Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The halogens form three stable, weak acids, HOX. $$\begin{array}{ll}\text { Acid } & \mathrm{pK}_{\mathrm{a}} \\\\\hline \mathrm{HOCl} & 7.46 \\\\\mathrm{HOBr} & 8.7 \\ \mathrm{HOI} & 10.6 \\\\\hline\end{array}$$ (a) Which is the strongest of these acids? (b) Explain why the acid strength changes as the halogen atom is changed.

Short Answer

Expert verified
(a) HOCl is the strongest acid. (b) The acid strength changes due to differences in electronegativity, with more electronegative halogens stabilizing the conjugate base more effectively.

Step by step solution

01

Understanding Acid Strength and pKa Values

The acid dissociation constant (\( K_a \)) measures an acid's strength; the smaller the \( pK_a \) value, the stronger the acid. This is because \( pK_a \) is the negative logarithm of \( K_a \), so a lower \( pK_a \) indicates a higher \( K_a \), meaning the acid ionizes more completely in water.
02

Compare pKa Values of HOX Acids

We are given the \( pK_a \) values: \(\mathrm{HOCl} = 7.46\), \(\mathrm{HOBr} = 8.7\), and \(\mathrm{HOI} = 10.6\). To determine which acid is the strongest, we compare the \( pK_a \) values. The acid with the lowest \( pK_a \) value is the strongest.
03

Identify the Strongest Acid

Among the acids, \(\mathrm{HOCl}\) has the smallest \( pK_a \) value of 7.46. Therefore, \(\mathrm{HOCl}\) is the strongest acid of the three.
04

Explain Acid Strength Differences

The strength of these acids changes with different halogen atoms due to differences in electronegativity and the stability of the conjugate base. A more electronegative central atom (halogen) stabilizes the conjugate base by drawing electron density away, thus allowing the acid to donate a proton more easily.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

pKa Values
The concept of pKa values is essential when discussing acid strength. A pKa value is derived from the acid dissociation constant (Ka). It represents the strength of an acid in a solution. The pKa is calculated as the negative logarithm (base 10) of the Ka, given by the formula:\[pK_a = -\log(K_a)\\]A lower pKa value indicates a stronger acid, meaning the acid more readily releases its proton in solution. In the case of the halogen acids, we observe pKa values as follows:
  • HOCl: 7.46
  • HOBr: 8.7
  • HOI: 10.6
Among these, HOCl has the lowest pKa value, making it the strongest acid. This is because it dissociates more in water, releasing more hydrogen ions.
Halogen Acids
Halogen acids are a group of binary acids composed of hydrogen, oxygen, and a halogen from Group 17 of the periodic table. In the case of the described acids, HOX (where X represents Cl, Br, or I), the strength varies notably. As we move down the halogen group in the periodic table — from chlorine to bromine to iodine — we observe changes in acid behavior.
  • HOCl is the strongest, reflecting chlorine's high electronegativity.
  • HOBr is weaker, followed by HOI, the weakest.
The variation in acid strength among halogen acids is partly due to the varying electronegativities of the halogen atoms. Chlorine's greater electronegativity helps stabilize the conjugate base after proton donation, making HOCl a stronger acid compared to the others. This behavior shows how the nature of halogen acids is influenced by their respective halogen components.
Acid Dissociation Constant
The acid dissociation constant, denoted Ka, is a vital measure describing an acid's ability to donate protons in a given environment or solution. It represents the equilibrium constant for the dissociation of an acid into its ions. The larger the value of Ka, the more an acid dissociates completely, which demonstrates its strength.In mathematical terms:\[K_a = \frac{[H^+][A^-]}{[HA]}\\]Here, \([H^+]\) and \([A^-]\) are the concentrations of the hydrogen ion and conjugate base, while \([HA]\) is the concentration of the undissociated acid. Therefore, a higher Ka value translates to a stronger acid. When comparing halogen acids like HOCl, HOBr, and HOI, analyzing their Ka and thus their pKa values helps predict which will dissociate more readily in water, which is a significant factor in understanding acid strength.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

About this time, you may be wishing you had an aspirin. Aspirin is an organic acid (page 756 ) with a \(K_{\mathrm{a}}\) of 3.27 \(\times 10^{-4}\) for the reaction $$\mathrm{HC}_{9} \mathrm{H}_{7} \mathrm{O}_{4}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightleftarrows \mathrm{C}_{9} \mathrm{H}_{7} \mathrm{O}_{4}^{-}(\mathrm{aq})+\mathrm{H}_{3} \mathrm{O}^{+}(\mathrm{aq})$$ If you have two tablets, each containing \(0.325 \mathrm{g}\) of aspirin (mixed with a neutral "binder" to hold the tablet together), and you dissolve them in a glass of water to give 225 mL of solution, what is the \(\mathrm{pH}\) of the solution?

Methylamine, \(\mathrm{CH}_{3} \mathrm{NH}_{2},\) is a weak base. $$\mathrm{CH}_{3} \mathrm{NH}_{2}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightleftarrows \mathrm{CH}_{3} \mathrm{NH}_{3}^{+}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq})$$ If the pH of a 0.065 M solution of the amine is 11.70 what is the value of \(K_{\mathrm{b}} ?\)

Chloroacetic acid \(\left(\mathrm{ClCH}_{2} \mathrm{CO}_{2} \mathrm{H}\right)\) has \(K_{\mathrm{a}}=1.41 \times 10^{-3}\) What is the value of \(K_{\mathrm{b}}\) for the chloroacetate ion \(\left(\mathrm{ClCH}_{2} \mathrm{CO}_{2}^{-}\right) ?\)

The weak base methylamine, \(\mathrm{CH}_{3} \mathrm{NH}_{2},\) has \(K_{\mathrm{b}}=\) \(4.2 \times 10^{-4} .\) It reacts with water according to the equation \(\mathrm{CH}_{3} \mathrm{NH}_{2}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightleftarrows \mathrm{CH}_{3} \mathrm{NH}_{3}^{+}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq})\) Calculate the equilibrium hydroxide ion concentration in a \(0.25 \mathrm{M}\) solution of the base. What are the \(\mathrm{pH}\) and pOH of the solution?

Nicotine, \(\mathrm{C}_{10} \mathrm{H}_{14} \mathrm{N}_{2},\) has two basic nitrogen atoms (page \(795),\) and both can react with water. $$\mathrm{Nic}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightleftarrows \mathrm{NicH}^{+}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq})$$ $$\mathrm{NicH}^{+}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightleftarrows \mathrm{NicH}_{2}^{2+}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq})$$ \(K_{\mathrm{b} 1}\) is \(7.0 \times 10^{-7}\) and \(K_{\mathrm{b} 2}\) is \(1.1 \times 10^{-10} .\) Calculate the approximate \(\mathrm{pH}\) of a \(0.020 \mathrm{M}\) solution.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free