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Explain why benzenesulfonic acid is a Bronsted acid.

Short Answer

Expert verified
Benzenesulfonic acid donates a proton from its sulfonic group, defining it as a Bronsted acid.

Step by step solution

01

Definition of a Bronsted Acid

A Bronsted acid is a substance that can donate a proton (H⁺ ion) to another substance. The defining characteristic of a Bronsted acid is its ability to release a proton.
02

Structure of Benzenesulfonic Acid

Benzenesulfonic acid has a benzene ring attached to a sulfonic acid group (-SO₃H). The sulfonic acid group is what makes it acidic as it contains a hydrogen atom that can be released as a proton.
03

Proton Donation Mechanism

In benzenesulfonic acid, the hydrogen atom in the sulfonic acid group can dissociate, leaving behind a negatively charged sulfonate ion ( ext{SO}_3^−). This dissociation is the process of donating a proton, making it a Bronsted acid.
04

Stability of the Sulfonate Ion

After proton donation, the sulfonate ion is stabilized through resonance, where the negative charge is delocalized over the oxygen atoms. This stability encourages the release of the proton, reinforcing its nature as a Bronsted acid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proton Donation
In chemistry, proton donation is a fundamental concept for understanding acids and their behavior. A Bronsted acid is defined by its ability to donate a proton, which is essentially a hydrogen ion ( H^{+} ). During this process, the acid releases its proton to another molecule, referred to as the acceptor or base. This capability is what classifies a substance as a Bronsted acid.

To think about proton donation, consider it as a chemical "handoff" where the acid loses a hydrogen ion. The initial molecule from which the proton was released becomes a conjugate base. This is a core aspect of acid-base reactions and is essential for identifying acids and bases in chemistry.
  • Acid: Donates a proton (H⁺)
  • Base: Accepts a proton (H⁺)
  • Conjugate Base: The remainder of the acid following the donation of a proton
This simplicity in the exchange of the proton helps in understanding complex reactions and forms the basis for many biological and chemical processes.
Benzenesulfonic Acid
Benzenesulfonic acid is a unique compound characterized by its benzene ring bonded to a sulfonic acid group ( -SO_3H ). This chemical structure is important for its properties as a Bronsted acid.

The sulfonic acid group is the acidic functional group responsible for the acid's ability to donate protons. It consists of sulfur ( S ) atom double-bonded to two oxygen atoms and single-bonded to an -OH group. The -OH group has a hydrogen atom that is easily ionizable. This arrangement allows benzenesulfonic acid to release a hydrogen ion ( H^{+} ), thus acting as a Bronsted acid.
  • Chemical Structure: Benzene ring attached to -SO₃H
  • Acidic Group: Sulfonic acid ( -SO_3H )
  • Proton Donation: Ability to dissociate a hydrogen ion
The readiness to give away a proton is enhanced by the presence of the sulfonic acid group, making benzenesulfonic acid a strong acid.
Sulfonate Ion Stability
Once benzenesulfonic acid donates a proton, it transforms into a sulfonate ion ( -SO_3^− ). The stability of this sulfonate ion plays a crucial role in determining the propensity of the molecule to donate a proton.

The sulfonate ion is characterized by a negative charge that can be delocalized across the oxygen atoms through resonance. This phenomenon of resonance involves the spreading out of electron density over multiple atoms, which stabilizes the ion. This stability is key to understanding why sulfonic acids are such strong acids.
  • Charge Distribution: Negative charge delocalized over oxygen atoms
  • Resonance Stability: Provides extra stability to the sulfonate ion
  • Influence on Acid Strength: The stable ion makes proton donation more favorable
The more stable the resultant ion after proton donation, the more readily the acid will donate a proton. This is why benzenesulfonic acid, with its stable sulfonate ion, efficiently acts as a Bronsted acid.

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Most popular questions from this chapter

Which of the following common food additives would give a basic solution when dissolved in water? (a) \(\mathrm{NaNO}_{3}\) (used as a meat preservative) (b) \(\mathrm{NaC}_{6} \mathrm{H}_{5} \mathrm{CO}_{2}\) (sodium benzoate; used as a soft-drink preservative) (c) \(\mathrm{Na}_{2} \mathrm{HPO}_{4}\) (used as an emulsifier in the manufacture of pasteurized cheese)

Which should be the stronger acid, HOCN or HCN? Explain briefly. (In HOCN, the \(\mathrm{H}^{+}\) ion is attached to the \(\mathrm{O}\) atom of the \(\mathrm{OCN}^{-}\) ion.)

Several acids are listed here with their respective equilibrium constants. $$\begin{aligned} &\mathrm{HF}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightleftarrows \mathrm{H}_{3} \mathrm{O}^{+}(\mathrm{aq})+\mathrm{F}^{-}(\mathrm{aq})\\\ &K_{\mathrm{a}}=7.2 \times 10^{-4} \end{aligned}$$ $$\begin{aligned} &\mathrm{HPO}_{4}^{2-}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightleftarrows \mathrm{H}_{3} \mathrm{O}^{+}(\mathrm{aq})+\mathrm{PO}_{4}^{3-}(\mathrm{aq})\\\ &K_{\mathrm{a}}=3.6 \times 10^{-13} \end{aligned}$$ $$\begin{aligned} &\mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightleftarrows \mathrm{H}_{3} \mathrm{O}^{+}(\mathrm{aq})+\mathrm{CH}_{3} \mathrm{CO}_{2}^{-}(\mathrm{aq})\\\ &K_{\mathrm{a}}=1.8 \times 10^{-5} \end{aligned}$$ (a) Which is the strongest acid? Which is the weakest acid? (b) What is the conjugate base of the acid HF? (c) Which acid has the weakest conjugate base? (d) Which acid has the strongest conjugate base?

In each of the following acid-base reactions, identify the Bronsted acid and base on the left and their conjugate partners on the right. (a) \(\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{N}(\mathrm{aq})+\mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H}(\mathrm{aq}) \rightleftarrows\) \(\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{NH}^{+}(\mathrm{aq})+\mathrm{CH}_{3} \mathrm{CO}_{2}^{-}(\mathrm{aq})\) (b) \(\mathrm{N}_{2} \mathrm{H}_{4}(\mathrm{aq})+\mathrm{HSO}_{4}^{-}(\mathrm{aq}) \rightleftarrows\) \(\mathrm{N}_{2} \mathrm{H}_{5}^{+}(\mathrm{aq})+\mathrm{SO}_{4}^{2-}(\mathrm{aq})\) (c) \(\left[\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq}) \rightleftarrows\) \(\left[\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{OH}\right]^{2+}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell)\)

You prepare a 0.10 M solution of oxalic acid, \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4} .\) What molecules and ions exist in this solution? List them in order of decreasing concentration.

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