Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

You have three solutions labeled \(\mathrm{A}, \mathrm{B},\) and \(\mathrm{C}\). You know only that each contains a different cation \(-\mathrm{Na}^{+}\) \(\mathrm{NH}_{4}^{+},\) or \(\mathrm{H}_{3} \mathrm{O}^{+} .\) Each has an anion that does not contribute to the solution \(\mathrm{pH}\) (e.g., \(\mathrm{Cl}^{-}\) ). You also have two other solutions, Y and Z, each containing a different anion, \(\mathrm{Cl}^{-}\) or \(\mathrm{OH}^{-},\) with a cation that does not influence solution \(\mathrm{pH}\) (e.g., \(\mathrm{K}^{+}\) ). If equal amounts of B and Y are mixed, the result is an acidic solution. Mixing A and Z gives a neutral solution, whereas B and Z give a basic solution. Identify the five unknown solutions. (Adapted from D. H. Barouch: Voyages in Conceptual Chemistry, Boston, Jones and Bartlett, 1997.)

Short Answer

Expert verified
A: Na⁺, B: H₃O⁺, C: NH₄⁺. Y: Cl⁻, Z: OH⁻.

Step by step solution

01

Analyze the results of mixing B and Y

When solution B is mixed with solution Y, the resulting mixture is acidic. This implies that solution B must contain a cation that increases acidity when paired with a neutral anion, like \( \mathrm{Cl}^{-} \) from Y. Thus, solution B is \( \mathrm{H}_{3} \mathrm{O}^{+} \).
02

Analyze the results of mixing A and Z

Mixing solution A with solution Z results in a neutral solution. Solution Z contains \( \mathrm{OH}^{-} \), a strong base, which when it neutralizes a strong acid, results in a neutral solution. Thus, solution A must contain \( \mathrm{H}_{3} \mathrm{O}^{+} \), however based on previous analysis, it cannot. Therefore, solution A contains \( \mathrm{Na}^{+} \) as it cannot alter the pH on its own when mixed with \( \mathrm{OH}^{-} \).
03

Analyze the results of mixing B and Z

Mixing solution B with solution Z yields a basic solution. Given that B contains \( \mathrm{H}_{3} \mathrm{O}^{+} \) and Z contains \( \mathrm{OH}^{-} \), the amount of \( \mathrm{OH}^{-} \) must overcome the presence of \( \mathrm{H}_{3} \mathrm{O}^{+} \) in solution B, making the solution basic. This further confirms the composition of B being \( \mathrm{H}_{3} \mathrm{O}^{+} \).
04

Determine the content of solution C

With B containing \( \mathrm{H}_{3} \mathrm{O}^{+} \) and A being \( \mathrm{Na}^{+} \), solution C must contain the remaining cation \( \mathrm{NH}_{4}^{+} \). This ion would act with any anion present in a manner distinct from either of the cases involving A or B.
05

Identify solutions Y and Z

Since mixing B (containing \( \mathrm{H}_{3} \mathrm{O}^{+} \)) with Y results in an acidic solution, solution Y must contain \( \mathrm{Cl}^{-} \), a neutral anion. Consequently, solution Z contains \( \mathrm{OH}^{-} \), which when paired with \( \mathrm{Na}^{+} \) (in A), results in a neutral solution and with \( \mathrm{H}_{3} \mathrm{O}^{+} \) (in B), results in a basic solution.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solution pH
The pH of a solution is a crucial measure of its acidity or basicity. It ranges from 0 to 14, with lower values indicating acidic solutions, higher values suggesting basic ones, and a neutral solution having a pH of 7.
Understanding the pH helps identify reactions and interactions within mixtures as certain ions contribute to different pH levels.
To assess the pH of our given solutions, we need to understand which ions affect it:
  • Hydronium ions ( \( \mathrm{H}_{3} \mathrm{O}^{+} \)): Contributes to acidity, lowering the pH of the solution.
  • Hydroxide ions ( \( \mathrm{OH}^{-} \)): Contributes to basicity, raising the pH of the solution.
  • Neutral ions (e.g., \( \mathrm{Na}^{+} \) and \( \mathrm{Cl}^{-} \)): Generally do not affect the pH directly.
In the given exercise, analyzing the combination of different solutions and their resultant pH gives us clues about the ions present in each solution.
Acid-Base Reactions
An acid-base reaction involves the transfer of protons (\( \mathrm{H}^{+} \)) from an acid to a base. This type of reaction is fundamental in understanding how substances will interact in a solution.
For our exercise:
  • When solution B, containing \( \mathrm{H}_{3} \mathrm{O}^{+} \), is mixed with solution Y that doesn't alter pH, acidity in the mixture means an acid is reacting.
  • The presence of acids or bases in a mixture can result in different pH outcomes depending on which ions predominate.
  • These reactions are essential in determining the characteristics of the unknown solutions based on their interactions.
The analysis during mixing allows identification of acidic or basic solutions due to the acid-base reactions occurring with each mix.
Neutralization Reactions
Neutralization occurs when an acid reacts with a base to produce water and, usually, a salt. This reaction is particularly telling in determining unknown solutions due to its predictable outcome of reaching a neutral pH of 7.
In the exercise:
  • Neutralization is evident when solution A with \( \mathrm{Na}^{+} \) is combined with solution Z containing \( \mathrm{OH}^{-} \)
  • The resulting mixture highlighted as neutral suggests that neither solution \( \mathrm{H}_{3} \mathrm{O}^{+} \) nor strong bases are present in overpowering amounts.
  • This relationship between the acid and base confirms the identity of cations in solution A as being neutral and not contributing to the overall pH change.
By observing these reactions, we draw conclusions on which solutions react to produce neutral solutions and uncover more about the involved ions.
Chemical Mixtures
Chemical mixtures involve the combination of two or more substances that may react or not, altering the properties and behaviors of each component in the process.
For identifying unknowns:
  • The results from mixing solutions inform the determination of specific ions, e.g., acidic, basic, or neutral outcomes from mixtures provide key insights.
  • In the progression of mixing A and Z resulting in neutral and B and Y resulting in acidic solutions, alignment of expected outcomes with results confirms the identity of the solutions.
  • Understanding these mixtures aids in predicting the presence and behavior of ions based on known ionic interactions.
Thus, observing how different chemical mixtures influence each other guides the problem-solving process regarding these solutions.
Ions in Solution
Ions play an essential role in the properties of a solution, dictating whether it's acidic, basic, or neutral.
Key ions in this context include:
  • \( \mathrm{H}_{3} \mathrm{O}^{+} \)
  • \( \mathrm{NH}_{4}^{+} \)
  • \( \mathrm{Na}^{+} \)
  • Neutral anions like \( \mathrm{Cl}^{-} \)
  • Basic anions like \( \mathrm{OH}^{-} \)
Knowing which ions are present provides crucial information to decipher the nature of the solutions.
The proper identification of ions allows for the understanding of solution behavior, like whether solution B is acidic due to containing \( \mathrm{H}_{3} \mathrm{O}^{+} \).
These insights are crucial for resolving the problem of determining the specifics of the solutions in an educational context.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Methylamine, \(\mathrm{CH}_{3} \mathrm{NH}_{2},\) is a weak base. $$\mathrm{CH}_{3} \mathrm{NH}_{2}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightleftarrows \mathrm{CH}_{3} \mathrm{NH}_{3}^{+}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq})$$ If the pH of a 0.065 M solution of the amine is 11.70 what is the value of \(K_{\mathrm{b}} ?\)

In each of the following acid-base reactions, identify the Bronsted acid and base on the left and their conjugate partners on the right. (a) \(\mathrm{HCO}_{2} \mathrm{H}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightleftarrows \mathrm{HCO}_{2}^{-}(\mathrm{aq})+\mathrm{H}_{3} \mathrm{O}^{+}(\mathrm{aq})\) (b) \(\mathrm{NH}_{3}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{S}(\mathrm{aq}) \rightleftarrows \mathrm{NH}_{4}^{+}(\mathrm{aq})+\mathrm{HS}^{-}(\mathrm{aq})\) (c) \(\mathrm{HSO}_{4}^{-}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq}) \rightleftarrows \mathrm{SO}_{4}^{2-}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell)\)

Several acids are listed here with their respective equilibrium constants. $$\begin{aligned} &\mathrm{HF}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightleftarrows \mathrm{H}_{3} \mathrm{O}^{+}(\mathrm{aq})+\mathrm{F}^{-}(\mathrm{aq})\\\ &K_{\mathrm{a}}=7.2 \times 10^{-4} \end{aligned}$$ $$\begin{aligned} &\mathrm{HPO}_{4}^{2-}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightleftarrows \mathrm{H}_{3} \mathrm{O}^{+}(\mathrm{aq})+\mathrm{PO}_{4}^{3-}(\mathrm{aq})\\\ &K_{\mathrm{a}}=3.6 \times 10^{-13} \end{aligned}$$ $$\begin{aligned} &\mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightleftarrows \mathrm{H}_{3} \mathrm{O}^{+}(\mathrm{aq})+\mathrm{CH}_{3} \mathrm{CO}_{2}^{-}(\mathrm{aq})\\\ &K_{\mathrm{a}}=1.8 \times 10^{-5} \end{aligned}$$ (a) Which is the strongest acid? Which is the weakest acid? (b) What is the conjugate base of the acid HF? (c) Which acid has the weakest conjugate base? (d) Which acid has the strongest conjugate base?

Iodine, \(\mathrm{I}_{2},\) is much more soluble in an aqueous solution of potassium iodide, KI, than it is in pure water. The anion found in solution is \(\mathrm{I}_{3}^{-}\). (a) Draw an electron dot structure for \(\mathrm{I}_{3}^{-}\). (b) Write an equation for this reaction, indicating the Lewis acid and the Lewis base.

About this time, you may be wishing you had an aspirin. Aspirin is an organic acid (page 756 ) with a \(K_{\mathrm{a}}\) of 3.27 \(\times 10^{-4}\) for the reaction $$\mathrm{HC}_{9} \mathrm{H}_{7} \mathrm{O}_{4}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightleftarrows \mathrm{C}_{9} \mathrm{H}_{7} \mathrm{O}_{4}^{-}(\mathrm{aq})+\mathrm{H}_{3} \mathrm{O}^{+}(\mathrm{aq})$$ If you have two tablets, each containing \(0.325 \mathrm{g}\) of aspirin (mixed with a neutral "binder" to hold the tablet together), and you dissolve them in a glass of water to give 225 mL of solution, what is the \(\mathrm{pH}\) of the solution?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free