Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Write two chemical equations, one in which \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) is a Bronsted acid (in reaction with the carbonate ion, \(\left.\mathrm{CO}_{3}^{2-}\right),\) and a second in which \(\mathrm{HPO}_{4}^{2-}\) is a Bronsted base (in reaction with acetic acid, \(\mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H}\) ).

Short Answer

Expert verified
H2PO4- reacts with CO3^2- to form HPO4^2- and HCO3-. HPO4^2- reacts with CH3CO2H to form H2PO4- and CH3CO2-.

Step by step solution

01

Identify the reaction for H2PO4- as a Bronsted acid

Bronsted acids donate protons (H+ ions). The dihydrogen phosphate ion, \( \mathrm{H}_2\mathrm{PO}_4^{-}\), can donate a hydrogen ion to the carbonate ion, \( \mathrm{CO}_3^{2-} \). Thus, the Bronsted acid reaction is:\[ \mathrm{H}_2\mathrm{PO}_4^{-} + \mathrm{CO}_3^{2-} \rightarrow \mathrm{HPO}_4^{2-} + \mathrm{HCO}_3^{-} \]
02

Identify the reaction for HPO4^2- as a Bronsted base

Bronsted bases accept protons. The hydrogen phosphate ion, \( \mathrm{HPO}_4^{2-} \), can accept a hydrogen ion from acetic acid, \( \mathrm{CH}_3\mathrm{CO}_2\mathrm{H} \). Thus, the Bronsted base reaction is:\[ \mathrm{HPO}_4^{2-} + \mathrm{CH}_3\mathrm{CO}_2\mathrm{H} \rightarrow \mathrm{H}_2\mathrm{PO}_4^{-} + \mathrm{CH}_3\mathrm{CO}_2^{-} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acid-Base Reactions
Understanding acid-base reactions is crucial in chemistry, especially when dealing with different ions. According to the Bronsted-Lowry theory, acids are substances that can donate protons (i.e., hydrogen ions, H extsuperscript{+}), while bases are those that can accept these protons. This concept is essential for identifying the roles of various substances in chemical reactions.
In the given problem, dihydrogen phosphate ion (\(\mathrm{H}_2\mathrm{PO}_4^{-}\)) acts as a Bronsted acid because it donates a proton to the carbonate ion (\(\mathrm{CO}_3^{2-}\)), forming hydrogen carbonate (\(\mathrm{HCO}_3^{-}\)). The balanced reaction is:
  • \(\mathrm{H}_2\mathrm{PO}_4^{-} + \mathrm{CO}_3^{2-} \rightarrow \mathrm{HPO}_4^{2-} + \mathrm{HCO}_3^{-}\)
This showcases a typical acid-base reaction where the acid loses a proton, forming a conjugate base.
On the flip side, hydrogen phosphate ion (\(\mathrm{HPO}_4^{2-}\)) acts as a Bronsted base when it accepts a proton from acetic acid (\(\mathrm{CH}_3\mathrm{CO}_2\mathrm{H}\)), forming dihydrogen phosphate (\(\mathrm{H}_2\mathrm{PO}_4^{-}\)) and acetate ion (\(\mathrm{CH}_3\mathrm{CO}_2^{-}\)).
  • \(\mathrm{HPO}_4^{2-} + \mathrm{CH}_3\mathrm{CO}_2\mathrm{H} \rightarrow \mathrm{H}_2\mathrm{PO}_4^{-} + \mathrm{CH}_3\mathrm{CO}_2^{-}\)
This reaction illustrates the classic action of a base gaining a proton to form a conjugate acid.
Dihydrogen Phosphate
Dihydrogen phosphate, or \(\mathrm{H}_2\mathrm{PO}_4^{-}\), is an anion with diverse roles in biological and chemical systems. It is a polyatomic ion, formed from a combination of hydrogen, phosphorus, and oxygen.
This ion plays a noteworthy role as a Bronsted acid. In its role as an acid, \(\mathrm{H}_2\mathrm{PO}_4^{-}\) can donate a hydrogen ion to a base, leading to the formation of hydrogen phosphate (\(\mathrm{HPO}_4^{2-}\)). This specific conversion exemplifies its ability to act within buffer solutions.
  • Helps maintain pH levels in solutions by acting as an acid or base when necessary.
  • Used in biological systems as part of energy transfers and enzymatic reactions.
Its dualistic nature, being able to act as an acid or base, makes \(\mathrm{H}_2\mathrm{PO}_4^{-}\) a vital component in various chemical and biological settings.
Carbonate Ion
The carbonate ion, or \(\mathrm{CO}_3^{2-}\), is an important polyatomic ion in both the geological and biological spheres. It consists of one carbon atom centrally bonded to three oxygen atoms, creating a trigonal planar shape.
In the context of Bronsted-Lowry acid-base reactions, \(\mathrm{CO}_3^{2-}\) behaves predominantly as a base because it has the tendency to accept protons. When reacting with a Bronsted acid like dihydrogen phosphate (\(\mathrm{H}_2\mathrm{PO}_4^{-}\)), it forms the hydrogen carbonate ion (\(\mathrm{HCO}_3^{-}\)).
  • In nature, carbonate ions are found in mineral deposits and are a part of the Earth's carbon cycle.
  • They play a key role in buffering systems, helping to maintain consistent pH levels in environmental and physiological processes.
The flexibility of the carbonate ion to act in acid-base reactions enhances its significance, particularly in buffering environments and regulating acidity.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Balance the following equations, and then classify each as a precipitation, acid-base, or gas-forming reaction. Show states for the products (s, \(\ell, \mathrm{g},\) aq), and then balance the completed equation. Write the net ionic equation. (a) \(\mathrm{MnCl}_{2}(\mathrm{aq})+\mathrm{Na}_{2} \mathrm{S}(\mathrm{aq}) \rightarrow \mathrm{MnS}+\mathrm{NaCl}\) (b) \(\mathrm{K}_{2} \mathrm{CO}_{3}(\mathrm{aq})+\mathrm{ZnCl}_{2}(\mathrm{aq}) \rightarrow \mathrm{ZnCO}_{3}+\mathrm{KCl}\)

Identify each of the following substances as a likely oxidizing or reducing agent: \(\mathrm{HNO}_{3}, \mathrm{Na}, \mathrm{Cl}_{2}, \mathrm{O}_{2} \mathrm{KMnO}_{4}\).

Balance the following equations, and then write the net ionic equation: (a) \(\mathrm{Zn}(\mathrm{s})+\mathrm{HCl}(\mathrm{aq}) \rightarrow \mathrm{H}_{2}(\mathrm{g})+\mathrm{ZnCl}_{2}(\mathrm{aq})\) (b) \(\mathrm{Mg}(\mathrm{OH})_{2}(\mathrm{s})+\mathrm{HCl}(\mathrm{aq}) \rightarrow \mathrm{MgCl}_{2}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell)\) (c) \(\mathrm{HNO}_{3}(\mathrm{aq})+\mathrm{CaCO}_{3}(\mathrm{s}) \rightarrow \mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell)+\mathrm{CO}_{2}(\mathrm{g})\) (d) \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{S}(\mathrm{aq})+\mathrm{FeCl}_{2}(\mathrm{aq}) \rightarrow \mathrm{NH}_{4} \mathrm{Cl}(\mathrm{aq})+\mathrm{FeS}(\mathrm{s})\)

Write the net ionic equation and identify the spectator ion or ions in the reaction of nitric acid and magnesium hydroxide. What type of reaction is this? $$\begin{array}{rl} 2 \mathrm{H}_{3} \mathrm{O}^{+}(\mathrm{aq})+2 \mathrm{NO}_{3}^{-}(\mathrm{aq})+\mathrm{Mg}(\mathrm{OH})_{2}(\mathrm{s}) & \rightarrow \\ 4 \mathrm{H}_{2} \mathrm{O}(\ell)+\mathrm{Mg}^{2+}(\mathrm{aq})+2 & \mathrm{NO}_{3}^{-}(\mathrm{aq}) \end{array}$$

Equal amounts of two acids- -HCl and HCO \(_{2} \mathrm{H}\) (formic acid) - are placed in solution. When equilibrium has been achieved, the HCl solution has a much greater electrical conductivity than the HCO,H solution. Which reaction is more product-favored at equilibrium? $$\begin{aligned}\mathrm{HCl}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) & \rightleftarrows \mathrm{H}_{3} \mathrm{O}^{+}(\mathrm{aq})+\mathrm{Cl}^{-}(\mathrm{aq}) \\\\\mathrm{HCO}_{2} \mathrm{H}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) & \rightleftarrows \mathrm{H}_{3} \mathrm{O}^{+}(\mathrm{aq})+\mathrm{HCO}_{2}^{-}(\mathrm{aq})\end{aligned}$$

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free