Chapter 17: Problem 57
Calculate the hydronium ion concentration and \(\mathrm{pH}\) in a \(0.20 \mathrm{M}\) solution of ammonium chloride, \(\mathrm{NH}_{4} \mathrm{Cl}\).
Short Answer
Expert verified
[H₃O⁺] for 0.20 M NH₄Cl is approximately calculated using Kₐ and then pH is found from \(-\log[H₃O⁺]\).
Step by step solution
01
Understand the Problem
We have a 0.20 M solution of ammonium chloride (NH₄Cl), which is a salt formed from a weak base (NH₄OH) and a strong acid (HCl). This solution will act as an acidic solution because NH₄⁺ can donate a proton to water, forming hydronium ions, which we need to calculate.
02
Write the Reaction Equation
NH₄Cl dissociates in water to produce NH₄⁺ ions. The ammonium ions then react with water to form hydronium ions:
NH₄⁺ + H₂O ⇌ NH₃ + H₃O⁺. This equilibrium reaction will help us determine the H₃O⁺ concentration.
03
Use the Equilibrium Expression
The equilibrium constant for the reaction is the ionization constant of NH₄⁺, represented as Kₐ. First, find Kₐ using the relation Kₐ = \( \dfrac{K_w}{K_b} \), where K_w is the ion-product constant for water \(1.0 \times 10^{-14} \) and K_b is the base ionization constant for NH₄OH. Use given or standard tables to find these constants.
04
Set Up the Equilibrium Table
Create a table showing initial concentrations (initially, [NH₄⁺] = 0.20 M and [H₃O⁺] = [NH₃] = 0), the change in concentrations, and equilibrium concentrations. Let 'x' be the change in concentration to form H₃O⁺ and NH₃. Therefore, equilibrium concentrations are [NH₄⁺] = 0.20 - x, [H₃O⁺] = x, and [NH₃] = x.
05
Solve the Equilibrium Equation
Using the Kₐ expression for NH₄⁺: \( Kₐ = \dfrac{[NH₃][H₃O⁺]}{[NH₄⁺]} \) Substitute the equilibrium concentrations into the expression: \( Kₐ = \dfrac{x^2}{0.20-x} \). Assuming 0.20-x ≈ 0.20 (because x is small), solve for x to find [H₃O⁺].
06
Calculate pH
Once the [H₃O⁺] is determined, use the formula for pH: \( ext{pH} = -\log[H₃O⁺] \). Evaluate the logarithm to find the pH of the solution.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Hydronium Ion Concentration
When working with solutions like ammonium chloride, it is crucial to calculate the hydronium ion concentration.
Ammonium chloride, with a concentration of 0.20 M, dissociates fully in water to form ammonium ions (NH₄⁺).
These ammonium ions can interact with water molecules to form hydronium ions (H₃O⁺).
This reaction can be represented as:
- NH₄⁺ + H₂O ⇌ NH₃ + H₃O⁺
Equilibrium Expression
An equilibrium expression helps quantify the relationship between the concentrations of reactants and products in a chemical reaction at equilibrium. For the reaction involving NH₄⁺ and water:
- NH₄⁺ + H₂O ⇌ NH₃ + H₃O⁺
- \[ Kₐ = \dfrac{[NH₃][H₃O⁺]}{[NH₄⁺]} \]
Ammonium Chloride Solution
Ammonium chloride (NH₄Cl) is a white crystalline solid that is highly soluble in water.
When dissolved, it dissociates into ammonium ions (NH₄⁺) and chloride ions (Cl⁻).
Ammonium chloride solutions tend to be acidic due to the weak base (NH₄OH) and strong acid (HCl) from which it originates.
The balanced dissociation equation in water is:
- NH₄Cl → NH₄⁺ + Cl⁻
Ionization Constant
The ionization constant, or Kₐ, is crucial when dealing with weak acids or bases and their salts like ammonium chloride. It represents the strength of the acid or base in a solution, showing how readily it donates protons. For NH₄⁺, you can find Kₐ using the formula:
- \[ Kₐ = \dfrac{K_w}{K_b} \]