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What structural requirement is necessary for an alkene to have cis and trans isomers? Can cis and trans isomers exist for an alkane? For an alkyne?

Short Answer

Expert verified
Alkenes need two distinct groups on each carbon of the double bond. Alkanes and alkynes cannot have cis-trans isomers.

Step by step solution

01

Understanding Cis-Trans Isomerism

Cis-trans isomers, also known as geometric isomers, occur in alkenes when there are distinct groups attached to each carbon of the double bond. These isomers result due to restricted rotation around the double bond.
02

Identify the Structural Requirement for Alkenes

For an alkene to have cis and trans isomers, each carbon of the double bond must have two different groups attached to it. This difference allows the two forms: 'cis' where similar groups are on the same side and 'trans' where they are on opposite sides.
03

Analyze the Possibility in Alkanes

Alkanes have only single bonds, allowing free rotation around their bonds. This free rotation means that there are no fixed positions, and thus, alkanes cannot have cis-trans isomers.
04

Consider the Case for Alkynes

Alkynes have triple bonds, which provide even more rigidity than a double bond but result in linear geometry. This linearity makes it impossible for alkynes to have distinct 'cis' and 'trans' forms, as the groups are aligned 180 degrees apart.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cis-Trans Isomers
Cis-trans isomers are a fascinating example of geometric isomerism seen predominantly in alkenes. These isomers arise from the restricted rotation around double bonds, a feature characteristic of alkenes. In a simple sense, if an alkene has two different groups attached to each carbon of its double-bond, it can exhibit two different configurations.
In the 'cis' form, the similar groups are on the same side of the double bond, leading to a kind of molecule mirror image. On the other hand, the 'trans' form has the similar groups on opposite sides of the bond, resembling a diagonal position. These configurations impact the chemical and physical properties of the molecules, making cis-trans isomerism a crucial concept in chemistry.
Alkene Structure
Alkenes are hydrocarbons characterized by at least one carbon-carbon double bond. This key structural feature is crucial for geometric isomerism. The double bond consists of a sigma bond and a pi bond. The pi bond restricts rotation around the doble bond, maintaining the molecule's shape.
To foster cis-trans isomerism, it's vital that each carbon in the double bond is bonded to two different groups. This diversity in groups is what allows the molecule to have distinct cis and trans forms. Without this structural requirement, the potential for geometric isomers diminishes significantly. Alkenes' structure, thus, significantly influences their potential to exhibit cis-trans isomers.
Alkane Rotation
Alkanes are another type of hydrocarbon, but unlike alkenes, they possess only single bonds. These single bonds are comprised of only sigma bonds, which allow free rotation. Due to this free rotation, the diverse configurational constraints necessary for forming cis-trans isomers cannot be sustained in alkanes.
The lack of fixed orientation means that all configurations are interchangeable via rotation. Consequently, it becomes impossible to maintain the distinct 'same side' or 'opposite side' arrangements critical for cis or trans isomers. Therefore, alkanes do not exhibit geometric isomerism.
Alkyne Geometry
Alkynes stand apart with their characteristic carbon-carbon triple bonds, consisting of one sigma bond and two pi bonds. This bonding setup leads to a linear geometry, as the triple bond exerts a strong directional pull, aligning all groups attached to the bond 180 degrees apart.
This linear structure means that, unlike alkenes, there is simply no spatial room for the formation of distinct cis and trans forms. All groups align in a straight line, eliminating the possibility of different isomeric configurations. Therefore, despite the rigidity of an alkyne's triple bond, no geometric isomerism is observed simply due to its alignment.

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Most popular questions from this chapter

Isooctane, 2,2,4 -trimethylpentane, is one of the possible structural isomers with the formula \(\mathrm{C}_{8} \mathrm{H}_{18} .\) Draw the structure of this isomer, and draw and name structures of two other isomers of \(\mathrm{C}_{8} \mathrm{H}_{18}\) in which the longest carbon chain is five atoms.

Carbon atoms appear in organic compounds in several different ways with single, double, and triple bonds combining to give an octet configuration. Describe the various ways that carbon can bond to reach an octet, and give the name and draw the structure of a compound that illustrates that mode of bonding.

Name the following amines: (a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\) (b) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{N}\) (c) \(\left(\mathrm{CH}_{3}\right)\left(\mathrm{C}_{2} \mathrm{H}_{5}\right) \mathrm{NH}\) (d) \(\mathrm{C}_{6} \mathrm{H}_{13} \mathrm{NH}_{2}\)

A hydrocarbon with the formula \(\mathrm{C}_{5} \mathrm{H}_{10}\) can be either an alkene or a cycloalkane. (a) Draw a structure for each of the six isomers possible for \(\mathrm{C}_{5} \mathrm{H}_{10},\) assuming it is an alkene. Give the systematic name of each isomer. (b) Draw a structure for a cycloalkane having the formula \(\mathrm{C}_{5} \mathrm{H}_{10}\)

You are asked to identify an unknown colorless, liquid carbonyl compound. Analysis has determined that the formula for this unknown is \(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O} .\) Only two compounds match this formula. (a) Draw structures for the two possible compounds. (b) To decide which of the two structures is correct, you react the compound with an oxidizing agent and isolate from that reaction a compound that is found to give an acidic solution in water. Use this result to identify the structure of the unknown. (c) Name the acid formed by oxidation of the unknown.

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