Chapter 10: Problem 27
Draw structures for alkenes that have the formula \(\mathrm{C}_{3} \mathrm{H}_{5} \mathrm{Cl},\) and name each compound. (These are derivatives of propene in which a chlorine atom replaces one hydrogen atom.)
Short Answer
Expert verified
1-Chloropropene and 2-Chloropropene.
Step by step solution
01
Understanding the Molecular Formula
The formula \(\mathrm{C}_{3}\mathrm{H}_{5}\mathrm{Cl}\) suggests a molecule with 3 carbon atoms, 5 hydrogen atoms, and 1 chlorine atom. This is a chlorosubstituted derivative of propene, where one hydrogen atom is substituted by a chlorine atom.
02
Identify Propene Substitution Points
Propene, \((\mathrm{C}_{3}\mathrm{H}_6)\), has the structure: CH2=CH-CH3. The chlorine can replace a hydrogen atom attached to any carbon atom.
03
Draw Isomer 1: 1-Chloropropene
The chlorine atom can replace one of the hydrogen atoms on the first carbon of propene, resulting in the structure CH2=CH-CH2Cl. Here, the double bond remains between the first and second carbon atoms.
04
Draw Isomer 2: 2-Chloropropene
Alternatively, the chlorine atom can replace a hydrogen attached to the second carbon atom, resulting in CH3-CH=CHCl. In this structure, the double bond is between the second and third carbon atoms.
05
Naming the Isomers
The first structure, CH2=CH-CH2Cl, is named 1-Chloropropene since the chlorine is on the first carbon from one end. The second structure, CH3-CH=CHCl, is called 2-Chloropropene since the chlorine is on the second carbon from the other end.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molecular Structure
The concept of molecular structure involves understanding how atoms are arranged in a molecule. For the compound with the formula \(\mathrm{C}_{3}\mathrm{H}_{5}\mathrm{Cl}\), we need to understand how these atoms come together to form a stable organic structure. Here, the compound consists of:
- Three carbon atoms
- Five hydrogen atoms
- One chlorine atom
Isomerism
Isomerism occurs when compounds have the same molecular formula but different structural formulas. This means they differ in the arrangement of their atoms, giving rise to structural isomers. For our compound \(\mathrm{C}_{3}\mathrm{H}_{5}\mathrm{Cl}\), we explore positional isomers:
- Isomer 1: 1-Chloropropene - Here, the chlorine atom takes the place of a hydrogen atom on the first carbon, resulting in the structure \(\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}_2\mathrm{Cl}\).
- Isomer 2: 2-Chloropropene - In this case, chlorine substitutes a hydrogen on the second carbon atom, forming \(\mathrm{CH}_3-\mathrm{CH}=\mathrm{CHCl}\).
Halogenation
Halogenation is a chemical reaction that involves the addition of halogen atoms like chlorine to an organic compound. In our exercise, halogenation refers to replacing one hydrogen atom in propene with a chlorine atom:
- This process forms chloropropene, which can exist in two isomeric forms as demonstrated previously.
- The presence of chlorine, a halogen, brings about significant changes in the compound’s reactivity and physical properties.
Organic Chemistry
Organic chemistry is the study of carbon compounds and is often referred to as the chemistry of life. Alkenes, like propene, are a major class of organic molecules characterized by at least one carbon-carbon double bond. This subset of hydrocarbons forms the backbone of many reactions in organic chemistry.
- These reactions include halogenation, as we see with the conversion of propene to chloropropene.
- The presence of different functional groups, such as chlorine in chloropropenes, modifies physical and chemical properties, expanding the versatility of organic compounds.