containing solutions. (Concentrations are reported in grams of phosphorus (P) per liter of solution.) $$\begin{array}{lc} \text { Solution (mass P/L) } & \begin{array}{c} \text { Absorbance at } 650 \mathrm{nm} \\ \text { in a } 1.0-\mathrm{cm} \text { cell } \end{array} \\ \hline 1.00 \times 10^{-6} \mathrm{g} & 0.230 \\ 2.00 \times 10^{-6} \mathrm{g} & 0.436 \\ 3.00 \times 10^{-6} \mathrm{g} & 0.638 \\ 4.00 \times 10^{-6} \mathrm{g} & 0.848 \\ \text { Urine sample } & 0.518 \\ \hline \end{array}$$ (a) What are the slope and intercept of the calibration curve? (b) What is the mass of phosphorus per liter of urine? (c) What mass of phosphate did the patient excrete in the one-day period?

A You place \(2.56 \mathrm{g}\) of \(\mathrm{CaCO}_{3}\) in a beaker containing \(250 .\) mL of \(0.125 \mathrm{M} \mathrm{HCl}\). When the reaction has ceased, does any calcium carbonate remain? What mass of \(\mathrm{CaCl}_{2}\) can be produced? \(\mathrm{CaCO}_{3}(\mathrm{s})+2 \mathrm{HCl}(\mathrm{aq}) \rightarrow\) $$ \mathrm{CaCl}_{2}(\mathrm{aq})+\mathrm{CO}_{2}(\mathrm{g})+\mathrm{H}_{2} \mathrm{O}(\ell) $$

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free