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Give the symbol, including the correct charge, for each of the following ions: (a) permanganate ion (b) nitrite ion (c) dihydrogen phosphate ion (d) ammonium ion (e) phosphate ion (f) sulfite ion

Short Answer

Expert verified
(a) \( \text{MnO}_4^- \), (b) \( \text{NO}_2^- \), (c) \( \text{H}_2\text{PO}_4^- \), (d) \( \text{NH}_4^+ \), (e) \( \text{PO}_4^{3-} \), (f) \( \text{SO}_3^{2-} \)

Step by step solution

01

Identify the Permanganate Ion

The permanganate ion is known in chemistry as a compound containing manganese in a specific oxidation state. The symbol for the permanganate ion is written as \( \text{MnO}_4^- \). It has a charge of -1.
02

Identify the Nitrite Ion

The nitrite ion consists of nitrogen and oxygen in a specific arrangement. The symbol for the nitrite ion is \( \text{NO}_2^- \), with a charge of -1.
03

Identify the Dihydrogen Phosphate Ion

The dihydrogen phosphate ion has hydrogen atoms combined with a phosphate group. The correct symbol is \( \text{H}_2\text{PO}_4^- \) and carries a charge of -1.
04

Identify the Ammonium Ion

Commonly found in many chemical reactions, the ammonium ion is one of the few positively charged ions listed. It is represented as \( \text{NH}_4^+ \), with a charge of +1.
05

Identify the Phosphate Ion

The phosphate ion is derived from phosphoric acid, releasing all hydrogen ions in the reaction. It is represented by \( \text{PO}_4^{3-} \) and carries a charge of -3.
06

Identify the Sulfite Ion

The sulfite ion is a result of the reduction of sulfur in sulfurous acid. It is denoted as \( \text{SO}_3^{2-} \), with a charge of -2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation State
The oxidation state is an essential concept in chemistry.It helps indicate the degree of electron deficiency or excess in an atom.In ions, this becomes crucial to understand their behavior in reactions. Generally, the oxidation state reflects the charge of the ion. For example, in the permanganate ion (\[\text{MnO}_4^-\]), manganese has an oxidation state of +7.This means that manganese has lost 7 electrons compared to its neutral state. Understanding oxidation states assists in predicting how an ion will combine with others and form compounds. In the sulfite ion (\[\text{SO}_3^{2-}\]), sulfur has an oxidation number of +4, which informs us about its electron arrangement in bonding.
Chemical Formulas
Chemical formulas are like blueprints of chemical species.They convey the type and number of each atom present in a molecule or ion. For ions, these formulas also help represent the charge associated with them. For instance, the formula for the ammonium ion is \[\text{NH}_4^+\]. This tells us that it consists of one nitrogen atom covalently bonded to four hydrogen atoms and carries a positive charge.In contrast, the formula for phosphate ion is \[\text{PO}_4^{3-}\], indicating the presence of one phosphorus atom surrounded by four oxygen atoms, bearing a charge of -3. A solid grasp on writing and interpreting these chemical formulas aids in comprehending molecular composition and reactions.
Ionic Charges
Ionic charges provide vital insights into chemical species.The charge of an ion is a result of the loss or gain of electrons. A positive charge indicates fewer electrons than protons, seen in cations like the ammonium ion (\[\text{NH}_4^+\]). Conversely, a negative charge signifies more electrons than protons, exemplified by anions such as the nitrite ion (\[\text{NO}_2^-\]). These charges are crucial for understanding chemical interactions. They dictate how ions combine to form salts and other compounds. The attraction between positive and negative charges in ions is what leads to ionic bonding. Handler rates these attractions and predicts the formation of new compounds.
Ions Identification
Identifying ions is a fundamental skill in chemistrystudents should master. This involves recognizing the specific composition and charge of an ion. Common practices include memorizing particular ions' names, formulas, and corresponding charges. For example, the dihydrogen phosphate ion is noted as \[\text{H}_2\text{PO}_4^-\] and carries a charge of -1.Understanding its structure reveals two hydrogen atoms linked to the phosphate base. Recognizing ions also involves familiarizing oneself with common ions encountered in chemistry labs. By doing so, students can easily identify ions in reactions, helping them predict outcomes. Identification of ions like the sulfate and sulfite (\[\text{SO}_3^{2-}\]) ions also reveals important insights into their chemical nature and usage.

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Most popular questions from this chapter

Zinc metal ( \(2.50 \mathrm{g}\) ) combines with \(9.70 \mathrm{g}\) of iodine to produce zinc iodide, \(\mathrm{Zn}_{x} \mathrm{I}_{y}\). What is the formula of this ionic compound?

Name each of the following ionic compounds: (a) \(\mathrm{K}_{2} \mathrm{S}\) (b) \(\cos 0_{4}\) (c) \(\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}\) (d) \(\mathrm{Ca}(\mathrm{ClO})_{2}\)

When analyzed, an unknown compound gave these experimental results: \(\mathbf{C}, 54.0 \% ; \mathbf{H}, \mathbf{6} .00 \% ;\) and \(\mathbf{O}, 40.0 \%\) Four different students used these values to calculate the empirical formulas shown here. Which answer is correct? Why did some students not get the correct answer? (a) \(\mathrm{C}_{4} \mathrm{H}_{5} \mathrm{O}_{2}\) (b) \(\mathrm{C}_{5} \mathrm{H}_{7} \mathrm{O}_{3}\) (c) \(\mathrm{C}_{7} \mathrm{H}_{10} \mathrm{O}_{4}\) (d) \(\mathrm{C}_{9} \mathrm{H}_{12} \mathrm{O}_{5}\)

Reviewing the periodic table. (a) Name the element in Group \(2 \mathrm{A}\) and the fifth period. (b) Name the element in the fifth period and Group \(4 B\). (c) Which element is in the second period in Group \(4 \mathrm{A} ?\) (d) Which element is in the fourth period in Group \(5 \mathrm{A} ?\) (e) Which halogen is in the fifth period? (f) Which alkaline earth element is in the third period? (g) Which noble gas element is in the fourth period? (h) Name the nonmetal in Group \(6 \mathrm{A}\) and the third period. (i) Name a metalloid in the fourth period.

Analysis of a 10.0 -g sample of apatite (a major component of tooth enamel) showed that it was made up of \(3.99 \mathrm{g} \mathrm{Ca}, 1.85 \mathrm{g} \mathrm{P}, 4.14 \mathrm{g} \mathrm{O},\) and \(0.020 \mathrm{g} \mathrm{H} .\) I ist these elements based on relative amounts (moles), from smallest to largest.

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