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The following statements relate to the reaction for the formation of HI: $$\mathrm{H}_{2}(\mathrm{g})+\mathrm{I}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{HI}(\mathrm{g}) \quad \text { Rate }=k\left[\mathrm{H}_{2}\right]\left[\mathrm{I}_{2}\right]$$ Determine which of the following statements are true. If a statement is false, indicate why it is incorrect. (a) The reaction must occur in a single step. (b) This is a second-order reaction overall. (c) Raising the temperature will cause the value of \(k\) to decrease. (d) Raising the temperature lowers the activation energy for this reaction. (e) If the concentrations of both reactants are doubled, the rate will double. (f) Adding a catalyst in the reaction will cause the initial rate to increase.

Short Answer

Expert verified
(b) is true and (f) is true. All other statements are false.

Step by step solution

01

Identify Reaction Order

Given the rate law \(\text{Rate} = k[\text{H}_2][\text{I}_2]\), identify the order of the reaction with respect to each reactant. The reaction is first-order with respect to \(\text{H}_2\) and first-order with respect to \(\text{I}_2\). Therefore, the overall order of the reaction is the sum of the exponents, \(1 + 1 = 2\). Thus, it is a second-order reaction.
02

Review Statement (a)

Statement (a) claims the reaction must occur in a single step. A reaction's molecularity (single-step mechanism) cannot be determined just from the rate law. Therefore, statement (a) is false because the reaction could be a multi-step process.
03

Review Statement (b)

Since the overall reaction order is determined to be 2, statement (b) is true.
04

Review Statement (c)

Statement (c) states raising the temperature causes the value of \(k\) to decrease. In general, increasing temperature increases the rate constant \(k\) for most reactions, according to the Arrhenius equation. Therefore, statement (c) is false.
05

Review Statement (d)

Statement (d) suggests that raising the temperature lowers the activation energy. Instead, raising the temperature does not change the activation energy but provides more thermal energy to surpass it. Thus, statement (d) is false.
06

Review Statement (e)

Statement (e) claims that doubling concentrations of both reactants will double the rate. For the second-order reaction \(\text{Rate} = k[\text{H}_2][\text{I}_2]\), if both concentrations are doubled, the rate increases by a factor of 4 (\(2 \times 2 = 4\)). Thus, statement (e) is false.
07

Review Statement (f)

Statement (f) claims adding a catalyst will increase the initial rate. A catalyst provides an alternative pathway with a lower activation energy, typically increasing the rate of reaction. Thus, statement (f) is true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Order
The order of a reaction is a crucial concept in chemical kinetics. It tells us how the concentration of reactants affects the rate of the reaction. In a rate law, the order with respect to a particular reactant is the exponent of its concentration term.
For example, when given that the rate law of a reaction is \( \text{Rate} = k[\text{H}_2][\text{I}_2] \), the reaction is first-order with respect to \( \text{H}_2 \) and first-order with respect to \( \text{I}_2 \). The overall order is the sum of the exponents, which in this case is 2.
This makes it a second-order reaction. This means the rate depends on the square of the concentrations of the reactants. If the concentrations are changed, the rate changes significantly.
  • A first-order reaction means the rate is proportional to the concentration.
  • A second-order reaction means the rate is proportional to the square of the concentration.
Rate Law
The rate law of a chemical reaction is an expression that relates the rate of reaction to the concentrations of the reactants. It is an equation that captures how these concentrations influence the speed at which a reaction proceeds.
The rate law is generally given by: \( \text{Rate} = k[A]^m[B]^n \), where \( k \) is the rate constant, \( A \) and \( B \) are reactants, and \( m \) and \( n \) are the orders of the reaction with respect to each reactant.
If we take our example, \( \text{Rate} = k[\text{H}_2][\text{I}_2] \), each reactant's exponent reflects its effect on the rate. In many cases, the overall order of the reaction (sum of individual orders) helps determine how changes in concentration will impact the reaction rate.
  • The rate constant \( k \) is specific to a reaction at a given temperature.
  • Larger exponents indicate a more significant effect on the reaction rate.
Activation Energy
Activation energy is the minimum energy that reactants need to start a chemical reaction. It's an energy barrier that reactants must overcome to transform into products.
With the help of a graph, called a reaction energy diagram, you can see activation energy as the peak that needs to be surpassed to get from reactants to products.
One important idea in kinetics is that raising the temperature does not lower the activation energy itself. Instead, it provides the reactants with more energy to help surpass that barrier. An increase in temperature usually reduces the time it takes for particles to reach that energy level, thus speeding up the reaction.
  • More thermal energy makes it easier to overcome the activation energy.
  • The activation energy is specific for each reaction.
Catalyst Effect
A catalyst plays a fascinating role in chemical reactions. It speeds up a reaction by providing an alternative pathway with a lower activation energy. This means the energy peak that reactants need to overcome is lower, making it easier for them to convert into products.
Importantly, a catalyst is not consumed in the reaction; it is available to participate in the reaction cycle repeatedly. By lowering the activation energy, a catalyst increases the rate without altering the overall capacity of the reaction.
This is why adding a catalyst to a reaction typically increases the initial reaction rate, fulfilling its primary purpose. Catalysts are extensively used in many industrial processes to enhance efficiency.
  • Catalysts do not change the final products of the reaction.
  • They reduce energy costs in industrial processes by lowering the required energy input.

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Most popular questions from this chapter

The reaction cyclopropane \(\rightarrow\) propene occurs on a platinum metal surface at \(200^{\circ} \mathrm{C}\). (The platinum is a catalyst.) The reaction is first order in cyclopropane. Indicate how the following quantities change (increase, decrease, or no change) as this reaction progresses, assuming constant temperature. (a) [cyclopropane] (b) [propene] (c) [catalyst] (d) the rate constant, \(k\) (e) the order of the reaction (f) the half-life of cyclopropane

Ammonia decomposes when heated according to the equation $$\mathrm{NH}_{3}(\mathrm{g}) \rightarrow \mathrm{NH}_{2}(\mathrm{g})+\mathrm{H}(\mathrm{g})$$ The data in the table for this reaction were collected at a high temperature. $$\begin{array}{cc}\text { Time (h) } & \text { [NH }\left._{3}\right] \text { (mol/L) } \\\\\hline 0 & 8.00 \times 10^{-7} \\\25 & 6.75 \times 10^{-7} \\\50 & 5.84 \times 10^{-7} \\\75 & 5.15 \times 10^{-7} \\\\\hline\end{array}$$ Plot ln \(\left[\mathrm{NH}_{3}\right]\) versus time and \(1 /\left[\mathrm{NH}_{3}\right]\) versus time. What is the order of this reaction with respect to NH \(_{3} ?\) Find the rate constant for the reaction from the slope.

We want to study the hydrolysis of the beautiful green, cobalt-based complex called trans-dichlorobis(ethylenediamine) cobalt(III) ion, (Check your book to see figure) In this hydrolysis reaction, the green complex ion trans\(\left[\mathrm{Co}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right]^{+}\) forms the red complex ion \(\left[\mathrm{Co}(\mathrm{en})_{2}\left(\mathrm{H}_{2} \mathrm{O}\right) \mathrm{Cl}\right]^{2+}\) as a \(\mathrm{Cl}^{-}\) ion is replaced with a water molecule on the \(\mathrm{Co}^{3+}\) ion (en \(=\mathrm{H}_{2} \mathrm{NCH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\) ). The reaction progress is followed by observing the color of the solution. The original solution is green, and the final solution is red, but at some intermediate stage when both the reactant and product are present, the solution is gray. Changes in color with time as \(\mathrm{Cl}^{-}\) ion is replaced by \(\mathrm{H}_{2} \mathrm{O}\) in a cobalt(III) complex. The shape in the middle of the beaker is a vortex that arises because the solutions are being stirred using a magnetic stirring bar in the bottom of the beaker. Reactions such as this have been studied extensively, and experiments suggest that the initial, slow step in the reaction is the breaking of the Co-Cl bond to give a five-coordinate intermediate. The intermediate is then attacked rapidly by water. Slow: $$\begin{aligned}\operatorname{trans}-\left[\mathrm{Co}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right]^{+}(\mathrm{aq}) & \rightarrow \\\&\left[\mathrm{Co}(\mathrm{en})_{2} \mathrm{Cl}\right]^{2+}(\mathrm{aq})+\mathrm{Cl}^{-}(\mathrm{aq})\end{aligned}$$ Fast: $$\begin{aligned}\left[\mathrm{Co}(\mathrm{en})_{2} \mathrm{Cl}\right]^{2+}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\mathrm{aq}) & \rightarrow \\\&\left[\mathrm{Co}(\mathrm{en})_{2}\left(\mathrm{H}_{2} \mathrm{O}\right) \mathrm{Cl}\right]^{2+}(\mathrm{aq})\end{aligned}$$ (a) Based on the reaction mechanism, what is the predicted rate law? (b) As the reaction proceeds, the color changes from green to red with an intermediate stage where the color is gray. The gray color is reached at the same time, no matter what the concentration of the green starting material (at the same temperature). How does this show the reaction is first order in the green form? Explain. (c) The activation energy for a reaction can be found by plotting In \(k\) versus \(1 / T .\) However, here we do not need to measure \(k\) directly. Instead, because \(k=-(1 / t) \ln \left([\mathrm{R}] /[\mathrm{R}]_{0}\right),\) the time needed to achieve the gray color is a measure of \(k .\) Use the data below to find the activation energy. $$\begin{array}{cc}\text { Temperature }^{\circ} \mathrm{C} & \text { (for the Same Initial Concentration) } \\\\\hline 56 & 156 \mathrm{s} \\\60 & 114 \mathrm{s} \\\65 & 88 \mathrm{s} \\\75 & 47 \mathrm{s} \\\\\hline\end{array}$$

Nitrogen oxides, \(\mathrm{NO}_{x}\) (a mixture of \(\mathrm{NO}\) and \(\mathrm{NO}_{2}\) collectively designated as \(\mathrm{NO}_{x}\) ), play an essential role in the production of pollutants found in photochemical smog. The \(\mathrm{NO}_{x}\) in the atmosphere is slowly broken down to \(\mathrm{N}_{2}\) and \(\mathrm{O}_{2}\) in a first-order reaction. The average half-life of \(\mathrm{NO}_{x}\) in the smokestack emissions in a large city during daylight is 3.9 hours. (a) Starting with \(1.50 \mathrm{mg}\) in an experiment, what quantity of NO, remains after 5.25 hours? (b) How many hours of daylight must have elapsed to decrease \(1.50 \mathrm{mg}\) of \(\mathrm{NO}_{x}\) to \(2.50 \times 10^{-6} \mathrm{mg} ?\)

Describe each of the following statements as true or false. If false, rewrite the sentence to make it correct. (a) The rate-determining elementary step in a reaction is the slowest step in a mechanism. (b) It is possible to change the rate constant by changing the temperature. (c) As a reaction proceeds at constant temperature, the rate remains constant. (d) A reaction that is third order overall must involve more than one step.

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