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Using the rate equation "Rate \(=k[\mathrm{A}]^{2}[\mathrm{B}],\) " define the order of the reaction with respect to \(\mathrm{A}\) and \(\mathrm{B}\). What is the total order of the reaction?

Short Answer

Expert verified
Order with respect to A: 2; Order with respect to B: 1; Total order: 3.

Step by step solution

01

Understanding Reaction Order

Reaction order refers to the power to which the concentration term of a reactant is raised in the rate equation. For any reactant specified in a rate law, the reaction order indicates how the rate is affected by changes in the concentration of that reactant.
02

Identify Order with Respect to A

According to the given rate equation \( \text{Rate} = k[\mathrm{A}]^{2}[\mathrm{B}] \), the concentration of \([\mathrm{A}]\) is raised to the power of 2. This means that the reaction is second order with respect to reactant \( \mathrm{A} \).
03

Identify Order with Respect to B

In the rate equation \( \text{Rate} = k[\mathrm{A}]^{2}[\mathrm{B}] \), the concentration of \([\mathrm{B}]\) is raised to the power of 1. Therefore, the reaction is first order with respect to reactant \( \mathrm{B} \).
04

Calculate Total Order of the Reaction

The total order of the reaction is the sum of the orders with respect to all reactants involved. So, the total order is \(2 + 1 = 3\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Equation
A rate equation, often called the rate law, is an expression that quantifies the rate of a chemical reaction in relation to the concentration of its reactants. It helps us understand how different factors like concentration affect the speed of a reaction. For example, in our rate equation:

\[\text{Rate} = k[\mathrm{A}]^2[\mathrm{B}] \]
  • The letter \( k \) is the rate constant. It provides a proportionality constant that makes the equation work out correctly, based on experimental data.
  • The terms \( [\mathrm{A}] \) and \( [\mathrm{B}] \) represent the molar concentrations of reactants \( \mathrm{A} \) and \( \mathrm{B} \).
  • The exponents \( 2 \) and \( 1 \) in this equation are crucial because they tell us the reaction order with respect to each reactant.
Understanding the components of a rate equation helps in predicting how changing one factor will change the rate of the reaction. This makes it a powerful tool in both academic studies and industrial applications.
Second Order Reaction
The term second order reaction specifically refers to the reaction order with respect to a given reactant. In the rate equation provided:

\[ \text{Rate} = k[\mathrm{A}]^{2}[\mathrm{B}] \]\( \mathrm{A} \) is raised to the power of \( 2 \), signifying that the reaction is second order with respect to \( \mathrm{A} \). This means the rate of reaction is highly sensitive to changes in the concentration of \( \mathrm{A} \). For example, if the concentration of \( \mathrm{A} \) is doubled, the reaction rate will increase by a factor of four.

  • This squared relationship implies that any change in \( \mathrm{A} \) will have a pronounced effect on the reaction rate.
  • Second order reactions are often observed in complex processes like enzyme kinetics and polymerization.
  • Second order doesn't only mean the presence of a squared term; it indicates a deeper dependence on a particular reactant.
Knowing the second order nature of the reaction is crucial for figuring out how to effectively control the reaction rate in practical applications.
Total Order of Reaction
The total order of a reaction is determined by summing the exponents of all the reactants in the rate equation. It gives a holistic view of how the reaction rate is affected by the concentrations of all reactants involved. For our rate equation:

\[\text{Rate} = k[\mathrm{A}]^{2}[\mathrm{B}] \]
  • The reaction is second order with respect to \( \mathrm{A} \) since the concentration of \( \mathrm{A} \) is raised to the power of 2.
  • It is first order with respect to \( \mathrm{B} \), as its concentration is raised to the power of 1.
The total order of the reaction is calculated by adding these individual orders:
\[ 2 + 1 = 3 \]Understanding the total order is important because it guides you in understanding the overall behavior of the reaction. If you're considering a system where multiple reactants are interacting, knowing the total order of reaction aids in understanding how variations in concentrations influence overall reaction rates. This information is highly useful when designing experiments or industrial processes involving the reaction.

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Most popular questions from this chapter

Give the relative rates of disappearance of reactants and formation of products for each of the following reactions. (a) \(2 \mathrm{NO}(\mathrm{g})+\mathrm{Br}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{NOBr}(\mathrm{g})\) (b) \(\mathrm{N}_{2}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{NH}_{3}(\mathrm{g})\)

The following statements relate to the reaction for the formation of HI: $$\mathrm{H}_{2}(\mathrm{g})+\mathrm{I}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{HI}(\mathrm{g}) \quad \text { Rate }=k\left[\mathrm{H}_{2}\right]\left[\mathrm{I}_{2}\right]$$ Determine which of the following statements are true. If a statement is false, indicate why it is incorrect. (a) The reaction must occur in a single step. (b) This is a second-order reaction overall. (c) Raising the temperature will cause the value of \(k\) to decrease. (d) Raising the temperature lowers the activation energy for this reaction. (e) If the concentrations of both reactants are doubled, the rate will double. (f) Adding a catalyst in the reaction will cause the initial rate to increase.

Nitryl fluoride can be made by treating nitrogen dioxide with fluorine: $$2 \mathrm{NO}_{2}(\mathrm{g})+\mathrm{F}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{NO}_{2} \mathrm{F}(\mathrm{g})$$ Use the rate data in the table to do the following: (a) Write the rate equation for the reaction. (b) Indicate the order of reaction with respect to each component of the reaction. (c) Find the numerical value of the rate constant, \(k.\) $$\begin{array}{ccccl}\hline \text { Experiment } & {\left[\mathrm{NO}_{2}\right]} & {\left[\mathrm{F}_{2}\right]} & {\left[\mathrm{NO}_{2} \mathrm{F}\right]} & \left(\mathrm{mol} \mathrm{F}_{2} / \mathrm{L} \cdot \mathrm{s}\right) \\\\\hline 1 & 0.001 & 0.005 & 0.001 & 2.0 \times 10^{-4} \\\2 & 0.002 & 0.005 & 0.001 & 4.0 \times 10^{-4} \\\3 & 0.006 & 0.002 & 0.001 & 4.8 \times 10^{-4} \\\4 & 0.006 & 0.004 & 0.001 & 9.6 \times 10^{-4} \\\5 & 0.001 & 0.001 & 0.001 & 4.0 \times 10^{-5} \\\6 & 0.001 & 0.001 & 0.002 & 4.0 \times 10^{-5} \\\\\hline\end{array}$$

Gaseous azomethane, \(\mathrm{CH}_{3} \mathrm{N}=\mathrm{NCH}_{3},\) decomposes in a first-order reaction when heated: $$\mathrm{CH}_{3} \mathrm{N}=\mathrm{NCH}_{3}(\mathrm{g}) \rightarrow \mathrm{N}_{2}(\mathrm{g})+\mathrm{C}_{2} \mathrm{H}_{6}(\mathrm{g})$$ The rate constant for this reaction at \(600 \mathrm{K}\) is 0.0216 \(\min ^{-1} .\) If the initial quantity of azomethane in the flask is \(2.00 \mathrm{g},\) how much remains after 0.0500 hour? What quantity of \(\mathrm{N}_{2}\) is formed in this time?

Many biochemical reactions are catalyzed by acids. A typical mechanism consistent with the experimental results (in which HA is the acid and X is the reactant) is Step 1: Fast, reversible: \(\quad \mathrm{HA} \rightleftarrows \mathrm{H}^{+}+\mathrm{A}^{-}\) Step 2: Fast, reversible: \(\quad \mathrm{X}+\mathrm{H}^{+} \rightleftarrows \mathrm{XH}^{+}\) Step 3: Slow \(\quad \mathrm{XH}^{+} \rightarrow\) products What rate law is derived from this mechanism? What is the order of the reaction with respect to HA? How would doubling the concentration of HA affect the reaction?

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