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The first law of thermodynamics is often described as another way of stating the law of conservation of energy. Discuss whether this is an accurate portrayal.

Short Answer

Expert verified
Yes, the first law accurately represents the conservation of energy, focusing on thermodynamic processes.

Step by step solution

01

Understand the First Law of Thermodynamics

The first law of thermodynamics states that energy cannot be created or destroyed, only transferred or transformed. It can be mathematically expressed as \( \Delta U = Q - W \), where \( \Delta U \) is the change in internal energy of a system, \( Q \) is the heat added to the system, and \( W \) is the work done by the system.
02

Recognize the Law of Conservation of Energy

The law of conservation of energy succinctly states that in an isolated system, the total energy remains constant over time. It implies that energy can change forms (e.g., kinetic to potential) but cannot be created or destroyed.
03

Compare Both Laws

The first law of thermodynamics is essentially a specific application of the law of conservation of energy to thermodynamic processes, emphasizing the relationship between internal energy, heat, and work. Both laws highlight the principle of energy conservation, but the first law of thermodynamics provides a more detailed framework for thermodynamic systems.
04

Analyze their Applications

While the law of conservation of energy applies universally, the first law of thermodynamics is particularly useful in analyzing processes involving heat and work, such as engines and refrigerators. It gives a calculable relationship to track energy flow within a system.
05

Conclusions

The first law of thermodynamics accurately portrays the law of conservation of energy for thermodynamic contexts, being a more detailed, process-specific version that includes heat and work explicitly. It does not contradict the conservation law but clarifies its application in thermodynamics.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Energy
The principle of conservation of energy is a fundamental concept in physics. It states that energy in an isolated system cannot be created or destroyed, but can only change forms, such as kinetic energy turning into potential energy. This principle is broad and underpins much of classical physics. It serves as a fundamental rule that applies universally, whether you're dealing with mechanical systems, electrical systems, or even biological processes.
  • Energy transformations can occur, leading to a change in energy type, like converting chemical energy from food into mechanical energy through movement.
  • While energy can change forms, its total quantity in a closed system remains constant.
Understanding conservation of energy is key to analyzing how different types of energy interact and balance within a system.
Thermodynamic Processes
Thermodynamic processes deal with energy transfer, often involving heat and work. They describe how systems transform energy, providing detailed pathways for energy changes, guided by thermodynamic laws such as the first law. These processes include various scenarios such as isothermal (constant temperature) and adiabatic (no heat exchange) processes. In a thermodynamic process, several parameters may change:
  • Pressure
  • Volume
  • Temperature
These variables are crucial in defining the state and changes within a thermodynamic system. Whether you're examining how a refrigerator cools or how a car engine works, understanding the specific thermodynamic process involved is essential for comprehending how energy flows and transforms.
Internal Energy
Internal energy is the total energy contained within a system. It encompasses the kinetic and potential energy of particles inside the system. This concept is central in thermodynamics, where changes in internal energy are closely analyzed. The first law of thermodynamics expresses how internal energy is affected by heat and work through the formula \( \Delta U = Q - W \),where \( \Delta U \) represents the change in internal energy, \( Q \) is heat added to the system, and \( W \) is work done by the system. Considerations in internal energy involve:
  • Understanding how molecular movement or intermolecular forces contribute to a system's internal energy.
  • Recognizing that while internal energy change can mirror state changes (like temperature), it can also involve latent heat without temperature variation.
Mastering the idea of internal energy helps explain why and how energy flows within a system, forming the basis for predicting system behavior during energy exchanges.
Heat and Work
Heat and work are two specific forms of energy transfer in thermodynamic contexts. Heat refers to the process of energy transfer from one object to another due to a temperature difference. It naturally flows from a hotter body to a colder one and is usually denoted by \( Q \). On the other hand, work involves energy transfer due to an object's displacement caused by a force, and it is typically denoted by \( W \). Important distinctions include:
  • Heat is often associated with random molecular motion, while work is linked with organized external forces causing motion.
  • Both heat and work result in the change of a system's internal energy, as described by the first law of thermodynamics.
Understanding the roles of heat and work helps clarify how different forms of energy transfer affect system changes, especially in engines and other practical applications, making predictions about energy efficiency and performance possible.

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Most popular questions from this chapter

A piece of lead with a mass of \(27.3 \mathrm{g}\) was heated to \(98.90^{\circ} \mathrm{C}\) and then dropped into \(15.0 \mathrm{g}\) of water at \(22.50^{\circ} \mathrm{C} .\) The final temperature was \(26.32^{\circ} \mathrm{C} .\) Calculate the specific heat capacity of lead from these data.

Nitrogen monoxide, a gas recently found to be involved in a wide range of biological processes, reacts with oxygen to give brown \(\mathrm{NO}_{2}\) gas. $$2 \mathrm{NO}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g}) \longrightarrow 2 \mathrm{NO}_{2}(\mathrm{g}) \quad \Delta H_{\mathrm{rxn}}^{\circ}=-114.1 \mathrm{kJ}$$ Is this reaction endothermic or exothermic? If \(1.25 \mathrm{g}\) of NO is converted completely to \(\mathrm{NO}_{2}\), what quantity of heat is absorbed or evolved?

Hydrazine, \(\mathrm{N}_{2} \mathrm{H}_{4}(\ell),\) is an efficient oxygen scavenger. It is sometimes added to steam boilers to remove traces of oxygen that can cause corrosion in these systems. Combustion of hydrazine gives the following information: $$\begin{aligned}&\mathrm{N}_{2} \mathrm{H}_{4}(\ell)+\mathrm{O}_{2}(\mathrm{g}) \longrightarrow \mathrm{N}_{2}(\mathrm{g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\\\&\Delta H_{\mathrm{rxn}}^{\circ}=-534.3 \mathrm{kJ}\end{aligned}$$ (a) Is the reaction product- or reactant-favored? (b) Use the value for \(\Delta H_{\mathrm{rxn}}^{\circ}\) with the enthalpy of formation of \(\mathrm{H}_{2} \mathrm{O}(\mathrm{g})\) to calculate the molar enthalpy of formation of \(\mathrm{N}_{2} \mathrm{H}_{4}(\ell)\).

A 0.692 -g sample of glucose, \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6},\) is burned in a constant volume calorimeter. The temperature rises from \(21.70^{\circ} \mathrm{C}\) to \(25.22^{\circ} \mathrm{C} .\) The calorimeter contains \(575 \mathrm{g}\) of water and the bomb has a heat capacity of \(650 \mathrm{J} / \mathrm{K}\). What quantity of heat is evolved per mole of glucose?

You should use care when dissolving \(\mathrm{H}_{2} \mathrm{SO}_{4}\) in water because the process is highly exothermic. To measure the enthalpy change, \(5.2 \mathrm{g} \mathrm{H}_{2} \mathrm{SO}_{4}(\ell)\) was added (with stirring) to 135 g of water in a coffee-cup calorimeter. This resulted in an increase in temperature from \(20.2^{\circ} \mathrm{C}\) to \(28.8^{\circ} \mathrm{C}\) Calculate the enthalpy change for the process \(\mathrm{H}_{2} \mathrm{SO}_{4}(\ell) \longrightarrow \mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{aq}),\) in \(\mathrm{k} \mathrm{J} / \mathrm{mol}\).

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