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Give the number of nodal surfaces for each orbital type: \(s\) \(p, d,\) and \(f\)

Short Answer

Expert verified
s: 0 nodal surfaces, p: 1 nodal surface, d: 2 nodal surfaces, f: 3 nodal surfaces.

Step by step solution

01

Understanding Nodal Surfaces

A nodal surface, also known as a nodal plane, is a region where the probability density of finding an electron is zero. Nodal surfaces are directly related to the angular part of the wavefunction, expressed in terms of quantum numbers.
02

The s Orbital

The s orbitals are spherical and have no angular nodes. They have only radial nodes. Since the principal quantum number minus one gives the number of nodal surfaces, an s orbital with \(n\) equals any number has \(n-1\) radial nodes and zero angular ones. Thus, the total number of nodal surfaces for the s orbital is 0.
03

The p Orbital

The p orbitals have one angular node and no radial nodes (if \(n=2\), with additional radial nodes possible if \(n\) is greater than 2). For p orbitals, regardless of any additional radial nodes, there is always 1 nodal surface. Therefore, a typical p orbital will have 1 nodal surface.
04

The d Orbital

The d orbitals are more complex, having two angular nodal surfaces. These correspond to higher quantum numbers than p, and similar to p orbitals, additional radial nodes appear for \(n > 3\). The standard count for d orbitals is always 2 nodal surfaces due to these angular nodes.
05

The f Orbital

The f orbitals have the most angular complexity and contain three angular nodes. They are associated with \(n > 4\) quantum levels, and irrespective of radial nodes due to the principal quantum number, f orbitals have 3 angular nodal surfaces.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

s orbital
The s orbital is the simplest type of atomic orbital. The letter "s" stands for "spherical" which is the shape of these orbitals. They are symmetric around the nucleus, like a perfect sphere. One of the key characteristics of an s orbital is that it has no angular nodes. This means that there are no areas on the surface of the orbital where the probability of finding an electron is zero due to its shape.

In terms of nodal surfaces, for any s orbital, the **number is zero**. This is calculated using the principle that the total number of nodal surfaces is given by the principal quantum number (n) minus one. Therefore, the s orbital only has radial nodes, and specifically, there are no angular nodal surfaces.
p orbital
The p orbital is the next step up in complexity after the s orbital. These are shaped like dumbbells, having two lobes on opposite sides of the nucleus. Unlike s orbitals, p orbitals have angular nodal planes. This means there is a region where the probability of finding an electron is zero. For p orbitals, this is one angular nodal surface.

Irrespective of the principal quantum number, there will always be one angular node for a p orbital. However, as the principal quantum number increases, additional radial nodes can appear. The number of angular nodes remains constant at one.
d orbital
D orbitals are more complex than both s and p orbitals. They are often depicted as four-leaf clover shapes or a dumbbell with a donut around the center. These orbitals have two angular nodal surfaces, meaning there are two planes where the probability of finding an electron is zero.

Like with other orbitals, the total number of nodal surfaces can increase with additional principal quantum numbers through radial nodes. Still, the two angular nodes are a hallmark of the d orbitals. They are found in atoms starting at the third energy level (n=3) and above.
f orbital
F orbitals are the most complex types of atomic orbitals. They start to appear in atoms at the fourth energy level (n=4) and typically have three angular nodal surfaces. This complexity is due to the higher energy levels and quantum numbers involved.

The f orbitals have intricate shapes which are hard to visualize compared to s, p, or even d orbitals. Despite their complexity, the number of angular nodes is a constant feature: always three. With higher quantum numbers, more radial nodes can appear, but the defining three angular nodes remain fixed. This complexity is why f orbitals are often discussed in advanced chemistry and physics classes.

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Most popular questions from this chapter

Consider only transitions involving the \(n=1\) through \(n=5\) energy levels for the H atom (where the energy level spacings below are not to scale). $$\begin{aligned} &\begin{aligned} & n=5 \\ & n=4 \\ & n=3 \\ & n=2 \end{aligned}\\\ &7\\\ &n=1 \end{aligned}$$ (a) How many emission lines are possible, considering only the five quantum levels? (b) Photons of the highest frequency are emitted in a transition from the level with \(n=\quad\) to a level with \(n=\) (c) The emission line having the longest wavelength corresponds to a transition from the level with \(n=\ldots\) to the level with \(n=\)

Place the following types of radiation in order of increasing energy per photon: (a) yellow light from a sodium lamp (b) \(x\) -rays from an instrument in a dentist's office (c) microwaves in a microwave oven (d) your favorite FM music station at \(91.7 \mathrm{MHz}\)

Radiation in the ultraviolet region of the electromagnetic spectrum is quite energetic. It is this radiation that causes dyes to fade and your skin to develop a sunburn. If you are bombarded with 1.00 mol of photons with a wavelength of 375 nm, what amount of energy, in kilojoules per mole of photons, are you being subjected to?

Green light has a wavelength of \(5.0 \times 10^{2} \mathrm{nm}\). What is the energy, in joules, of one photon of green light? What is the energy, in joules, of 1.0 mol of photons of green light?

Light is given off by a sodium- or mercury-containing streetlight when the atoms are excited. The light you see arises for which of the following reasons? (a) Electrons are moving from a given energy level to one of higher \(n\) (b) Electrons are being removed from the atom, thereby creating a metal cation. (c) Electrons are moving from a given energy level to one of lower \(n\)

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