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Can carbon monoxide \(\left(T_{c}=132.9 \mathrm{K} ; P_{c}=34.5 \mathrm{atm}\right)\) be liquefied at or above room temperature? Explain briefly.

Short Answer

Expert verified
Carbon monoxide cannot be liquefied at or above room temperature.

Step by step solution

01

Identify the Critical Temperature

The critical temperature \(T_c\) of carbon monoxide is the temperature above which it cannot be liquefied, no matter how much pressure is applied. For carbon monoxide, this value is given as \(T_c = 132.9 \, \text{K}\).
02

Convert Room Temperature to Kelvin

Room temperature is typically around 25°C. To convert this to Kelvin, use the formula \(T_K = T_{°C} + 273.15\). Thus, \(T_K = 25 + 273.15 = 298.15 \, \text{K}\).
03

Compare Temperatures

Now, compare the critical temperature \(T_c = 132.9 \, \text{K}\) with the converted room temperature \(T_K = 298.15 \, \text{K}\). Since 298.15 K is greater than 132.9 K, this means room temperature is above the critical temperature.
04

Conclusion on Liquefaction at Room Temperature

Since the room temperature is above the critical temperature of carbon monoxide, it cannot be liquefied at or above room temperature regardless of the pressure applied. Therefore, carbon monoxide cannot be liquefied at or above room temperature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Carbon Monoxide
Carbon monoxide (CO) is a colorless and odorless gas that is slightly less dense than air. It's a simple molecule composed of one carbon atom and one oxygen atom, connected by a triple bond. It's produced in various combustion processes, particularly when there is not enough oxygen to produce carbon dioxide (CO₂). Despite its simplicity, carbon monoxide is highly toxic to humans and animals when inhaled, as it interrupts the ability of blood to transport oxygen.
The critical temperature
  • The critical temperature of a substance is the temperature above which it cannot be converted into a liquid state, irrespective of the pressure applied.
  • For carbon monoxide, this critical temperature is 132.9 Kelvin.
  • This means that above this temperature, no amount of pressure can liquefy the substance.
Liquefaction and Its Limitations
Liquefaction is the process of converting a gas into a liquid. This process can typically be achieved by either increasing the pressure or lowering the temperature of the gas. At the molecular level, this means the gas particles are brought closer together, overcoming their kinetic energy that keeps them apart.

For each gas, there's a critical temperature that defines its limit for being liquefied. As you probably recall, the critical temperature is the maximum temperature below which a gas can transition into a liquid with the application of pressure.

Limitations
  • If a gas is above its critical temperature, like carbon monoxide at room temperature, it cannot be transformed into a liquid by pressure alone.
  • This explains why CO cannot be liquefied in these conditions: room temperature exceeds its critical temperature of 132.9 Kelvin.
Kelvin Conversion Simplified
Temperature conversion can be confusing, but the Kelvin scale simplifies scientific calculations related to gases because it starts from absolute zero. Kelvin is a thermodynamic temperature scale used worldwide in science and engine design. It's useful because it aligns directly with the laws of thermodynamics, making it a natural choice for scientific work.
How to Convert Celsius to Kelvin
  • Converting Celsius to Kelvin is straightforward: add 273.15 to the Celsius value.
  • For example, room temperature is 25°C, which converts to 298.15 Kelvin.
Kelvin’s Benefits
  • Using Kelvin avoids negative numbers when dealing with thermodynamic equations, simplifying many scientific calculations.
  • It's particularly useful in situations involving gas laws and critical phenomena, such as the liquefaction of gases.

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Most popular questions from this chapter

A "hand boiler" can be purchased in toy stores or at science supply companies. If you cup your hand around the bottom bulb, the volatile liquid in the boiler boils, and the liquid moves to the upper chamber. Using your knowledge of kinetic molecular theory and intermolecular forces, explain how the hand boiler works. (IMAGE CAN'T COPY)

Ethanol, \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH},\) has a vapor pressure of \(59 \mathrm{mm}\) Hg at \(25^{\circ} \mathrm{C}\). What quantity of energy as heat is required to evaporate \(125 \mathrm{mL}\) of the alcohol at \(25^{\circ} \mathrm{C} ?\) The enthalpy of vaporization of the alcohol at \(25^{\circ} \mathrm{C}\) is 42.32 \(\mathrm{kJ} / \mathrm{mol} .\) The density of the liquid is \(0.7849 \mathrm{g} / \mathrm{mL}.\)

Equilibrium vapor pressures of benzene, \(\mathrm{C}_{6} \mathrm{H}_{6},\) at various temperatures are given in the table. $$\begin{array}{cc} \text { Temperature }\left(^{\circ} \mathrm{C}\right) & \text { Vapor Pressure }(\mathrm{mm} \mathrm{Hg}) \\ \hline 7.6 & 40 . \\ 26.1 & 100 \\ 60.6 & 400 \\\ 80.1 & 760 \\ \hline \end{array}$$ (a) What is the normal boiling point of benzene? (b) Plot these data so that you have a graph resembling the one in Figure \(12.17 .\) At what temperature does the liquid have an equilibrium vapor pressure of \(250 \mathrm{mm}\) Hg? At what temperature is the vapor pressure \(650 \mathrm{mm}\) Hg? (c) Calculate the molar enthalpy of vaporization for benzene using the the Clausius-Clapeyron equation.

You are comparing three different substances, \(A, B,\) and C, all liquids. The vapor pressure at \(25^{\circ} \mathrm{C}\) for substance A is less than the vapor pressure for \(B\) at this temperature. Substance C has the highest boiling point of the three substances. List the three substances \(\mathrm{A}, \mathrm{B},\) or \(\mathrm{C}\) in order of the strength of intermolecular forces, from least to greatest.

Mercury and many of its compounds are dangerous poisons if breathed, swallowed, or even absorbed through the skin. The liquid metal has a vapor pressure of \(0.00169 \mathrm{mm}\) Hg at \(24^{\circ} \mathrm{C} .\) If the air in a small room is saturated with mercury vapor, how many atoms of mercury vapor occur per cubic meter?

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