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Write two chemical equations, one that shows \(\mathrm{H}_{2} \mathrm{O}\) reacting (with HBr) as a Bronsted base and a second that shows \(\mathrm{H}_{2} \mathrm{O}\) reacting (with \(\mathrm{NH}_{3}\) ) as a Bronsted acid.

Short Answer

Expert verified
Water acts as a base with HBr and as an acid with NH3.

Step by step solution

01

Understanding Bronsted-Lowry Theory

The Bronsted-Lowry theory defines acids as proton (H+) donors and bases as proton (H+) acceptors. Water, therefore, can act either as an acid or a base depending on the substance it reacts with.
02

Identifying Water as a Base

When water \(\mathrm{H}_{2}\mathrm{O}\) acts as a base, it accepts a proton from an acid. In the case of hydrobromic acid (HBr), \(\mathrm{H}_{2}\mathrm{O}\) accepts a proton from HBr, forming hydronium ion \(\mathrm{H}_{3}\mathrm{O}^{+}\) and bromide ion \(\mathrm{Br}^{-}\): \\[ \\mathrm{H}_{2}\mathrm{O} + \mathrm{HBr} \rightarrow \mathrm{H}_{3}\mathrm{O}^{+} + \mathrm{Br}^{-} \]
03

Identifying Water as an Acid

When water \(\mathrm{H}_{2}\mathrm{O}\) acts as an acid, it donates a proton to a base. In the case with ammonia (NH3), \(\mathrm{H}_{2}\mathrm{O}\) donates a proton to NH3, forming hydroxide ion \(\mathrm{OH}^{-}\) and ammonium ion \(\mathrm{NH}_{4}^{+}\): \\[ \\mathrm{H}_{2}\mathrm{O} + \mathrm{NH}_{3} \rightarrow \mathrm{OH}^{-} + \mathrm{NH}_{4}^{+} \]
04

Review of Reactions

Based on the equations provided, water can be seen acting as both a Bronsted base and a Bronsted acid. With HBr, it accepts a proton, and with NH3, it donates a proton.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Water as Bronsted Base
Water, a versatile substance in chemistry, has the ability to act as either an acid or a base, thanks to the Bronsted-Lowry theory. As a Bronsted base, water accepts protons (H extsuperscript{+}) from acids. This attribute is showcased when water interacts with hydrobromic acid (HBr).

In this reaction, water (\(\mathrm{H}_{2}\mathrm{O}\)) acts as a base by accepting a proton from the acid \(\mathrm{HBr}\). This leads to the formation of a hydronium ion \(\mathrm{H}_{3}\mathrm{O}^{+}\) and a bromide ion \(\mathrm{Br}^{-}\).

The chemical equation for this reaction is:

\[ \mathrm{H}_{2}\mathrm{O} + \mathrm{HBr} \rightarrow \mathrm{H}_{3}\mathrm{O}^{+} + \mathrm{Br}^{-} \]

Key points to remember:
  • The base (water) must have lone pair electrons to accept the proton.
  • The acid (HBr) donates the proton to the base.
  • This results in a conjugate acid-base pair: \(\mathrm{H}_{3}\mathrm{O}^{+}\) (conjugate acid of water) and \(\mathrm{Br}^{-}\) (conjugate base of HBr).
Water as Bronsted Acid
Water can also act as a Bronsted acid, which means it can donate a proton (H extsuperscript{+}) to a base. In the context of its reaction with ammonia \(\mathrm{NH}_{3}\), water exhibits its acidic property.

When water meets ammonia, it donates a proton to \(\mathrm{NH}_{3}\), transforming water into hydroxide \(\mathrm{OH}^{-}\) and ammonia into the ammonium ion \(\mathrm{NH}_{4}^{+}\).

Here's the chemical equation for clarity:

\[ \mathrm{H}_{2}\mathrm{O} + \mathrm{NH}_{3} \rightarrow \mathrm{OH}^{-} + \mathrm{NH}_{4}^{+} \]

Important highlights:
  • Ammonia acts as the base by accepting the proton.
  • Water, in donating a proton, becomes the conjugate base, \(\mathrm{OH}^{-}\).
  • The product \(\mathrm{NH}_{4}^{+}\) is the conjugate acid of ammonia.
Chemical Equations
Chemical equations are crucial in understanding and illustrating chemical reactions. They tell us exactly what substances are involved and how they transform during the reaction. When depicting reactions such as water acting as a Bronsted base or acid, these equations become incredibly informative.

A balanced chemical equation ensures that the number of atoms for each element is the same on both sides of the equation, preserving mass and charge. Let's explore the previously discussed reactions involving water:

For water acting as a base:

\[ \mathrm{H}_{2}\mathrm{O} + \mathrm{HBr} \rightarrow \mathrm{H}_{3}\mathrm{O}^{+} + \mathrm{Br}^{-} \]

And for water acting as an acid:

\[ \mathrm{H}_{2}\mathrm{O} + \mathrm{NH}_{3} \rightarrow \mathrm{OH}^{-} + \mathrm{NH}_{4}^{+} \]

  • Each equation illustrates the transfer of protons, a central theme in Bronsted-Lowry theory.
  • Visualizing these equations helps us understand the role of each substance: proton donor or acceptor.
  • Practicing writing and balancing chemical equations is key to mastering chemical reactions.
Understanding how to write and balance chemical equations is essential to grasp the dynamic nature of chemical reactions and correctly predict the outcome of reactions!

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Most popular questions from this chapter

Two solutions were prepared, one containing 0.10 mol of boric acid \(\left(\mathrm{H}_{3} \mathrm{BO}_{3}\right)\) in \(200 \mathrm{mL}\) and the second containing 0.10 mol phosphoric acid \(\left(\mathrm{H}_{3} \mathrm{PO}_{4}\right)\) in \(200 \mathrm{mL}\). Both were weak conductors of electricity, but the \(\mathrm{H}_{3} \mathrm{PO}_{4}\) solution was a noticeably stronger conductor. Write equations to describe the equilibrium in each solution, and explain the observed difference in conductivity.

Balance each of the following equations, and then write the net ionic equation. Show states for all reactants and products (s, \(\ell, \mathrm{g}, \text { aq })\). (a) the reaction of sodium hydroxide and iron(II) chloride to give iron(II) hydroxide and sodium chloride (b) the reaction of barium chloride with sodium carbonate to give barium carbonate and sodium chloride (c) the reaction of ammonia with phosphoric acid

What is an electrolyte? How can you differentiate experimentally between a weak electrolyte and a strong electrolyte? Give an example of each.

Suppose you wish to prepare a sample of magnesium chloride. One way to do this is to use an acid-base reaction, the reaction of magnesium hydroxide with hydrochloric acid. $$\mathrm{Mg}(\mathrm{OH})_{2}(\mathrm{s})+2 \mathrm{HCl}(\mathrm{aq}) \rightarrow \mathrm{MgCl}_{2}(\mathrm{aq})+2 \mathrm{H}_{2} \mathrm{O}(\ell)$$ When the reaction is complete, evaporating the water will give solid magnesium chloride. Suggest at least one other way to prepare \(\mathrm{MgCl}_{2}\).

Balance the following equations, and name each reactant and product: (a) \(\mathrm{SF}_{4}(\mathrm{g})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow \mathrm{SO}_{2}(\mathrm{g})+\mathrm{HF}(\ell)\) (b) \(\mathrm{NH}_{3}(\mathrm{aq})+\mathrm{O}_{2}(\mathrm{aq}) \rightarrow \mathrm{NO}(\mathrm{g})+\mathrm{H}_{2} \mathrm{O}(\ell)\) (c) \(\mathrm{BF}_{3}(\mathrm{g})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow \mathrm{HF}(\mathrm{aq})+\mathrm{H}_{3} \mathrm{BO}_{3}(\mathrm{aq})\)

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